a: =476-324-124-524

=-172-324

=-496

b:=-127+2013-1013-372

=1000-449=501

-496

\(\left(476-324\right)-\left(124+524\right)\)

\(=476-324-124-524\)

\(=-496\)

A= ( 476-324) - ( 124+524)

= 152 - 648

= -496

a ) 1 14 b ) 2 4 c ) 0. d ) − 7 129

b: =67-5759+5759=67

a =-400
b=67
c=8080

\(a,524-\left[\left(476+524\right)-76\right]\)

\(=524-1000+76\)

\(=600-1000\)

\(=-400\)

\(b,\left(67-5759\right)+5759\)

\(=67-5759+5759\)

\(=67\)

\(c,4.\left(2020+2019\right)+4.\left(-2019\right)\)

\(=4.\left(2020+2019-2019\right)\)

\(=4.2020\)

\(=8080\)

\(a,\left(1-\dfrac{1}{10}\right)\times\left(1-\dfrac{1}{11}\right)\times\left(1-\dfrac{1}{12}\right)\times\left(1-\dfrac{1}{13}\right)\times\left(1-\dfrac{1}{14}\right)\times\left(1-\dfrac{1}{15}\right)=\dfrac{9}{10}\times\dfrac{10}{11}\times\dfrac{11}{12}\times\dfrac{12}{13}\times\dfrac{13}{14}\times\dfrac{14}{15}=\dfrac{9}{15}=\dfrac{3}{5}\)

\(b,\dfrac{2013\times2012-2}{2011+2011\times2013}=\dfrac{\left(2014-1\right)\times2012-2}{2011\times\left(2013+1\right)}=\dfrac{2014\times2012-2012-2}{2011\times2014}=\dfrac{2014\times2012-2014}{2011\times2014}=\dfrac{2014\times\left(2012-1\right)}{2011\times2014}=\dfrac{2011\times2014}{2011\times2014}=1\)

3/5,1

#\(N\)

`a, -677*54+54.(-125)+2.54`

`=54.(-677+-125+2)`

`=54.(-800)`

`=-43200`

`b, -(324-267+252)+(133-76)`

`=-324+267-252+133-76`

`= (-324+-76)+(133+267)-252`

`=-400+400-252`

`=-252`

a: =54(-677-125+2)

=54*(-800)

=-43200

b: =-324+267-252+133-76

=-400+400-252

=-252

a. -677 . 54 + 54 . ( - 125 ) + 2. 54

= 54 . ( -677 + ( -125 ) + 2 )

= 54 . ( -802 + 2 )

= 54 . ( -800 )

= -43200

b.- (324 - 267 + 252) + (133 - 76)

= 324 - 267 + 252 + 133 -76

= 324 +76 - 267 + 133 -252

= 400 - 400 +252

= -252

a) -8; -9; -10; ...; 5; 6; 7

b)

1) 700

2) -1201

a) -7 < 0,1,2,3,4,5,6,7<8

b) 

1) 631  + [ 587 - (287+231)]                                

= 631 + [ 587 - 518 ] 

= 631 + 69

=700                                              

2)  (-524) – [(476 + 245) - 45]

= (-524) – 476 – 245 + 45

= (-524) + (– 476) + (– 245) + 45

= (-1000) + (-200)

= -1200.

= 631 + 69                                                   

= 700

a) Tìm các số nguyên x thỏa mãn: \(-7< x< 8.\)

\(x=\left\{-6;-5;-4;-3;-2;-1;0;1;2;3;4;5;6;7\right\}.\)

b)  Tính nhanh các tổng:

1)  \(631+\left[587-\left(287+231\right)\right]=631+587-287-231=\left(631-231\right)+\left(587-287\right)=400+300=700.\)

2)  \(\left(-524\right)-\left[\left(476+246\right)-45\right]=\left(-524-246\right)+\left(-476+45\right)=-1201.\)

2012 x 2013 - 1013 x 2013 + 2013

= 2012 x 2013 - 1013 x 2013 + 2013 x 1

= 2013 x ( 2012 - 1013 + 1 )

= 2013 x         1000

=       2013000

a) 2012x2013-1013x2013+2013

=2013(2012-1013+1)

=2013x1000

=2013000

\(2012x2013-1013x2013+2013\)

\(=2013x\left(2012-1013+1\right)\)

\(=2013x1000\)

\(=2013000\)

Nhớ ấn đúng cho mình nha!