Tìm x
3.(x-2)-6.(x-5)=2.(5-x)
tìm x
(x+7\4) x3\2=6
x:5\3+2\5=9\5
1\2:3+x=5\3
Một bể cá dạng hình hộp chữ nhật làm bằng kính ( không nắp ) có chiều dài 90cm chiều dài 60cm chiều cao 45cm Mực nước ban đầu trong bể là 35cm
a) Tính diện tích kính dùng để làm bể cá đó
b) Người ta cho vào bể cá một hòn đá Lúc này mực nước đo được là 40cm
Tính thể tích của hòn đá
Giúp mình nhé
Tìm x, biết:
a) 2(5x-8)-3(4x-5) = 4(3x-4) + 11;
b) 2 x ( 6 x - 2 x 2 ) + 3 x 2 ( x - 4 ) = 8;
c) 2 ( x 3 - 1 ) - 2 x 2 ( x + 2 x 4 ) + ( 4 x 5 + 4 ) x = 6;
d)(2x)2(4x-2)-(x3 -8x2) = 15.
a) x = 2 7 b) x = 2.
c) x = 2 d) x = 1.
Tìm x
3 - ( \(\dfrac{1}{6}\)- x ) . \(\dfrac{2}{5}\)=\(\dfrac{1}{2}\)
\(3-\left(\dfrac{1}{6}-x\right).\dfrac{2}{5}=\dfrac{1}{2}\\ \Rightarrow\left(\dfrac{1}{6}-x\right).\dfrac{2}{5}=3-\dfrac{1}{2}\\ \Rightarrow\left(\dfrac{1}{6}-x\right).\dfrac{2}{5}=\dfrac{5}{2}\\ \Rightarrow\dfrac{1}{6}-x=\dfrac{5}{2}:\dfrac{2}{5}\\ \Rightarrow\dfrac{1}{6}-x=\dfrac{25}{4}\\ \Rightarrow x=\dfrac{1}{6}-\dfrac{25}{4}\\ \Rightarrow x=-\dfrac{73}{12}\)
Tìm x biết:
a) (x+5).(2x+1)=0
b) x.(x+2)-3.(x+2)=0
c) 2x.(x-5)-x.(3+2x)=26
d) x2-10x-8x+16=0
e) x2-10x=25
f) 5x.(x-1)=x-1
g) 2.(x+5)-x2-5x=0
h) x2+5x-6=0
i) (2x-3)2-4.(x+1).(x-1)=49
j) x3+x2+x+1=0
k) x3-x2=4x2-8x+4
Mn ơi giúp em vs ạ,em cảm ơn trc ạ
\(a,\Leftrightarrow\left[{}\begin{matrix}x+5=0\\2x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=-\dfrac{1}{2}\end{matrix}\right.\\ b,\Leftrightarrow\left(x+2\right)\left(x-3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=3\end{matrix}\right.\\ c,\Leftrightarrow2x^2-10x-3x-2x^2=26\\ \Leftrightarrow-13x=26\Leftrightarrow x=-2\\ d,\Leftrightarrow x^2-18x+16=0\\ \Leftrightarrow\left(x^2-18x+81\right)-65=0\\ \Leftrightarrow\left(x-9\right)^2-65=0\\ \Leftrightarrow\left(x-9+\sqrt{65}\right)\left(x-9-\sqrt{65}\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=9-\sqrt{65}\\9+\sqrt{65}\end{matrix}\right.\)
\(e,\Leftrightarrow x^2-10x-25=0\\ \Leftrightarrow\left(x-5\right)^2-50=0\\ \Leftrightarrow\left(x-5-5\sqrt{2}\right)\left(x-5+5\sqrt{2}\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=5+5\sqrt{2}\\x=5-5\sqrt{2}\end{matrix}\right.\\ f,\Leftrightarrow5x\left(x-1\right)-\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(5x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{5}\end{matrix}\right.\\ g,\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\\ \Leftrightarrow\left(2-x\right)\left(x+5\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-5\end{matrix}\right.\\ h,\Leftrightarrow x^2+2x+3x+6=0\\ \Leftrightarrow\left(x+3\right)\left(x+2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\end{matrix}\right.\\ i,\Leftrightarrow4x^2-12x+9-4x^2+4=49\\ \Leftrightarrow-12x=36\Leftrightarrow x=-3\)
\(j,\Leftrightarrow x^2\left(x+1\right)+\left(x+1\right)=0\Leftrightarrow\left(x^2+1\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x^2=-1\left(vô.lí\right)\\x=-1\end{matrix}\right.\Leftrightarrow x=-1\\ k,\Leftrightarrow x^2\left(x-1\right)=4\left(x-1\right)^2\\ \Leftrightarrow x^2\left(x-1\right)-4\left(x-1\right)^2=0\\ \Leftrightarrow\left(x-1\right)\left(x^2-4x+4\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x-2\right)^2=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)
Bài 5:
1) a) Cho hai đa thức:
P (x) = 5x2 + 3x3 - 5x2 + 2x3 – 2 +4x – 4x2 + x3
Q(x) = 6x – x3 + 5 – 4x3 + 6 – 3x2 – 7x2
Tính M(x) = P(x) + Q(x)
b) Tìm C(x) biết: (5x2 + 9x – 3x4 + 7x3 -12) + C(x) = -2x3 + 9 – 6x + 7x4 -2x3
2) Tìm nghiệm của các đa thức sau
a) 4x - b) x2 – 4x +3
a: P(x)=6x^3-4x^2+4x-2
Q(x)=-5x^3-10x^2+6x+11
M(x)=x^3-14x^2+10x+9
b: \(C\left(x\right)=7x^4-4x^3-6x+9+3x^4-7x^3-5x^2-9x+12\)
=10x^4-11x^3-5x^2-15x+21
1/4 x 2/6 x3/8 x 4/10 x 5/12 x....x 30/62 x 31/64=2n. Tìm n
<=> \(\frac{1.2.3....31}{4.6.8....64}=2^n\Rightarrow\frac{1.2.3....30.31}{2\left(2.3.4.5...31\right).32}=2^n\Leftrightarrow\frac{1}{2.32}=2^n\Leftrightarrow\frac{1}{2^6}=2^n\)
=> 2^6.2^n = 1
=> 2^ (n + 6 ) = 2^0
=> n+ 6 = 0
=> n = - 6
\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}....\frac{31}{64}=\frac{1.2.3....31}{4.6.8....64}=\frac{1.2.3....31}{2.3.2.4....2.32}=\frac{1.2.3....31}{2^{30}.\left(3.4....32\right)}=\frac{2}{2^{30}.32}=\frac{1}{2^{34}}=2^{-34}=2^n=>n=-34\)
2^n × 2³¹ = \(\dfrac{ }{ }\)2/4×4/6×6/8×...×62/64
2^n×2³¹=1/32=2^-5
2^n=2^-5 ÷ 2³¹=2^-36
=>n=-36
Tìm x, biết:
a) 8 x 3 - 50x = 0;
b) 2(x + 3)- x 2 - 3x = 0;
c) 6 x 2 - 15x - (2x - 5)(2x + 5) = 0.
2 x 1 x 2 x3 x3 x4 x 4 x 5 x 5 x 6 x9 x8 x 1
2 x 1 x 2 x 3 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1 =
= 2 x 2 x 3 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 4 x 3 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 12 x 3 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 36 x 4 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 144 x 4 x 5 x 5 x 6 x 9 x 8 x 1
= 576 x 5 x 5 x 6 x 9 x 8 x 1
= 2 880 x 5 x 6 x 9 x 8 x 1
= 14 400 x 6 x 9 x 8 x 1
= 86 400 x 9 x 8 x 1
= 777 600 x 8 x 1
= 6 220 800 x 1
= 6 220 800
:)
2 x 1 x 2 x3 x3 x4 x4 x5 x5 x6 x9 x8 x 1
= 6 220 800
Tìm x, biết :
a) (x-2)3 +6(x+1)2-x3+12=0
b) (x-5) (x+5) - (x+3)2+3(x-2)2=(x+1)2- (x+4)(x-4)+3x2
c) (2x+3)2 +(x-1)(x+1)=5(x+2)2-(x-5)(x+1)+(x+4)
d) (1-3x)2-(x-2)(9x+1)=(3x-4)(3x+4)-9(x+3)2
Giúp mk với ạ, mk cảm ơn !
a) (x-2)3+6(x+1)2-x3+12=0
\(\Rightarrow\)x3-6x2+12x-8+6(x2+2x+1)-x3+12=0
\(\Rightarrow\)x3-6x2+12x-8+6x2+12x+6-x3+12=0
\(\Rightarrow\)24x+10=0
\(\Rightarrow\)24x=-10
\(\Rightarrow\)x=\(\dfrac{-10}{24}=\dfrac{-5}{12}\)
b)(x-5)(x+5)-(x+3)2+3(x-2)2=(x+1)2-(x-4)(x+4)+3x2
\(\Rightarrow\)x2-25-(x2+6x+9)+3(x2-4x+4)=x2+2x+1-(x2-16)+3x2
\(\Rightarrow\)x2-25-x2-6x-9+3x2-12x+12=x2+2x+1-x2+16+3x2
\(\Rightarrow\)3x2-18x-22=3x2+2x+17
\(\Rightarrow\)3x2-18x-22-3x2-2x-17=0
\(\Rightarrow\)-20x-39=0
\(\Rightarrow\)-20x=39
\(\Rightarrow\)x=\(-\dfrac{39}{20}\)
c) (2x+3)2 +(x-1)(x+1)=5(x+2)2-(x-5)(x+1)+(x+4)
⇒4x2+12x+9+x2-1=5(x2+4x+4)-(x2+x-5x-5)+x+4
⇒5x2+12x+8=5x2+20x+20-x2-x+5x+5+x+4
⇒5x2+12x+8-5x2-20x-20+x2+x-5x-5-x-4=0
⇒x2-13x-21=0
-3 x 1 x 6 x 2 x 5 x 12 x 13 x16 x 16 - 15 x 20
-1 x 2 x3 x 4 x3 x-3 x6 - 4 x 8 - 5 x 100