5mu6 :5mu3+2mu2 .2mu3
19 mu7 : 19mu5+4.4mu2
2mu5. 7+3mu19 :3 mứ-2018
17.3mu2 -5mu15 :5mu13+39mu0
Những câu hỏi liên quan
A=(5+5mu2)+(5mu3+5mu4)+(5mu5+5mu6)+(5mu7+5mu8)
5mu13 : 5mu10 - 25*2mu2
513 : 510 - 25 * 22
= 513-10 - 25 * 4
= 53 - 100
= 125 - 100
= 25
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bai1
5mu3+3mu5
bai2
(x-1)mu3=125
720/(41-(2*x-5))=2mu 3*5
bai3
1 phan 9 * 3 mu 4 * 3 mu n =3 mu 7
(2 mu 2 chia 4)* 2 mu n = 4
bai4
2 * 2mu2 * 2mu3 * 2mu4 *.......*2 mu100
2mu17+15mu4).(3mu19-2mu17).(2mu4-4mu2)
(217+154).(319-217).(24-42)
=(217+154).(319-217).(16-16)
=(217+154).(319-217).0
=0
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4mu2:4.3mu3-2mu2+7
42:4.33-22+7
⇒ 4.27-4+7
⇒ 108-4+7
⇒ 111
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4\(^2\) : 4.3\(^3\) - 2\(^2\) + 7
= 16 : 4 . 27 - 4 + 7
= 4 . 27 - 4 + 7
= 108 - 4 + 7
= 104 + 7
= 111
-Tick cho mình nha mình cảm ơn ạ. <3
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\(S=\dfrac{2mu2}{1.2}+\dfrac{2mu2}{2.3}+\dfrac{2mu2}{3.4}+...+\dfrac{2mu2}{2022.2023}\)
(mu = mũ)
\(S=\dfrac{2^2}{1.2}+\dfrac{2^2}{2.3}+\dfrac{2^2}{3.4}+...+\dfrac{2^2}{2022.2023}\)
\(S=2^2.\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{2022.2023}\right)\)
\(S=2^2.\left(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2022}-\dfrac{1}{2023}\right)\)
\(S=2^2.\left(\dfrac{1}{1}-\dfrac{1}{2023}\right)\)
\(S=2^2.\dfrac{2022}{2023}\)
\(S=\dfrac{2^2.2022}{2023}=\dfrac{8088}{2023}\)
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hãy viết thành một bình phương
1mu3+2mu3+3mu3+4mu3+5mu3
1mu3+2mu3+3mu3+4mu3+5mu3+6mu3
20+2.(x+3)=5mu2.4
(2x-6)=2.5mu4:5mu3
20 + 2.(x + 3) = 52 . 4
20 + 2.(x + 3) = 25 . 4
20 + 2.(x + 3) = 100
2.(x + 3) = 100 - 20
2.(x + 3) = 80
x + 3 = 80 : 2
x + 3 = 40
x = 40 - 3
x = 36
(2x - 6) = 2.54 : 53
(2x - 6) = 2.625 : 125
(2x - 6) = 1250 : 125
(2x - 6) = 10
2x = 10 + 6
2x = 16
x = 16 : 2 = 8
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A=3mu2+3mu2+2mu2+2mu2+.........=1mu2+1mu2