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Chứng minh răng :
1/1945^2+1/1946^2+1/1947^2+.....+1/1974^2+1/1975^2<1/1944
Những câu hỏi liên quan
1/1945*1945+1/1946*1946+1/1947*1947+...+1/1974+*1974+1/1975*1975<1/1944
Chứng tỏ rằng
\(\frac{1}{1945^2}\)\(+\frac{1}{1946^2}+\frac{1}{1947^2}+...+\frac{1}{1974^2}+\frac{1}{1975^2}\)<1/1944
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Chứng tỏ rằng:
1/1945² + 1/1946² + 1/1947² + .......+1/1974² + 1/1975² < 1/1944
M= 1/1975*(2+1/1945-1)-1/1945*(1-2/1975)-1974/1975*1946/1945-3/1975*1945
chung minh
1/1945^2+1/1946^2+1/1947^2+...+1/1975<1/1944
1/19452 < 1/ 1944.1945
1/19462 < 1/ 1945.1946
....
1/19752 < 1/ 1974.1975
=> 1/119452 +1/119462+....+1/119752 < 1/ 1944.1945+1/ 1945.1946+..+1/ 1974.1975=1/1944-1/1945+1/1945-1/1946+....+1/1974-1/1975
=1/19444-1/1975<1/1944
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Chứng tỏ rằng:
1/1945^2+1/1946^2+...+1/1947^2+1/1975^2<1/1944
Có : 1/1945^2 + 1/1946^2 + ...... + 1/1975^2
< 1/1944.1945 + 1/1945.1946 + ...... + 1/1974.1975
= 1/1944 - 1/1945 +1/1945 - 1/1946 + ...... + 1/1974 - 1/1975
= 1/1944 - 1/1975
< 1/1944
Tk mk nha
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Chứng tỏ : 1/1945^2+1/1946^3+1/1947^2+...+1/1975^2<1/1944
\(\dfrac{1}{1945^2}< \dfrac{1}{1944^2}\\ \dfrac{1}{1946^2}< \dfrac{1}{1944^2}\\ \dfrac{1}{1947^2}< \dfrac{1}{1944^2}\\ ...\\ \dfrac{1}{1975^2}< \dfrac{1}{1944^2}\\ \Leftrightarrow\dfrac{1}{1945^2}+\dfrac{1}{1946^2}+\dfrac{1}{1947^2}+...+\dfrac{1}{1975^2}< \dfrac{1}{1944^2}+\dfrac{1}{1944^2}+\dfrac{1}{1944^2}+...+\dfrac{1}{1944^2}\left(31\text{ số }\dfrac{1}{1944^2}\right)=31\cdot\dfrac{1}{1944^2}< 1944\cdot\dfrac{1}{1944^2}=\dfrac{1}{1944}\)
Vậy \(\dfrac{1}{1945^2}+\dfrac{1}{1946^2}+\dfrac{1}{1947^2}+...+\dfrac{1}{1975^2}< \dfrac{1}{1944}\)
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\(M=\frac{1}{1975}.\left(\frac{2}{1975}-1\right)-\frac{1}{1945}.\left(1-\frac{2}{1975}\right)-\frac{1974}{1975}.\frac{1946}{1945}-\frac{3}{1975.1945}\)
nho khô nha
5 tháng 9 2018 lúc 21:13
Tính M=\(\dfrac{1}{1975}\left(\dfrac{2}{1945}-1\right)-\dfrac{1}{1945}\left(1-\dfrac{2}{1975}\right)+\dfrac{1974}{1975}\times\dfrac{1946}{1945}-\dfrac{3}{1975\times1945}\)
Ta có : P = \(\dfrac{1}{1975}\left(\dfrac{2}{1945}-1\right)-\dfrac{1}{1945}\left(1-\dfrac{2}{1975}\right)+\dfrac{1974}{1975}.\dfrac{1946}{1945}\)
\(-\dfrac{3}{1975.1945}\)
= \(\dfrac{2}{1975.1945}-\dfrac{1}{1975}-\dfrac{1}{1945}+\dfrac{2}{1975.1945}+\dfrac{1974}{1975}.\dfrac{1946}{1945}\)
\(-\dfrac{3}{1975.1945}\)
= \(\dfrac{2+2+1974.1946-3-1975-1945}{1975.1945}\)
= \(\dfrac{2+2+1974.1946-3-1975-1945}{1975.1945}\)
= \(\dfrac{1973}{1975}\)
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