a) ab+ac= a(b+c)

b) ab-ac+ad= a(b-c+d)

c) ax-bx-cx+dx= x(a-b-c+d)

a.(b+c)

a.(b-c+d)

x.(a-b-c+d)

Mk chắc chắn 100% luôn, k mk nha

\(ab+ac=a\left(b+c\right)\)

\(ab-ac+ad=a\left(b+c+d\right)\)

\(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

k mk nha bn

thank you

ab + ac = a(b + c)

ab - ac + ad = a(b - c + d)

ax - bx - cx + dx

=x(a - b - c + d)

chuẩn men

ab+ac=a(b+c)

ab-ac+ad=a(b-c+d)

ax-bx-cx+dx=x(a-b-c+d)

1,  ab+ac= a(b+c)

2,  ab-ac+ad = a(b-c+d)

3,  ax-bx-cx+dx = x(a-b-c+d)

1, ab + ac = a(b+c)

2, ab - ac + ad = a(b-c+d)

3, ax-bx-cx+dx = x(a-b-c+d)

4, a(b+c) - d(b+c) = (a-d)(b+c)

5, ac-ad+bc-bd = a(c-d) + b(c-d) = (a+b)(c-d)

6, ax+by+bx+ay=ax+ay+bx+by=a(x+y)+b(x+y)=(a+b)(x+y)

a(b+c)
a(b-c+d)
x(a-b-c+d)
(b+c)(a-d)
a(c-d)+c(c-d)=(c-d)(a+c)
a(x+y)+b(x+y)=(x+y)(a+b)
T

Ta có: a(b-c+d)

=a(b-c+d)

chúc bn hok tốt 

forever

\(ab-ac+ad=a\left(b-c+d\right)\)

a, \(ab+ac=a\left(b+c\right)\)

b, \(ab-ac+ad=a\left(b-c+d\right)\)

c, \(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

a, ab + ac = a(b + c)

b,ab - ac + ad = a(b - c + d)

c,ax - bx - cx + dx = x(a - b) - x(c + d) = x (x - b - c - d)

Bài 2:

a) ab + ac = a(b + c)

Bài 1:

a) x(2 + x)(7 - x) = 0

=> x = 0 hoặc x + 2 = 0 hoặc 7 - x = 0

+) x = 0

+) x + 2 = 0 => x = -2

+) 7 - x = 0 => x = 7

Vậy x \(\in\){0;-2;7}

B1

a,không biết

b,không biết

B2,

a/ab+ac=[2xa]bc

b,ab-ac+ad=abcd

c/ ax-bx-cx+dx=0xABCD
 

ĐẶT NHÂN TỬ CHUNG NHA!

1) ab - ac + ad = a( b- c +d ) 

2) ax - bx - cx + dx = x( a-b-c+d)

3) a.( b + c ) - d . ( b + c )= (b+c)(a-d)

4) ac - ad + bc - bd = a( c-d)  + b( c-d) = (a+b)(c-d)

5) ax + by + bx + ay= a( x+y) + b( x+y) = (a+b)(x+y)