a: \(7^{x-5}+121=58\cdot2^3\)

=>\(7^{x-5}+121=58\cdot8\)

=>\(7^{x-5}=343\)

=>x-5=3

=>x=8

b: \(10^{x+25}+168=73\cdot2^4\)

=>\(10^{x+25}+168=73\cdot16\)

=>\(10^{x+25}=1000\)

=>x+25=3

=>x=-22

c: \(5x+59=21\cdot2^2=21\cdot4=84\)

=>5x=84-59=25

=>x=5

d: \(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)

=>\(2^{x-1}+3=24-16+3\)

=>\(2^{x-1}=8\)

=>x-1=3

=>x=4

7ˣ⁻⁵ + 121 = 58.2³

7ˣ⁻⁵ = 58.8 - 121

7ˣ⁻⁵ = 464 - 121

7ˣ⁻⁵ = 343

7ˣ⁻⁵ = 7³

x - 5 = 3

x = 3 + 5

x = 8

-------

10ˣ⁻²⁵ + 168 = 73.2⁴

10ˣ⁻²⁵ = 73.16 - 168

10ˣ⁻²⁵ = 1000

10ˣ⁻²⁵ = 10³

x - 25 = 3

x = 3 + 25

x = 28

-------- 

5x + 59 = 21.2²

5x = 21.4 - 59

5x = 84 - 59

5x = 25

x = 25 : 5

x = 5

--------

3 + 2ˣ⁻¹ = 24 - [4² - (2² - 1)]

3 + 2ˣ⁻¹ = 24 - (16 - 3)

2ˣ⁻¹ = 24 - 13 - 3

2ˣ⁻¹ = 8

2ˣ⁻¹ = 2³

2ˣ⁻¹ = 3

x - 1 = 3

x = 3 + 1

x = 4

\(2^{x+3}.2=2^2.3+52\)

\(=>2^{x+3}.2=64\)

\(=>2^{x+3}=64:2\)

\(=>2^{x+3}=32\)

\(=>2^{x+3}=2^5\)

=>x+3=5

=>x=5-3

=>x=2

Vậy ...........

 2^{x + 3} . 2 = 2² . 3 + 52

 2^{x + 3} . 2 = 4 . 3 + 52

 2^{x + 3} . 2 = 12 + 52

 2^{x + 3} . 2 = 64

     2^{x + 3}  = 64 : 2

     2^{x + 3}  = 32

     2^{x + 3} = 2⁵

     x + 3 = 5

           x = 5 - 3

           x = 2

Vậy x = 2

\(\frac{\left(\frac{2}{3}\right)^3\cdot\left(-\frac{3}{4}\right)^2\cdot\left(-1\right)^5}{\left(\frac{2}{5}\right)^2\cdot\left(-\frac{5}{12}\right)^3}\)

\(=\frac{\frac{2^3}{3^3}\cdot\frac{3^2}{4^2}\cdot\left(-1\right)}{\frac{2^2}{5^2}\cdot\frac{\left(-5\right)^3}{12^3}}\)

\(=\frac{\frac{8}{27}\cdot\frac{9}{16}\cdot\left(-1\right)}{\frac{4}{25}\cdot\frac{-125}{1728}}=\frac{-\frac{1}{6}}{-\frac{5}{432}}=\left(-\frac{1}{6}\right)\cdot\left(-\frac{432}{5}\right)=\frac{72}{5}\)

đã đi học ở trường đâu, học nhà cô à

bạn biết câu trả lời ko

nếu biết mong bạn giúp mình

a)

`9/2-3`

`=9/2-6/2`

`=3/2`

b)

`8/5xx25/12`

`=10/3`

c)

`4:3/7`

`=4xx7/3`

`=28/3`

thank you bạn

\(x:\dfrac{2}{3}=\dfrac{5}{4}\)

\(x=\dfrac{5}{4}\times\dfrac{2}{3}\)

\(x=\dfrac{5}{6}\)

x : 2/3 = 1/2 + 3/4 

x : 2/3 = 5/4

x = 5/4 x 2/3

x = 5/6 

\(x:\dfrac{2}{3}=\dfrac{1}{2}+\dfrac{3}{4}\)

\(x:\dfrac{2}{3}=\dfrac{2}{4}+\dfrac{3}{4}\)

\(x:\dfrac{2}{3}=\dfrac{5}{4}\)

\(x=\dfrac{5}{4}\times\dfrac{2}{3}\)

\(x=\dfrac{10}{12}\)

\(x=\dfrac{5}{6}\)

\(\left(x^2+5\right)\left(x-5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x^2+5=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x^2=-5\\x=5\end{cases}\Leftrightarrow}\orbr{\begin{cases}x\in\varnothing\\x=5\end{cases}}}\)

Vậy x=5

TK MK ĐÊ RỒI MK LÀM TIẾP!

\(x-\frac{1}{9}=\frac{8}{3}\)

\(\Leftrightarrow x=\frac{8}{3}+\frac{1}{9}\)

\(\Leftrightarrow x=\frac{24+1}{9}=\frac{25}{9}\)

\(\frac{-x}{4}=\frac{-9}{x}\)

\(\Leftrightarrow\left(-x\right)x=\left(-9\right)4\)

\(\Leftrightarrow-x^2=-36\)

\(\Leftrightarrow x^2=36=6^2\Leftrightarrow x=\pm6\)

Nhanh nhé mai mình nộp rồi