a) \(\left(x-1\right)^2=49\)

\(\Rightarrow\left(x-1\right)^2=7^2=\left(-7\right)^2\)

\(\Rightarrow x-1=7\)                        hoặc                           \(x-1=-7\)

\(x=7+1=8\)                                                                \(x=-7+1=-6\)

Vậy x = 8 hoặc x = - 6

b) \(3\cdot\left(13-x\right)^2=27\)

\(\left(13-x\right)^2=27\div3=9\)

\(\Rightarrow\left(13-x\right)^2=3^2=\left(-3\right)^2\)

\(\Rightarrow13-x=3\)                                          hoặc                                    \(13-x=-3\)

\(x=13-3=10\)                                                                                            \(x=13+3=16\)

Vậy x = 10 hoặc x = 16

c) \(164-\left(15-x\right)^3=100\)

\(\left(15-x\right)^3=164-100=64\)

\(\Rightarrow\left(15-x\right)^3=4^3\)

\(\Rightarrow15-x=4\)

\(x=15-4=11\)

Vậy x = 11

d) \(\left(x+3\right)^3-15=210\)

\(\left(x+3\right)^3=210+15=225\)

\(\Rightarrow\left(x+3\right)^3=...\)

Tương tự mũ lẻ cậu nhé

e) \(x^2\div4=16\)

\(x^2=16\cdot4=64\)

\(\Rightarrow x^2=8^2=\left(-8\right)^2\)
Vậy x = 8 hoặc x = - 8

a/\(\left(x-1\right)^2\)=49

\(\left(x-1\right)^2\)=\(7^2\)

=>x-1=7

x=7+1

x=8

b/3.\(\left(13-x\right)^2\)=27

\(\left(13-x\right)^2\)=27:3

\(\left(13-x\right)^2\)=9

\(\left(13-x\right)^2\)=\(3^2\)

=>13-x=3

x=13-3

x=10

c/164-\(\left(15-x\right)^3\)=100

\(\left(15-x\right)^3\)=164-100

\(\left(15-x\right)^3\)=64

\(\left(15-x\right)^3\)=\(4^3\)

=>15-x=4

x=15-4

x=11

d/\(\left(x+3\right)^3\)-15=210

\(\left(x+3\right)^3\)=210+15

\(\left(x+3\right)^3\)=225

sai đề bài câu d hay sao ý bạn ạ 

chỉ có \(\left(x+3\right)^2\)thì mới tính được

e/\(x^2\):4=16

\(x^2\)=16.4

\(x^2\)=64

\(x^2\)=\(8^2\)

=>x=8

3⁶ . 4⁶ = (3.4)⁶ = 12⁶

8² . 2³ . 16² = (2³)² . 2³ . (2⁴)

= 2⁶ . 2³ . 2⁴ = 2^{6 + 3 + 4} = 2¹³

2³ . 2² . 8³ = 2³ . 2² . (2³)³

= 2³ . 2² . 2⁹ = 2^{3 + 2 + 9} = 2¹⁴

y. y⁷ = y^{1 + 7} = y⁸

\(3^6\cdot4^6=\left(3\cdot4\right)^6=12^6\)

\(8^2\cdot2^3\cdot16^2=\left(2^3\right)^2\cdot2^3\cdot\left(2^4\right)^2\)

\(=2^6\cdot2^3\cdot2^8=2^{17}\)

\(2^3\cdot2^2\cdot8^3=2^5\cdot\left(2^3\right)^3\)

\(2^5\cdot2^9=2^{14}\)

\(y\cdot y^7=y^{1+7}=y^8\)

3⁶ . 4⁶

= ( 3 . 4 )⁶

= 12⁶

8² . 2³ . 16²

= ( 2³ )² . 2³ . ( 2⁴ )²

= 2⁶ . 2³ . 2⁸

= 2⁶⁺³⁺⁸

= 2¹⁷

2³ . 2² . 8³

= 2³ . 2² . ( 2³ )³

= 2³ 2² . 2⁹

= 2³⁺²⁺⁹

= 2¹⁴

y . y⁷

= y¹ . y⁷

= y¹⁺⁷

= 7⁸

\(x^3-2^3=2^5-\left(3^{16}:3^{14}+2^8:2^6\right)\)

\(x^3-8=\)\(32-\left(3^2+2^2\right)\)

\(x^3-8=\)\(32-\left(9+4\right)\)

\(x^3-8=32-13\)

\(x^3-8=19\)

\(x^3\)     \(=19+8\)    

\(x^3\)     \(=27\)

=> \(x=3\)

Vậy \(x=3\)

a) \(2^3=8\) ; \(3^2=9\)

=> \(2^3< 3^2\)

b) \(3^{210}\cdot3^{10}=3^{210+10}=3^{220}>3^{215}\)

=> \(3^{215}< 3^{210}.3^{10}\)

a,\(2^3\)và \(3^2\)

\(2^3=8\)\(3^2=9\)

Vì \(8< 9\Rightarrow2^3< 3^2\)

Vậy....

b,\(3^{215}\)và \(3^{210}.3^{10}\)

\(3^{215}\)và \(3^{220}\)

\(3^{215}< 3^{220}\Rightarrow3^{215}< 3^{210}.3^{10}\)

Vậy...

a) 2³ = 8 ; 3² = 9

Vì 8 < 9 => 2³ < 3²

b) 3²¹⁰.3¹⁰ = 3²¹⁰⁺¹⁰ = 3²²⁰ > 3²¹⁵

=> 3²¹⁵ < 3²¹⁰.3¹⁰

Bằng 139968

139968

Bằng 139968

a: =5-78*32

=5-2496

=-2491

b: \(=6\left(9-6\right)=6\cdot3=18\)

c: \(=46\cdot\dfrac{\left(123-42\right)}{81}=46\)

d: \(=181+3-84+8\cdot25\)

=100+200

=300

e: \(=64\cdot35+140\cdot84-1=2240-1+11760\)

=14000-1

=13999

f: \(=3^3+25\cdot8-1=26+200=226\)

g: \(=3+2^4+1=16+4=20\)

h: \(=36:4\cdot3+2\cdot25-1=27+50-1=27+49=76\)

210 : [ 16 + 3 (6 + 3 . 2\(^2\)) - 3

= 210 :  70 -3

=  3  - 3

=0