\(5\dfrac{3}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-\dfrac{1}{8}=\left(5\dfrac{3}{4}+2\dfrac{1}{4}\right)\times\dfrac{1}{3}-\dfrac{1}{8}\\ =8\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{8}{3}-\dfrac{1}{8}=\dfrac{61}{24}\\ ----\\ \dfrac{3}{5}:\dfrac{5}{6}:\dfrac{6}{7}:\dfrac{7}{8}+\dfrac{2}{5}+\dfrac{23}{35}\\ =\dfrac{3}{5}\times\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{18}{25}\times\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{353}{175}\)

Bài 1:

a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)

b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)

c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)

d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)

hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)

e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)

hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)

dad

\(\frac{1}{3}+\frac{3}{7}+\frac{5}{3}+\frac{8}{14}\)

\(=\left(\frac{1}{3}+\frac{5}{3}\right)+\left(\frac{3}{7}+\frac{8}{14}\right)\)

\(=\frac{6}{3}+\left(\frac{6}{14}+\frac{8}{14}\right)\)

\(=2+\frac{14}{14}\)

\(=2+1\)

\(=3\)

\(\frac{5}{6}+\frac{4}{15}+\frac{6}{18}+\frac{3}{45}\)

\(=\left(\frac{5}{6}+\frac{6}{18}\right)+\left(\frac{4}{15}+\frac{3}{45}\right)\)

\(=\left(\frac{5}{6}+\frac{2}{6}\right)+\left(\frac{4}{15}+\frac{1}{15}\right)\)

\(=\frac{7}{6}+\frac{5}{15}\)

\(=\frac{7}{6}+\frac{1}{3}\)

\(=\frac{7}{6}+\frac{2}{6}\)

\(=\frac{9}{6}\)

\(=\frac{3}{2}\)

~ Ủng hộ nhé 

\(9\times17+83\times9\)

\(=\left(83+17\right)\times9\)

\(=100\times9\)

\(=900\)

\(4\frac{1}{7}+7+8\frac{6}{7}\)

\(=\left(4\frac{1}{7}+8\frac{6}{7}\right)+7\)

\(=\left(8+4\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+7\)

\(=12+\frac{7}{7}+7\)

\(=12+1+7\)

\(=20\)

~ Ủng hộ nhé 

a) \(\frac{1}{3}+\frac{3}{7}+\frac{5}{3}+\frac{8}{14}\)

\(=\frac{1}{3}+\frac{6}{14}+\frac{5}{3}+\frac{8}{14}\)

\(=\left(\frac{1}{3}+\frac{5}{3}\right)+\left(\frac{6}{14}+\frac{8}{14}\right)\)

\(=2+1\)

\(=3\)

b) \(\frac{5}{6}+\frac{4}{15}+\frac{6}{18}+\frac{3}{45}\)

\(=\frac{5}{6}+\frac{4}{15}+\frac{2}{6}+\frac{1}{15}\)

\(=\left(\frac{5}{6}+\frac{2}{6}\right)+\left(\frac{4}{15}+\frac{1}{15}\right)\)

\(=\frac{7}{6}+\frac{1}{3}\)

\(=\frac{3}{2}\)

c) \(9\times17+83\times9\)

\(=9\times\left(17+83\right)\)

\(=9\times100\)

\(=900\)

d) \(4\frac{1}{7}+7+8\frac{6}{7}\)

\(=\left(4\frac{1}{7}+8\frac{6}{7}\right)+7\)

\(=\left(4+8\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+7\)

\(=12+1+7\)

\(=13+7\)

\(=20\)

_Chúc bạn học tốt_

1) \(\left(+15\right)+\left(+17\right)=15+17=32\)

2) \(\left(-3\right)+\left(-7\right)=-3-7=-\left(3+7\right)=-10\)

3) \(\left(-25\right)+\left(+4\right)=-25+4=-\left(25-4\right)=-21\)

4) \(\left(-6\right)+\left(-54\right)=-6-54=-\left(6+54\right)=-60\)

5) \(\left(-15\right)+20=20-15=5\)

6) \(\left(-5\right)+8+7+5\)

\(=\left(-5+5\right)+\left(8+7\right)\)

\(=15\)

7) \(\left(-8\right)+\left(-11\right)+\left(-2\right)\)

\(=\left[\left(-8\right)+\left(-2\right)\right]+\left(-11\right)\)

\(=\left(-10\right)+\left(-11\right)\)

\(=-21\)

8) \(15+\left(-5\right)+\left(-14\right)+\left(-16\right)\)

\(=\left[15+\left(-5\right)\right]+\left[\left(-14\right)+\left(-16\right)\right]\)

\(=10+\left(-30\right)\)

\(=-20\)

9) \(\left(-20\right)+\left(-14\right)+3+\left(-86\right)\)

\(=\left[\left(-20\right)+3\right]+\left[\left(-14\right)+\left(-86\right)\right]\)

\(=\left(-17\right)+\left(-100\right)\)

\(=-117\)

10) \(\left(-136\right)+123+\left(-264\right)+\left(-83\right)+240\)

\(=\left[\left(-136\right)+\left(-264\right)\right]+\left[123+\left(-83\right)\right]+240\)

\(=\left(-400\right)+40+240\)

\(=\left(-360\right)+240\)

\(=-120\)

11) \(\left(-596\right)+2001+1999+\left(-404+189\right)\)

\(=\left(-596\right)+2001+1999-404+189\)

\(=\left[\left(-596\right)-404\right]+\left(2001+189\right)+1999\)

\(=\left(-1000\right)+2190+1999\)

\(=1190+1999\)

\(=3189\)

12) \(314+\left(-153\right)+64+121+\left(-247\right)+218\)

\(=\left(314+64+121\right)+\left[\left(-153\right)+\left(-247\right)\right]+218\)

\(=\left(378+121\right)+\left(-400\right)+218\)

\(=499-400+218\)

\(=99+218\)

\(=317\)

\(\text{#}Toru\)

1: =7/2+23/5=35/10+46/10=81/10

2: =6/8+53/8=59/8

3: =43/8+65/7=821/56

\(a,3\dfrac{1}{2}+4\dfrac{3}{5}=\dfrac{81}{10}\\ b,\dfrac{3}{4}+6\dfrac{5}{8}=\dfrac{59}{8}\\ 5\dfrac{3}{8}+9\dfrac{2}{7}=\dfrac{821}{56}\\ 4,4\dfrac{1}{2}-2\dfrac{3}{10}=\dfrac{11}{5}\)

14x6=

a,34.(73-83)-83.(17-34)-73.17

  =34.73-34.83-83.17+83.34-73.17

  =34.73-83.17-73.17

  =17.(2.73-83-73)=17.(-10)=-170

b) 1 - 2 - 3 + 4 - 5 - 6 + 7 - 8 -9 + ........+ 28 - 29 -30

= (1 - 2 - 3) + (4 - 5 - 6) + (7 - 8 - 9) + .....+ (28 - 29 - 30)

= (-4) + (-7) + (-10) +......+(-31)

Ta có số số hạng là:

[(-31) - (-4)] : (-3) + 1= 10

⇒ Tổng của các số số hạng trên là:

[(-31) + (-4)] . 10 : 2 = -175

Vậy...........

Chúc bn học tốt nếu mình làm đúng phần này thì nha, phần a chưa nghĩ ra

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