a,P(x)=4x\(^3\)+2x\(^2\)-2x+7-x\(^2\)-x

=4x\(^3\)+(2x\(^2\)-x\(^2\))+(-2x-x)+7

=4x\(^3\)+x\(^2\)-3x+7

Q(x)=-4x\(^3\)+x-14-2x-x\(^2\)-1

=-4x\(^3\)-x\(^2\)+(x-2x)+(-14-1)

= -4x\(^3\)-x\(^2\) -x -15

b, P(x)+Q(x)=4x\(^3\)+x\(^2\)-3x+7-4x\(^3\)-x\(^2\) -x -15

=\(\left(4x^3-4x^3\right)\)+\(\left(x^2-x^2\right)\)+(-3x-x)+(7-15)

= -4x-8

P(x)-Q(x)=(4x\(^3\)+x\(^2\)-3x+7)-(-4x\(^3\)-x\(^2\) -x -15)

=4x\(^3\)+x\(^2\)-3x+7+4x\(^3\)+x\(^2\) +x +15

=\(\left(4x^3+4x^3\right)\)+\(\left(x^2+x^2\right)\)+(-3x+x)+(7+15)

= \(8x^3\) + \(2x^2\) - 2x + 22

1: P(x)=M(x)+N(x)

=-2x^3+x^2+4x-3+2x^3+x^2-4x-5

=2x^2-8

2: P(x)=0

=>x^2-4=0

=>x=2 hoặc x=-2

3: Q(x)=M(x)-N(x)

=-2x^3+x^2+4x-3-2x^3-x^2+4x+5

=-4x^3+8x+2

cái Q(x)=\(5x^2-4x^3-2x+7\)

mik ghi nhầm xin lổy đc chx 

a) \(P\left(x\right)=6x^3-3x^2+5x-1\)

\(Q\left(x\right)=5x^2-4x^2-2x+7=\left(5x^2-4x^2\right)-2x+7=x^2-2x+7\) ( Kết quả này cũng giống như sắp xếp nhé)

b) \(P\left(x\right)+Q\left(x\right)=6x^3+5x-3x^2-1+\left(x^2-2x+7\right)\)

\(=6x^3+5x-3x^2-1+x^2-2x+7\)

\(=6x^3+\left(5x-2x\right)+\left(-3x^2+x^2\right)+\left(-1+7\right)\)

\(=6x^3+3x+\left(-2x^2\right)+6\)

P(x)= 4x^3 + 2x^2 - 2x + 7 - x^2 - x

Q(x)= -4x^3 + x- 14 - 2x- x^2 - 1

P(x) = - Q(x)

<=> P(x) + Q(x) = 0

<=> 4x^3 + 2x^2 - 2x + 7 - x^2 - x -4x^3 + x- 14 - 2x- x^2 - 1 = 0

<=> -4x - 8 = 0

<=> -4(x+2) = 0

<=> x = -2

a: P(x)=5x^3+3x^2-2x-5

\(Q\left(x\right)=5x^3+2x^2-2x+4\)

b: P(x)-Q(x)=x^2-9

P(x)+Q(x)=10x^3+5x^2-4x-1

c: P(x)-Q(x)=0

=>x^2-9=0

=>x=3; x=-3

d: C=A*B=-7/2x^6y^4

a, \(P\left(x\right)=4x^3+2x-3+2x-2x^2-1\\ =4x^3-2x^2+\left(2x+2x\right)+\left(-3-1\right)\\ =4x^3-2x^2+4x-4\)

Bậc của P(x) là 3

\(Q\left(x\right)=6x^3-3x+5-2x+3x^2\\ =6x^3+3x^2+\left(-3x-2x\right)+5\\ =6x^3+3x^2-5x+5\)

Bậc của Q(x) là 3

b, \(M\left(x\right)=P\left(x\right)+Q\left(x\right)=4x^3-2x^2+4x-4+6x^3+3x^2-5x+5\\ =\left(4x^3+6x^3\right)+\left(-2x^2+3x^2\right)+\left(4x-5x\right)+\left(-4+5\right)\\ =10x^3+x^2-x+1\)