12+3...=9+10-2
a) 3^10 . (-5)^21 / (-5)^20 . 3^12
b) -11^5 . 13^7 / 11^5 . 13^8
c) 2^10 . 3^10 - 2^10 . 3^9 / 2^9 . 3^10
d) 5^11. 7^12 + 5^11 . 7^11/5^12 . 7^12 + 9 . 5^11 . 7^11
giúp em với ạ!! Đề bài là rút gọn ạ
Tính:
a) -5/7(14/5 - 7/10) : |-2/3| - 3/4(8/9 + 16/3) + 10/3(1/3 + 1/5)
b) 17/-26(1/6 - 5/3) : 17/13 - 20/3(2/5 - 1/4) + 2/3(6/5 - 9/2)
c) -8/9(9/8 - 3/2) + 5/4 : (5/2 - 15/4) - 3/4(10/9 - 8/3) : (-1/3)
d) 21/10 : (12/5 - 9/10) . (-4/7) - 3/2(1/6 - 7/12) + 1/5(3/2 - 1/4)
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
Bài 13: Dấu <, =, >
10 … 10 + 3
11 + 2…. 2 + 11
9 … 10 + 9
10 … 10 + 0
17 – 4 … 14 - 3
18 – 4 … 12
15 … 15 – 1
17 + 1… 17 + 2
12+ 5 … 16
16 … 19 - 3
15 – 4 … 10 + 1
19 – 3 … 11
10 < 10 + 3
11 + 2=2 + 11
9 < 10 + 9
10 = 10 + 0
17 – 4 > 14 - 3
18 – 4 >12
15 > 15 – 1
17 + 1<17 + 2
12+ 5 > 16
16 =19 - 3
15 – 4 =10 + 1
19 – 3 >11
Bài 1: Tính:
A= ((2^12 . 3^5 - 4^6 . 9^3 ) / 9( 2^2 . 3 )^6 + (8^4 . 3^5))) - ((5^10 . 7^3 - 25^2 . 49^2) / (( 125 . 7 )^3 + 5^9 . 14^3))
B= (2^9 . 27^3 + 15 . 4^9 . 9^4) / (6^9 . 2^0 + 12^10)
Tính nhanh:
a/ (1*5*6+2*10*12+4*20*24+9*45*54)/(1*3*5+2*6*10+4*12*20+9*27*45)
b/ [(1*5*6)+(2*10*12)+(4*20*24)+(9*45*54)]/[(1*3*5)+(2*6*10)+(4*12*20)+(9*27*45)]
/ là phân số nha!!!!!!!!!!!!!
Bài 1: Tính:
A= ((2^12 . 3^5 - 4^6 . 9^3 ) / 9( 2^2 . 3 )^6 + (8^4 . 3^5))) - ((5^10 . 7^3 - 25^2 . 49^2) / (( 125 . 7 )^3 + 5^9 . 14^3))
B= (2^9 . 27^3 + 15 . 4^9 . 9^4) / (6^9 . 2^0 + 12^10)
đúng ghi Đ sai ghi S
a,5/9+2/3=7/12 b,5/9+2/3=7/27
c, 5/9+2/3=11/9 d, 5/9+2/3=10/12
Tính giá trị biểu thức :
P = (10×10^2×10^3 ... 10^9)÷ (10^5× 10^10× 10^25)
Q= (2^9×3+2^9×5)÷ 2^12
1500×{5^3× 2^3 - 11×[7^2-5×2^3+8×(11^2-12^1]}
3^2×10^3-[13^2-5^2×4+2^2×15]×10^3
Mấy bạn ơi giúp mk vs mk đang cần gấp nạn nào biết làm thì giúp mk nha
Q=(2^9.3+2^9.5):2^12
Đặt A=2^9.3+2^9.5
A=2^9.(3+5)
A=2^9.8
Mặt khác:8=2^3
=>A=2^9.2^3
A=2^12
Theo đề bài ta có Q=(2^9.3+2^9.5):2^12
=>Q=2^12:2^12
Q=1
Nhìn dài dòng thế thôi chứ đơn giản lắm.Nếu thấy đúng thì cho mình nhé!
(2^19 . 27^3 + 15 . 4^9 . 9^4) / (6^9 . 2^10 + 12^10) = ?
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^9}{2^9.3^9.2^{10}+\left(3.2^2\right)^{10}}\)
\(=\frac{2^{19}.3^9+5.2^{18}.3^{19}}{2^{19}.3^9+3^{10}.2^{20}}=\frac{2^{18}.3^9\left(2+5.3\right)}{2^{18}.3^9\left(2+3.2^2\right)}=\frac{17}{14}\)
(6^9*2^10+12^10):(2^19*27^3+15*4^9*9^4)