=>23x-11x-3x=54

=>9x=54

hay x=6

=>23x-11x-3x=54

 x=6

1,\(54.\left(23-11\right)+23.\left(-22-54\right)\)

\(=54.12+23.\left(-76\right)\)

\(=648-1748\)

\(=-1100\)

2,\(-7+2x=-17-\left(-36\right)\)

\(=>-7+2x=-17+36\)

\(=>-7+2x=19\)

\(=>2x=19+7=26\)

\(=>x=\frac{26}{2}=13\)

3,\(5⋮2a+3\)

\(=>2a+3\inƯ\left(5\right)\)

\(=>2a+3\in\left\{-1;-5;1;5\right\}\)

\(=>2a\in\left\{-4;-8;-2;2\right\}\)

\(=>a\in\left\{-2;-4;-1;1\right\}\)

Vậy ...

54 . ( 23 - 11 ) + 23 . ( -22 - 54 )

=54.23-54.11+23.-22-23.54

=-54.11+23.-22

=-22(27+23)

=-22.50

=-1100

-7 + 2x = -17 - ( -36 ) 

-7+2x=-17+36

-7+2x+17-36=0

-26+2x=0

2x=26

x=13

Vậy x=13

Để \(5⋮\left(2a+3\right)\Leftrightarrow\left(2a+3\right)\inƯ\left(5\right)\)

\(\Leftrightarrow\left(2a+3\right)\in\left\{\pm1;\pm5\right\}\)

\(\Leftrightarrow a\in\left\{-1;-2;1;-4\right\}\)

Bài 1:

54. (23-11) + 23.(-22-54) = 54.23-11.54 -23.22 - 54.23

                                        = (54.23-54.23) -(11.54+23.22)

                                        = 0 - (11.54 +23.11.2)

                                        = 0 - 11.(54+23.2)

                                        = 0 - 11. 100

                                       = -1100

Bài 2:                        -7 +2x = -17 -(-36)

                                  -7 +2x = 19

                                       2x  = 26

                                         x  = 13

Bài 3:        Ta có: \(5⋮\left(2a+3\right)\) 

\(\Rightarrow2a+3\inƯ\left(5\right)\)

\(\Rightarrow2a+3\in\left\{-5;-1;1;5\right\}\)

\(\Rightarrow2a\in\left\{-8;-4;-2;2\right\}\)

\(\Rightarrow a\in\left\{-4;-2;-1;1\right\}\)

a: =6/35x39/54=13/105

b: \(=\dfrac{-5}{7}\left(\dfrac{2}{11}+\dfrac{9}{11}\right)+\dfrac{12}{7}=\dfrac{-5}{7}+\dfrac{12}{7}=1\)

(11:54) + 89 = (12:43) pm

{11:54} + 89 ={12:29}

\(54:3^1+6.5^2\)
\(=54:3+6.25\)
\(=18+150\)
\(=168\)
\(---------\)
\(11-13+15-17+19-21+23-25\)
\(=\left(11-13\right)+\left(15-17\right)+\left(19-21\right)+\left(23-25\right)\)
\(=\left(-2\right)+\left(-2\right)+\left(-2\right)+\left(-2\right)\)
\(=\left(-2\right).4\)
\(=-8\)

mn giúp min bài này vs ạ

<-6>.[3^2-<-2.^5]-<-11>

=<-6>.[9-<-10>]-<-11>

=<-6>.19-<-11>

=   -114-<-11>

=    -103

75  .  <-29>+29.<-25>

=<-75>.29+29.<-25>

=29.<-75+-25>

=29.<-100>

=-2900

e. = 12 - 25 + 38 + 25 - 38 + 88  - 250 

    = ( -25 + 25) + (38 - 38) + ( 12 + 88) - 250

   = -150

f. = (-12).44 + 44.(-88)

 = 44 ( -12 -88 )

= 44 . 100

= 4400

g. = -48 + 54 -77 -24 + 48 + 77

= (-48 + 48) + (-77+77) + (54 -24)

= 30

h. = 11.(-42) + 11.(-26) + 42.11 + 42.26 -26.11 - 42.26

 = \([11.\left(-42\right)+11.42]+\left[11.\left(-26\right)-26.11\right]+[42.26-42.26]\)

= 11. (-52)

= - 572

\(e.-\left(-12+25-38\right)+\left(25-38+88\right)-250\\ =12-25+38+25-38+88-250\\ =\left(25-25\right)+\left(38-38\right)+\left(12+88\right)-250\\ =0+0+100-250=-150\)

\(f.\left(-12\right)\cdot\left(67-23\right)+44\cdot\left(-88\right)\\ =\left(-12\right)\cdot44+44\cdot\left(-88\right)\\ =44\cdot\left[-12+\left(-88\right)\right]\\ =44\cdot\left(-100\right)=-4400\)

\(g.\left(-48+54-77\right)-\left(24-48-77\right)\\ =-48+54-77-24+48+77\\ =\left(48-48\right)+\left(54-24\right)+\left(77-77\right)\\ =0+30+0=30\)

\(h.11\cdot\left(-42-26\right)+42\cdot\left(11+26\right)-26\cdot11-42\cdot26\\ =11\cdot\left(-68\right)+42\cdot37-26\cdot11-42\cdot26\\ =-748+1554-286-1092=-572\)

đề?

sao cho ????????????????

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