(x-7)^2=36
(x + 2)^2 + (2x -1)^2-(x - 3)^2 = 36
(2x -1)2 + (x + 3)2 - 5(x + 7)(x - 7) = 0
a: Ta có: \(\left(x+2\right)^2+\left(2x-1\right)^2-\left(x-3\right)^2=36\)
\(\Leftrightarrow x^2+4x+4+4x^2-4x+1-x^2+6x-9=36\)
\(\Leftrightarrow4x^2+6x-4-36=0\)
\(\Leftrightarrow4x^2+6x-40=0\)
\(\text{Δ}=6^2-4\cdot4\cdot\left(-40\right)=676\)
Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:
\(\left\{{}\begin{matrix}x_1=\dfrac{-6-26}{8}=-4\\x_2=\dfrac{-6+26}{8}=\dfrac{5}{2}\end{matrix}\right.\)
a, x/147 = 5/7 ; b, x -2/36 = 7/12
a: x/147=5/7
=>x=147*5/7=105
b: x-2/36=7/12
=>x-2/36=21/36
=>x=21/36+2/36=23/36
PTTNT A=x[x^2(x^2-7)-36]
Tính nhẩm:
7 x 8 = ..... 16 : 2 = ..... 36 : 6 = ..... 49 : 7 = .....
2 x 5 = ..... 72 : 8 = ..... 9 x 3 = ...... 63 : 7 = .....
6 x 4 = ..... 25 : 5 = ..... 4 x 8 = ...... 7 x 5 = ......
7 x 8 = 56 16 : 2 = 8 36 : 6 = 6 49 : 7 = 7
2 x 5 = 10 72 : 8 = 9 9 x 3 = 27 63 : 7 = 9
6 x 4 = 24 25 : 5 = 5 4 x 8 = 32 7 x 5 = 35
7 x 8 = 56
2 x 5 = 10
6 x 4 = 24
16 : 2 = 8
72 : 8 = 9
25 : 5 = 5
36 : 6 = 6
9 x 3 = 27
4 x 8 = 32
49 : 7 = 7
63 : 7 = 9
7 x 5 = 35
\(\dfrac{x+2}{7}\)=\(\dfrac{-36}{28}\)
tìm x:
\(=>\left(x+2\right).28=7.\left(-36\right)\\ =>\left(x+2\right).28=-252\\ =>x+2=-252:28\\ =>x+2=-9\\ =>x=-11\)
\(\Rightarrow28.\left(x+2\right)=-36.7\)
\(\Rightarrow28x+56+252=0\)
\(\Rightarrow28x=-308\)
\(\Rightarrow x=-11\)
root(5x + 2, 3) = 3 5sqrt(4x - 16) - 7/3 * sqrt(9x - 36) = 36 - 3sqrt(x - 4)
b:
ĐKXĐ: x>=4
\(5\sqrt{4x-16}-\dfrac{7}{3}\cdot\sqrt{9x-36}=36-3\sqrt{x-4}\)
=>\(5\cdot2\cdot\sqrt{x-4}-\dfrac{7}{3}\cdot3\cdot\sqrt{x-4}+3\sqrt{x-4}=36\)
=>\(6\sqrt{x-4}=36\)
=>\(\sqrt{x-4}=6\)
=>x-4=36
=>x=40
3/8 x (X - 2/3) - 2/9 x (3X - 1/2) = 7/36
\(\dfrac{3}{8}x-\dfrac{1}{4}-\dfrac{2}{3}x+\dfrac{1}{9}=\dfrac{7}{36}\)
=> \(\dfrac{3}{8}x-\dfrac{2}{3}x-\left(\dfrac{1}{4}+\dfrac{1}{9}\right)=\dfrac{7}{36}\)
=> \(\dfrac{-7}{24}x-\dfrac{5}{36}=\dfrac{7}{36}\)
=> \(\dfrac{-7}{24}x=\dfrac{1}{3}\)
=> \(x=\dfrac{-8}{7}\)
7.x+2=36
(x-7) mũ 2 - (x+4)(x-4)=36-2x
(x - 7)2 - (x + 4)(x - 4) = 36 - 2x
=> x2 - 14x + 49 - (x2 - 16) = 36 - 2x
=> x2 - 14x + 49 -x2 + 16 = 36 - 2x
=> -14x + 2x = -29
=> -12x = -29
=> x = 29/12
( x - 7 )2 - ( x - 4 )( x + 4 ) = 36 - 2x
<=> x2 - 14x + 49 - ( x2 - 16 ) = 36 - 2x
<=> x2 - 14x + 49 - x2 + 16 = 36 - 2x
<=> 65 - 14x = 36 - 2x
<=> 65 - 36 = -2x + 14x
<=> 29 = 12x
<=> x = 29/12
\(\left(x-7\right)^2-\left(x+4\right)\left(x-4\right)=36-2x\)
\(\left(x^2-14x+49\right)-\left(x^2-16\right)=36-2x\)
\(x^2-14x+49-x^2+16=36-2x\)
\(14x+65=36-2x\)
\(14x-2x=36+65\)
\(12x=101\)
\(x=101:12\)
\(x\approx8\)
Tim X
X x 7 = 36 x7
X x 7 = 12 x ( 5 - 3 - 2 )