= 5.3.3^11+4.(3^3)^4/(3^2)^7

= 5.3^12+4.3^12/3^14

= 3^12.(5+4)/3.3^12.3^2

= 3^12.9/3^12.9 = 1

k mk nha

\(\frac{15.3^{11}+4.27^4}{9^7}\)

\(=\frac{5.3.3^{11}+4.\left(3^3\right)^4}{\left(3^2\right)^7}\)

\(=\frac{5.3^{12}+4.3^{12}}{3^{14}}\)

\(=\frac{3^{12}.\left(5+4\right)}{3^{14}}\)

\(=\frac{3^{12}.9}{3^{14}}\)

\(=\frac{3^{12}.3^2}{3^{14}}\)

\(=\frac{3^{14}}{3^{14}}\)

\(=1\)

Chúc bạn học tốt !!! 

\(A=\frac{15.3^{11}+4.27^4}{9^7}\)

\(\Rightarrow\frac{3.5.3^{11}+4.3^{3.4}}{3^{2.7}}\)

\(\Rightarrow\frac{3^{12}.5+3^{12}.4}{3^{14}}\)

\(\Rightarrow\frac{3^{12}\left(5+4\right)}{3^{14}}\)

\(\Rightarrow\frac{9}{3^2}=\frac{9}{9}=1\)

Vậy ....

thanks ban

Chứng minh à ?        

\(A=\frac{15.3^{11}+4.27^4}{9^7}=\frac{3.5.3^{11}+4.3^{3.4}}{3^{2.7}}=\frac{3^{12}.5+3^{12}.4}{3^{14}}=\frac{3^{12}\left(5+4\right)}{3^{14}}=\frac{9}{3^2}=\frac{9}{9}=1\)

3,78 x ( 200 - 68 ) - 3,78 x ( 100 - 68 )

= 3,78 x 132 - 3, 78 x 32

= 3,78 x ( 132 - 32 )

= 3 , 78 x 100

= 378

15, 3 x 9,55 + 9,45 x 15 , 3 + 15 , 3

= 15,3 x ( 9.55 + 9.45 + 15.1 )

= 15,3 x 34.1

= 521.73

mk sợ câu thứ 2 chưa chắc đúng đâu nha câu nhờ ai giúp câu 2 nhé ^^

a, \(3,78.\left(200-68\right)-3,78.\left(100-68\right)\)

\(=3,78.132-3,78.32\)

\(=3,78.\left(132-32\right)\)

\(=3,78.100\)

\(=378\)

b, \(15,3.9,55+9,45.15,3+15,3\)

\(=15,3.\left(9,55+9,45+1\right)\)

\(=15,3.20\)

\(=306\)