96 × 3 × ( x + 35 ) =  515

    288 × ( x + 35 ) = 515

                x + 35   = 515 : 288

                x + 35   = 515 / 288

                         x  = 515 / 288 - 35

                          x = -9565 / 288

5(x+35)=515

x+35 = 515 ÷5

x+35 = 103

x = 103-35

x = 68

Đúng ko

5( x + 35) = 515

x + 35 = 515 : 5

x + 35 = 103

x = 103 - 35

x = 68

96 - 3( x +1) = 42

3( x+1) = 96 - 42

3(x +1) = 54

x +1 = 54 : 3

x + 1 = 18

x = 18-1

x =17

chắc chắn nha bn!!!

1.
=(25x4)x(96x2)
=100x192=19200
2.
=155x(42+58)
=155x100=1500
3.
=35x(461+539)
=35x1000=35000
4
=196x(73+27)
=196x100=19600

ủa ;-;

sao ko cách dòng dc ta

36x4=144

50x3=150

22x6=132

35x4=140

46:2=23

96:3=32

60:3=20

88:4=22

96 : ( 3,75 : x ) = 94,5

3,75 : x = 96 : 94,5

3,75 : x = \(\frac{96}{94,5}\) 

x = 3,75 : \(\frac{96}{94,5}\)

x = \(\frac{354,375}{96}\)

\(\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{1}{x}\left(3+x\right)=\frac{6}{13}\)

\(\Rightarrow\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{3+x}{x}=\frac{6}{13}\)

\(\Rightarrow\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+1+\frac{3}{x}=\frac{6}{13}\)

\(\Rightarrow\frac{3}{x}+\frac{8}{5}=\frac{6}{13}\)

\(\Rightarrow\frac{3}{x}=-\frac{74}{65}\)

\(\Rightarrow-74x=195\)

\(\Rightarrow x=\frac{-195}{74}\)

\(\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{1}{x\left(3+x\right)}=\frac{6}{13}\)

\(\frac{3}{5}+\frac{1}{x\left(3+x\right)}=\frac{6}{13}\)

\(\frac{1}{x\left(3+x\right)}=-\frac{9}{65}\)

\(\Rightarrow-9x\left(3+x\right)=65\)

\(\Rightarrow-9x^2-27x-65=0\)

\(\Rightarrow9x^2-27x+65=0\)

Đề sai

1\(x=24\)

2.\(x=17\)

3.\(x=68\)

541 + ( 218 - x ) = 735

           218 - x   = 735 - 541

           218 - x   =    194

                   x   =  218 - 194

                   x   =      24

541 + (218 - x) = 735

=> 218 - x = 194

=> x = 218 - 194

     x = 24

t i c k nhé!! 3463464457568797898746837316436545745

Pt\(\Leftrightarrow\dfrac{x+98}{2}+1+\dfrac{x+96}{4}+1+\dfrac{x+65}{35}+1=\dfrac{x+3}{97}+1+\dfrac{x+5}{95}+1+\dfrac{x+49}{51}+1\)

\(\Leftrightarrow\dfrac{x+100}{2}+\dfrac{x+100}{4}+\dfrac{x+100}{35}-\dfrac{x+100}{97}-\dfrac{x+100}{95}-\dfrac{x+100}{51}=0\)

\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{35}-\dfrac{1}{97}-\dfrac{1}{35}-\dfrac{1}{51}\right)=0\)

\(\Leftrightarrow x+100=0\Leftrightarrow x=-100\)

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