Tính tổng B=50+50/3+25/3+20/4+10/3+100/6.7+...+100/98.99+1/99
Tìm tổng S biết:
S=50 +50/3=25/3+20/4+10/3+100/6.7+....+100/98.99+1/99.
Tính tổng :
\(B=50+\frac{50}{3}+\frac{25}{3}+\frac{20}{4}+\frac{10}{3}+\frac{100}{6.7}+...+\frac{100}{98.99}+\frac{1}{99}\)
\(B=50+\frac{50}{3}+\frac{25}{3}+\frac{20}{4}+\frac{10}{3}+\frac{100}{6.7}+...+\frac{100}{98.99}+\frac{1}{99}\)
\(B=\frac{100}{1.2}+\frac{100}{2.3}+\frac{100}{3.4}+\frac{100}{4.5}+\frac{100}{5.6}+\frac{100}{6.7}+...+\frac{100}{98.99}+\frac{100}{99.100}\)
\(B=100\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{98.99}+\frac{1}{99.100}\right)\)
\(B=100\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\right)\)
\(B=100\left(1-\frac{1}{100}\right)\)
\(B=100.\frac{99}{100}=99\)
Tìm S biết S=50+50/3+25/3+20/4+10/3+100/6.7+....+100/98.99+1/99
Tui còn chả hiểu nổi cái quy luật của nó như thế nào nữa.
quy luật là gì. mik xem mà ngất luôn
Tính
\(B=50+\frac{50}{3}+\frac{25}{3}+\frac{20}{4}+\frac{10}{3}+\frac{100}{6.7}+...+\frac{100}{98.99}+\frac{1}{99}\)
tính nhanh 50+50/3+25/3+20/4+10/3+100/6.7+...+100/98.99
tính A=50+50/3+25/3+10/4+10/3+100/6.7+100/7.8+...+100/98.99+1/99
\(A=\dfrac{100}{1\cdot2}+\dfrac{100}{2\cdot3}+\dfrac{100}{3\cdot4}+...+\dfrac{100}{99\cdot100}\)
\(A=100\cdot\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{99\cdot100}\right)\)
\(A=100\cdot\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{99}-\dfrac{1}{100}\right)\)
\(A=100\cdot\left(1-\dfrac{1}{100}\right)\)
\(A=100\cdot\dfrac{99}{100}\)
A=99
Tìm X:
\(\frac{50+\frac{50}{3}+\frac{25}{3}+\frac{20}{4}+\frac{10}{3}+\frac{100}{6.7}+...+\frac{100}{98.99}+\frac{1}{99}}{\left(2x-1\right)}\)=11
Giúp mình với, mình đang rất gấp
1. -2010.2009+109/2008.2010+1990
2. 50+50/3+25/3+20/4+10/3+100/6.7+...+100/98.99+1/99
3. (x+2)4+(2y-4)2 <4
Tính tổng:
\(50+\frac{50}{3}+\frac{25}{3}+\frac{30}{4}+\frac{10}{3}+\frac{100}{6.7}+...+198
.
99\)