Đáp án là A

Ta có: M = 14 - 23 + (5 - 14) - (5 - 23) + 17 = 14 - 23 + 5 - 14 - 5 + 23 + 17

     = (14 - 14) + (5 - 5) - (23 - 23) + 17 = 0 + 0 - 0 + 17 = 17

N = 24 - (72 - 13 + 24) - (72 - 13) = 24 - 72 + 13 - 24 - 72 + 13

     = (24 - 24) - (72 + 72) + (13 + 13) = 0 - 144 + 26 = -118

Do đó M > N

Đáp án cần chọn là: A

\(2^{500}\)và  \(5^{200}\)

\(2^{500}=\left(2^5\right)^{100}=32^{100}\)

\(5^{200}=\left(5^2\right)^{100}=25^{100}\)

Ta thấy :

 \(32^{100}>25^{100}\Rightarrow2^{500}>5^{200}\)

\(31^{11}\) và  \(17^{14}\)

\(31^{11}< 32^{12}=\left(2^5\right)^{12}\)

\(17^{14}< 18^{14}=\left(9.2\right)^{14}\)

Ta thấy \(\left(2^5\right)^{12}< \left(9.2\right)^{14}\Rightarrow31^{11}>17^{14}\)

a) `1/2 xx 5/4 + 1/2 xx 3/4 + 1/2`

`=1/2 xx (5/4 + 3/4 + 1)`

`=1/2 xx 3`

`=3/2`

b) `72/95 xx 64/72 xx 95/72 xx 14/86 xx 72/64 xx 86/14`

`=(72xx64xx95xx14xx72xx86)/(95xx72xx72xx86xx64xx14)`

`= 1`.

a)1/2.(5/4+3/4+1)

=1/2.3

=3/2

b)=(72/95.95/72).(64/72.72/64).(14/86.86/14)

=1.1.1=1

a: Ta có: \(3^{2020}=3^{2018}\cdot3^2=3^{2018}\cdot9\)

mà 9<10

nên \(3^{2020}< 10\cdot3^{2018}\)

1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)

\(=2155-174-2155-68+174\)

=-68

2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)

\(=-25\cdot\left(72-21+49\right)\)

\(=-25\cdot100=-2500\)

a)-900

b)456

a) (43 -13).(-3) +27.(-14 - 16) = -900

b) (-72).(34 -12) -34.(12 - 72) = 456

a)-900 b)456

Đáp án C