1+2+4+8+.......+256+512 = ?
(1/2+1/4+1/8.....+1/256+1/512)*2=511/256
A=1/2+1/4+1/8.....+1/256+1/512
2A=1+1/2+1/4+1/8...1/256
A=(1+1/2+1/4+1/8...1/256)-(1/2+1/4+1/8.....+1/256+1/512)
A=1-1/512
A=511/512
511/512
1+1=
2+2=
4+4=
8+8=
16+16=
32+32=
64+64=
128+128=
256+256=
512+512=
1024+1024=
1 + 1 = 2
2 + 2 = 4
4 + 4 = 8
8 + 8 = 16
16 + 16 = 32
32 + 32 = 64
64 + 64 = 128
128 + 128 = 256
256 + 256 = 512
512 + 512 = 1024
1024 + 1024 = 2048
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=265
256+256=512
512+512=1024
1024+1024=2048
Học tốt ^_^
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048
1+1=?
2+2=?
4+4=?
8+8=?
16+16=?
32+32=?
64+64=?
128+128=?
256+256=?
512+512=?
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=156
256+256=512
512+512=1024
Lần lượt nhe:2
4
8
16
32
128
256
512
1024
các tổng này đều = các số hạng của phép tính trên đúng ko
A= 1/2 + 1/4 + 1/8 +...+1/256 +1/512
\(A=\dfrac{1}{2}+\dfrac{1}{2^2}+\dfrac{1}{2^3}+...+\dfrac{1}{2^9}\\ 2A=1+\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^8}\\ 2A-A=\left(1+\dfrac{1}{2}+...+\dfrac{1}{2^8}\right)-\left(\dfrac{1}{2}+\dfrac{1}{2^2}+...+\dfrac{1}{2^9}\right)\\ A=1-\dfrac{1}{2^9}=\dfrac{511}{512}\)
1+1
2+2
4+4
8+8
16+16
32+32
64+64
128+128
256+256
512+512
1024+1024
2048+2048
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128 = 256
256+256=512
512+512= 1024
1024+1024 = 2048
2048 + 2048 = 4096
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048
2048+2048=4096
1+1=2
2+2=4
4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
128+128=256
256+256=512
512+512=1024
1024+1024=2048
2048+2048=4096
1 + 2 + 4 + 8 + ........... + 256 + 512 =
1 + 2 + 4 + 8 + .......753........ + 256 + 512 = 1.536
Tk mk nha
~~~chúc bn hok tốt~~~
^_^
D=1/2+1/4+1/8+.............+1/256+1/512
\(D=\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+..........+\dfrac{1}{256}+\dfrac{1}{512}\)
\(\Leftrightarrow2D=1+\dfrac{1}{2}+\dfrac{1}{4}+......+\dfrac{1}{256}\)
\(\Leftrightarrow2D-D=\left(1+\dfrac{1}{2}+.....+\dfrac{1}{256}\right)-\left(\dfrac{1}{2}+\dfrac{1}{4}+.....+\dfrac{1}{512}\right)\)
\(\Leftrightarrow D=1-\dfrac{1}{512}=\dfrac{511}{512}\)
1/2+1/4+1/8+1/16+...+1/256+1/512
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}+\frac{1}{512}\)
\(A\cdot2=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\)
\(A\cdot2-A=1-\frac{1}{512}\)
\(A=\frac{511}{512}\)
1/2+1/4+1/8+1/16+...+1/256+1/512(gọi A là tổng các PS trên)
A*2=(1+1/2+1/4+1/8+...+1/128+1/256)/2
A*2-A=1+1/2+1/4+1/8+...+1/128+1/256-1/2-1/4-1/8-1/16-...-1/256-1/512.
A=1-1/512
A=511/512.
Kết bạn với mình nha!
1/2 + 1/4 + 1/8 + 1/16 +...+ 1/256 + 1/512