\(\left(\frac{505}{707}+\frac{222}{333}\right)\cdot x=\frac{404}{909}\)

 =>     \(\left(\frac{5}{7}+\frac{2}{3}\right)\cdot x=\frac{4}{9}\)

=>                     \(\frac{29}{21}\cdot x=\frac{4}{9}\)

=>                               \(x=\frac{4}{9}:\frac{29}{21}\)

=>                              \(x=\frac{28}{87}\)

TK mk nha!

( 505/707+ 222/333) . x = 404/ 909

29/21 . x = 4/9

x= 4/9 : 29/21

x= 4/9 . 21/29

x= 28/87

Vậy x= 28/87

28/87

giúp mình nha 

-Vì (1/222)^333=(1/222)^3.111=(3/666)^111

     (1/333)^222=(1/333)^2.111=(2/666)^111

-Vì 111=111 và 3/666>2/666

=))(1/222)^333>(1/333)^222

Ta có:

222³³³ = 111³³³.2³³³ = 111²²².111¹¹¹.(2³)¹¹¹ = 111²²².111¹¹¹.8¹¹¹ = 111²²².888¹¹¹

333²²² = 111²²².3²²² = 111²²².(3²)¹¹¹ = 111²²².9¹¹¹

Vì 111²²².888¹¹¹ > 111²²².9¹¹¹

=> 222³³³ > 333²²²

=> \(\frac{1}{222^{333}}< \frac{1}{333^{222}}\)

hay \(\left(\frac{1}{222}\right)^{333}< \left(\frac{1}{333}\right)^{222}\)

\(\frac{2}{7}\)x  \(\left(\frac{707}{202}+\frac{707}{3030}+\frac{707}{4242}+\frac{707}{5656}+\frac{707}{7272}\right)\)

\(=\frac{2}{7}\)x   \(\left(\frac{7}{2}+\frac{7}{30}+\frac{1}{6}+\frac{1}{8}+\frac{7}{72}\right)\)

\(=\frac{2}{7}\)x    \(\left(\frac{1260}{360}+\frac{84}{360}+\frac{60}{360}+\frac{45}{360}+\frac{35}{360}\right)\)

\(=\frac{2}{7}\)x   \(\frac{371}{90}=\frac{53}{45}\)

\(\frac{x-1}{27}=\frac{-3}{1-x}\)

\(\Rightarrow\frac{x-1}{27}=\frac{3}{x-1}\)

\(\Rightarrow\left(x-1\right)^2=81\)

\(\Rightarrow x-1=\pm9\)

Làm nốt nhassssso

\(\frac{292929-404}{4.797979+909}\)=\(\frac{292525}{4798888}\)=\(\frac{11701}{599861}\)