d) 12x 156 - 12 x 55 - 12

= 12 x ( 156 - 55 - 12 )

= 12 x 100

= 1200

e ) 12 x 11 + 21 x 11 + 11 x 33

= ( 12+ 21 + 33) x 12

= 66 x 11

= 726

g) 132 x 11 - 11 x 32 - 54 x 11

= ( 132 - 32 - 54 ) x 11

= 46 x 11

= 506

d) 12 x 156 - 12 x 55 - 12 = 12x(156 - 55 - 1 ) = 12 x 100 = 1200

e) 12 x 11 + 21 x 11 + 11 x 33 = 11  x ( 12 + 21 + 33 ) = 11  x 66 = 726

g) 132 x 11 - 11 x 32 - 54 x 11 = 11 x ( 132 - 32 - 54 ) = 11 x 46 = 506

d) \(12\times156-12\times55-12\) \(=12\times\left(156-55-1\right)\)

                                                         \(=12\times100=1200\)

e) \(12\times11+21\times11+11\times33\)\(=11\times\left(12+21+33\right)=11\times66=726\)

g) \(132\times11-11\times32-54\times11\) \(=11\times\left(132-32-54\right)=11\times46=506\)

= 1100 nha

1100

\(1100\)

 a)12 x 11 + 21 x 11 x 11 + 11 x 33

= ( 12 x 11 ) + ( 21 x 11 x 11 ) + ( 11 x 33 )

= 

= 

b)132x11-11x32-54x11

= ( 132 x 11 ) - ( 11 x 32 ) - ( 54 x 11 )

= 

\(a,=11\times\left(12+21+33\right)=11\times66=726\\ b,=11\times\left(132-32-54\right)=11\times46=506\\ c,=11\times\left(245+365\right)=11\times610=6710\\ d,=75\times\left(78+89+123\right)=75\times290=21750\\ e,=\left(2\times50\right)\times\left(250\times8\right)=100\times2000=200000\\ g,=1994\times\left(867+11\right)=1994\times878=1750732\)

a) 12 x 11 + 21 x 11 + 11 x 33

= 11 x ( 12 + 21 + 33)

= 11 x 66

= 726

b) 132 x 11 - 11 x 32 - 54 x 11

= 11 x ( 132 - 32 - 54)

= 11 x 46

= 506

c) 245 x 11 + 11 x 365

= 11 x ( 245 + 365 )

= 11 x 610 = 6710

d) 78 x 75 + 75 x 89 + 75 x 123

= 75 x ( 78 + 89 + 123)

= 75 x 290 = 21750

e) 2 x 250 x 50 x 8

= (2 x 50) x ( 250 x 8)

= 100 x 2000 = 200000

g) 1994 x 867 + 1994 x 11

= 1994 x ( 867 + 11)

= 1994 x 878 = 1750732

c: Ta có: 11+x:5=13

\(\Leftrightarrow x:5=2\)

hay x=10

d: Ta có: \(13+2\left(x+1\right)=15\)

\(\Leftrightarrow2x+2=2\)

\(\Leftrightarrow2x=0\)

hay x=0

e: Ta có: 2x+21=41

\(\Leftrightarrow2x=20\)

hay x=10

f: Ta có: \(12+3\left(x-2\right)=60\)

\(\Leftrightarrow3\left(x-2\right)=48\)

\(\Leftrightarrow x-2=16\)

hay x=18

g: Ta có: \(24x-11\cdot13=11\cdot11\)

\(\Leftrightarrow24x=11\cdot24\)

hay x=11

h: Ta có: \(17-\left(x-4\right):2=3\)

\(\Leftrightarrow\left(x-4\right):2=14\)

\(\Leftrightarrow x-4=28\)

hay x=32

11×[(62+(-12)]+50+11

11×51+50+11

561+50+11

611+11

622

(5/13+8/13)+(-20/41+-21/41)+-5/7

1+-1+-5/7

-5/7

a)

11 x 62 + -12 x 11 + 50 + 11

= 11 x (62 + -12) + 50 + 11

= 11 x 50 + 50 + 11

= (11 + 11) x (50 + 50)

= 22 x 100

= 2200

b)

5/13 + -5/7 + -20/41 + 8/13 + -21/41

= (5/13 + 8/13) + (-20/41 + -21/41) + -5/7

= 1 + -1 + -5/7

= -5/7

b: \(\Leftrightarrow1-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{23}+\dfrac{1}{23}-\dfrac{1}{34}+...+\dfrac{1}{89}-\dfrac{1}{100}+x=\dfrac{5}{3}\)

=>x+99/100=5/3

=>x=5/3-99/100=203/300

c: \(\Leftrightarrow\left(\dfrac{1}{11}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{15}+...+\dfrac{1}{19}-\dfrac{1}{21}\right)-x+4+\dfrac{221}{231}=\dfrac{7}{3}\)

\(\Leftrightarrow\dfrac{10}{231}-x+4+\dfrac{221}{231}=\dfrac{7}{3}\)

=>5-x=7/3

hay x=8/3

Hướng dẫn giải:

a) 12 x 11 = 132

25 x 11 = 275

31 x 11 = 341

b) 83 x 11 = 913

58 x 11 = 638

79 x 11 = 869

a,132                 638

  275                  869

 341

b,913