110 , 132

110

132

55 x 2 = 110                                       66 x 2 = 132

\(0,36\times740-\dfrac{72}{20}\times4+36\times3\)

\(=0,36\times740-0,36\times10\times4-0,36\times100\times3\)

\(=0,36\times740-0,36\times40+0,36\times300\)

\(=0,36\times\left(740-40+300\right)\)

\(=0,36\times1000\)

\(=360\)

   0,36 x 740 - \(\dfrac{72}{20}\) x 4 + 36 x 3

= 3,6 x 74 - 3,6 x 4 + 3,6 x 30

= 3,6 x ( 74 - 4 + 30)

= 3,6 x 100

= 360

0,36 x 740 -72/20 x 4 +36 x 3

=0.36 x 740 - 0.36 x 10 x 4 -0.36 x 100 x 3

=0.36 x 740 - 0.36 x 40 + 0.36 x300

=0.36 x ( 740 - 40 +300 )

=0.36 x 1000

= 360

CHÚC BẠN HỌC TỐT :))))

\(9x^4+36x^3+29x^2-14x\)

\(=x\left(9x^3+36x^2+29x-14\right)\)

\(=x\left(9x^3+18x^2+18x^2+36x-7x-14\right)\)

\(=x\left[9x^2\left(x+2\right)+18x\left(x+2\right)-7\left(x+2\right)\right]\)

\(=x\left(x+2\right)\left(9x^2+18x-7\right)\)

\(=x\left(x+2\right)\left(9x^2-3x+21x-7\right)\)

\(=x\left(x+2\right)\left[3x\left(3x-1\right)+7\left(3x-1\right)\right]\)

\(=x\left(x+2\right)\left(3x+7\right)\left(3x-1\right)\)

a) Ta có: \(36x^3-4x=0\)

\(\Leftrightarrow4x\left(9x^2-1\right)=0\)

\(\Leftrightarrow x\left(3x-1\right)\left(3x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\\x=\dfrac{-1}{3}\end{matrix}\right.\)

b) Ta có: \(3x\left(x-2\right)+x-2=0\)

\(\Leftrightarrow\left(x-2\right)\left(3x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{-1}{3}\end{matrix}\right.\)

d) Ta có: \(x^2-6x-16=0\)

\(\Leftrightarrow\left(x-8\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=8\\x=-2\end{matrix}\right.\)

e) Ta có: \(x^4-6x^2-7=0\)

\(\Leftrightarrow\left(x^2-7\right)\left(x^2+1\right)=0\)

\(\Leftrightarrow x\in\left\{\sqrt{7};-\sqrt{7}\right\}\)

a) \(=6x^2y^2\left(6xy-7\right)\)

b) \(=3xy\left(x^3y+5x-6\right)\)

c) \(=\left(ax+ab\right)-\left(bx+x^2\right)=a\left(b+x\right)-x\left(b+x\right)=\left(a-x\right)\left(b+x\right)\)

d) \(=3\left(2x-1\right)-\left(2x-1\right)^2=\left(2x-1\right)\left(3-2x+1\right)=\left(2x-1\right)\left(4-2x\right)=2\left(2x-1\right)\left(2-x\right)\)

\(a,=6x^2y^2\left(6xy-7\right)\\ b,=3xy\left(x^3y+5x-6\right)\\ c,=x\left(a-x\right)-b\left(a-x\right)=\left(x-b\right)\left(a-x\right)\\ d,=3\left(2x-1\right)-\left(2x-1\right)^2=\left(2x-1\right)\left(3-2x+1\right)=2\left(2-x\right)\left(2x-1\right)\)

6 x 1 = 6

kết quả là 6 bạn nhé

6x1=6

x- \(\dfrac{1}{2}\) = 6 x \(\dfrac{1}{24}\)

x- 0,5 = 6 x \(\dfrac{1}{24}\)

x- 0,5 = \(\dfrac{1}{4}\) 

x- 0,5 = 0,25

x        = 0,25+0,5

x        =0,3

x - 1/2 = 6 x 1/24 

x - 0,5 = 1/4

x - 0,5 = 0,25 

x = 0,25 + 0,5 

x = 0,3

\(\frac{1}{3}\times\frac{1}{6}\times\frac{1}{9}=\frac{1\times1\times1}{3\times6\times9}=\frac{1}{162}\)

\(\frac{1}{3}\times\frac{1}{6}:\frac{1}{9}=\frac{1}{3}\times\frac{1}{6}\times\frac{9}{1}=\frac{1\times1\times9}{3\times6\times1}=\frac{9}{18}=\frac{1}{2}\)

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