a, ( 13.x - 12²) : 5 = 5

    ( 13.x - 12²)      = 5.5

    ( 13.x - 12²)      = 25

    ( 13.x - 144)      = 25

    13.x                   = 25 + 144

    13.x                   = 169

         x                   = 169 : 13

         x                   = 13

Vậy x = 13

b, 3.x[8² - 2.(2⁵ - 1)]  = 2022

    3.x[64 - 2.(32 - 1)] = 2022

    3.x[62 - 2.31]         = 2022

    3.x[62 - 62]            = 2022

    3.x.0                      = 2022

    3.x                         = 2022 : 0

    3.x                         = 0

       x                         = 0 : 3

       x                         = 0

Vậy x = 0

Đây bạn nhé !!!

Chúc bạn học tốt !!!

\(a,TH1:x-2021=0=>x=2021\)

\(Th2:x-2022=0=>x=2022\)

Vậy \(x\in\left\{2021;2022\right\}\)

\(b,x\left(8-5\right)=1080\)

\(x.3=1080\)

\(x=360\)

\(c,x^3=216< =>6^3=216=>x=3\)

\(d,5^5=3125\)

a)  ( x- 2021) * ( x- 2022) = 0

=>  \(\orbr{\begin{cases}x-2021=0\\x-2022=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2021\\x=2022\end{cases}}}\)

b)  b. 8x - 5x = 2022

=>  3x  =  2022

=>  x  =   674

c)  \(5\cdot x^3=1080\)

=>  \(x^3=216\)

=>  \(x^3=6^3\)

=>   x  =  6

d)   \(5^x=3125\)

=>    \(5^x=5^5\)

=>  x    =  5

\(a,81\cdot2022+25\cdot2022-6\cdot2022=2022\cdot\left(81+25-6\right)=2022\cdot100=202200\)

\(b,\left(x-1\right)\cdot\frac{2}{3}-\frac{1}{5}=\frac{2}{5}\)

\(\left(x-1\right)\cdot\frac{2}{3}=\frac{3}{5}\)

\(x-1=\frac{9}{10}\)

\(x=\frac{19}{10}\)

Vậy \(x=\frac{19}{10}\)

( Nếu phần b là hỗn số thì mình làm thế kia , còn nếu là nhân thì bạn tham khảo Câu hỏi của lương bảo ngọc - Toán lớp 5 - Học trực tuyến OLM nhé )

81 x 2022 + 25 x 2022 - 6 x 2022

= ( 81 + 25 - 6 ) x 2022

= 100 x 2022

= 202 200

b) \(\left(\text{x - 1}\right)\frac{\text{2}}{\text{3}}-\frac{\text{1}}{\text{5}}=\frac{\text{2}}{\text{5}}\)

\(\frac{\text{3 x }\text{( x - 1 ) }+\text{2}}{\text{3}}=\frac{\text{1}}{\text{5}}+\frac{\text{2}}{\text{5}}=\frac{\text{3}}{\text{5}}\)

=> \(\text{3 x ( x - 1 ) }+\text{2}=\frac{\text{3}}{\text{5}}\text{ x 3 = }\frac{\text{9}}{\text{5}}\)

=> \(\text{3 x ( x - 1 ) }=\frac{\text{9}}{\text{5}}-\text{2}=\frac{\text{-1}}{\text{5}}\)

=> \(\text{ x-1}=\frac{\text{-1}}{\text{5}}:3=\frac{\text{-1}}{\text{15}}\)

=> \(\text{x}=\frac{\text{-1}}{\text{15}}+\text{1 = }\frac{\text{14}}{\text{15}}\)

dạ vâng a off

\(5^{12}:5^{x+2}=\left(-5\right)^3.\left(-5\right)^7\)

\(\Rightarrow5^{12-x-2}=\left(-5\right)^{3+7}\)

\(\Rightarrow5^{10-x}=\left(-5\right)^{10}\)

\(\Rightarrow5^{10-x}=5^{10}\)

\(\Rightarrow10-x=10\)

\(\Rightarrow x=0\)

\(\left(2x-1\right)^{2020}+\left(y-\frac{2}{5}\right)^{2022}+\left|x+y-z\right|=0\)

Ta có : \(\left(2x-1\right)^{2020}\ge0\forall x;\left(y-\frac{2}{5}\right)^{2022}\ge0\forall x;\left|x+y-z\right|\ge0\forall x;y;z\)

Dấu bằng xảy ra <=> \(x=\frac{1}{2};y=\frac{2}{5};z=x+y=\frac{1}{2}+\frac{2}{5}=\frac{9}{10}\)

Vậy \(x=\frac{1}{2};y=\frac{2}{5};z=\frac{9}{10}\)

1.     Giải:

Do \(5x+13B\in\left(2x+1\right)\Rightarrow5x+13⋮2x+1.\)

 \(\Rightarrow2\left(5x+13\right)⋮2x+1\Rightarrow10x+26⋮2x+1.\)

 \(\Rightarrow5\left(2x+1\right)+21⋮2x+1.\)

Do 5(2x+1)⋮2x+1⇒ Ta cần 21⋮2x+1.

⇒ 2x+1 ϵ B(21)=\(\left\{1;3;7;21\right\}.\)

Ta có bảng:

Vậy xϵ\(\left\{0;1;3;10\right\}.\)

2. Giải:

Do (2x-18).(3x+12)=0.

⇒ 2x-18=0             hoặc             3x+12=0.

⇒ 2x     =18                               3x       =-12.

⇒   x     =9                                   x       =-4.

Vậy xϵ\(\left\{-4;9\right\}.\)

3. S= 1-2-3+4+5-6-7+8+...+2021-2022-2023+2024+2025.

S= (1-2-3+4)+(5-6-7+8)+...+(2021-2022-2023+2024)+2025 Có 506 cặp.

S= 0 + 0 + ... + 0 + 2025.

⇒S= 2025.

Tìm x ∈ N

a) 2x chia hết cho 12 ⇒ 2x ∈ B(12) 

2x chia hết cho 30 ⇒ 2x ∈ B(30) 

Mà x có hai chữ số ⇒ 10 ≤ x ≤ 99 

\(\Rightarrow2x\in BC\left(12;30\right)\)

Mà: \(B\left(12\right)=\left\{0;12;24;36;48;60;72;84;96;108;...\right\}\)

\(B\left(30\right)=\left\{0;30;60;90;120;...\right\}\)

\(\Rightarrow BC\left(12;30\right)=\left\{0;60;...\right\}\)

\(\Rightarrow2x=60\)

\(\Rightarrow x=\dfrac{60}{2}\\ \Rightarrow x=30\)

b) \(9^{x+2}-9^{x+1}+9^x=657\)

\(\Rightarrow9^x\cdot\left(9^2-9+1\right)=957\)

\(\Rightarrow9^x\cdot\left(81-8\right)=657\)

\(\Rightarrow9^x\cdot73=657\)

\(\Rightarrow9^x=9\)

\(\Rightarrow9^x=9^1\)

\(\Rightarrow x=1\)

a) (x - 15) × 7 - 270 : 45 = 169

(x - 15) × 7 - 6 = 169

(x - 15) × 7 = 169 + 6

(x - 15) × 7 = 175

x - 15 = 175 : 7

x - 15 = 25

x = 25 + 15

x = 40

b) [(4x + 28) × 3 + 55] : 5 = 35

(4x + 28) × 3 + 55 = 35 × 5

(4x + 28) × 3 + 55 = 175

(4x + 28) × 3 = 175 - 55

(4x + 28) × 3 = 120

4x + 28 = 120 : 3

4x + 28 = 40

4x = 40 - 28

4x = 12

x = 12 : 4

x = 3

c) (455 × x : 2 × 6) : 5 = 31

455 × x : 2 × 6 = 31 × 5

455 × x : 2 × 6 = 155

x × 455 : 2 × 6 = 155

x × 1365 = 155

x = 155 : 1365

x = 31/273

d) 128 × x - 12 × x - 16 × x = 520800

(128 - 12 - 16) × x = 520800

100 × x = 520800

x = 520800 : 100

x = 5208

e) (x × 0,25 + 2022) × 2023 = (50 + 2022) × 2023

(x × 0,25 + 2022) × 2023 = 2072 × 2023

(x × 0,25 + 2022) × 2023 = 4191656

x × 0,25 + 2022 = 4191656 : 2023

x × 0,25 + 2022 = 2072

x × 0,25 = 2072 - 2022

x × 0,25 = 50

x = 50 : 0,25

x = 200

f) 4 × x + 100 = x + 280

4 × x - x = 280 - 100

(4 - 1) × x = 180

3 × x = 180

x = 180 : 3

x = 60

g) (x + 1) + (x + 2) + (x + 3) + ... + (x + 100) = 7450

x + 1 + x + 2 + x + 3 + ... + x + 100 = 7450

100 × x + 100 × 101 : 2 = 7450

100 × x + 5050 = 7450

100 × x = 7450 - 5050

100 × x = 2400

x = 2400 : 100

x = 24