\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)

\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)

\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)

Vậy x = 5/19

\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)

Vậy x = 1/2 hoặc x = -6

\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)

\(\Leftrightarrow\left(x-3\right)^2=16\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)

Vậy x = 7 hoặc x = -1

\(\frac{8}{3}:x=\frac{16}{9}:\frac{8}{3}\)

\(\frac{8}{3}:x=\frac{16}{9}.\frac{3}{8}\)

\(\frac{8}{3}:x=\frac{2}{3}\)

       \(x=\frac{8}{3}:\frac{2}{3}\)

      \(x=\frac{8}{3}.\frac{3}{2}\)

    \(x=4\)

Vậy x = 4

a) X nhân 3/8 = 9/16
    X= 9/16 chia 3/8
    X= 9/16 nhân 8/3
    X= 3/2
b) x chia 12/7=5/8
    x= 5/8 nhân 12/7
    x= 15/14

Lời giải:

a. 

$x\times \frac{3}{8}=\frac{9}{16}$

$x=\frac{9}{16}: \frac{3}{8}$

$x=\frac{3}{2}$

b.

$x:\frac{12}{7}=\frac{5}{8}$

$x=\frac{5}{8}\times \frac{12}{7}$

$x=\frac{15}{14}$

\(a,\\ \left(x+\dfrac{1}{2}\right)^3=\dfrac{8}{125}=\dfrac{2^3}{5^3}\\ \left(x+\dfrac{1}{2}\right)^3=\left(\dfrac{2}{5}\right)^3\\ \Rightarrow\left(x+\dfrac{1}{2}\right)=\dfrac{2}{5}\\ x=\dfrac{2}{5}-\dfrac{1}{2}\\ x=-\dfrac{1}{10}\)

\(b,3\left|x\right|-27=\dfrac{1}{5}\\ 3\left|x\right|=\dfrac{1}{5}+27\\ 3\left|x\right|=\dfrac{136}{5}\\ \left|x\right|=\dfrac{136}{5}:3\\ \left|x\right|=\dfrac{136}{15}\\ Vậy:x=\dfrac{136}{15}.or.x=-\dfrac{136}{15}\)

\(c,\\ \dfrac{1}{2}.\left(x+\dfrac{1}{3}\right)=\dfrac{1}{16}\\ \left(x+\dfrac{1}{3}\right)=\dfrac{1}{16}:\dfrac{1}{2}\\ \left(x+\dfrac{1}{3}\right)=\dfrac{1}{8}\\ x=\dfrac{1}{8}-\dfrac{1}{3}\\ x=-\dfrac{5}{24}\)

x^3 = 27

x^3 = 3^3

=> x = 3

(2x-1)^3 = 8

(2x-1)^3 = 2^3

2x-1 = 2

2x = 2+1

2x = 3

x = 3:2

=> ko có x phù hợp.

(x-2)^2 = 16

(x-2)^2 = 4^2

x-2 = 4

x = 4+2

x = 6

Chúc bn học tốt!

x^3 = 27

x^3 = 3^3

Vậy x = 3

Đề bài 2 hình như sai bạn ạ

( x - 2 )^2 = 16

( x- 2 )^2 = 4^2

x - 2 = 4

x      = 4 + 2

x      = 6

Vậy x = 6

1) \(x^3=27=3^3\Rightarrow x=3\)

2) \(\left(2x-1\right)^3=8=2^3\Rightarrow2x-1=2\)

\(\Rightarrow2x=3\Rightarrow x=\dfrac{3}{2}\)

3) \(\left(x-2\right)^2=16\)

Mà \(x\in N\)

\(\Rightarrow x-2=4\Rightarrow x=6\)