2x + 11 = 3(x - 9)

=> 2x + 11 = 3x - 27

=> 2x - 3x = -11 - 27

=> -x = -38

=> x = 38

=>3x-2x=27+11

=>x=38

x= 38

còn giải thì có người giải rùi mk rảnh

2x + 27 = -11

2x = -11 - 27

2x = -38

x = -19

Vậy x = -19

2x + 27 = -11.

2x = (-11) - 27

2x = (-11) + (-27)

2x = (-38)

=> x = (-38) : 2

=> x = -19.

x^3+27-[11x-2x^2+33-6x]

x^3+27-11x+2x^2-33+6x

x^3+2x^2-5x-6

Phân tích thành nhân tử hả

\(x^3+27-\left(x+3\right)\left(11-2x\right)\)

\(=x^3+3^3-\left(x+3\right)\left(11-2x\right)\)

\(=\left(x+3\right)\left(x^2-3x+9\right)-\left(x+3\right)\left(11-2x\right)\)

\(=\left(x+3\right)\left(x^2-3x+9-11+2x\right)\)

\(=\left(x+3\right)\left(x^2-x-2\right)\)

\(=\left(x+3\right)\left(x^2-2x+x-2\right)\)

\(=\left(x+3\right)\left(x-2\right)\left(x+1\right)\)

\(3^{2x}.27=3^{11}\)

 \(3^{2x}.3^3=3^{11}\)

 \(3^{2x+3}=3^{11}\)

\(2x+3=11\)

\(2x=11-3\)

\(2x=8\)

\(x=4\)

3^2x . 27 = 3¹¹

=> 3^2x.3³ = 3¹¹

=> 3^{2x + 3} = 3¹¹

=>  2x + 3 = 11

=>  2x       = 11 - 3

=> 2x        = 8

=>   x        = 8 : 2

=>   x        = 4

\(3^{2x}.27=3^{11}\)

\(3^{2x}.3^3=3^{11}\)

\(3^{2x}=3^{11}:3^3\)

\(3^{2x}=3^8\)

\(2x=8\Leftrightarrow x=8:2=4\)

a) 12+(2x-11)=53

(2x-11) = 53-12

2x-11= 41

2x=41+11

2x=52

x= 52:2

x=26

Vậy...

\(b,21-\left(-6+3x\right)=9\)

\(\Rightarrow21+6-3x=9\)

\(\Rightarrow27-3x=9\)

\(\Rightarrow3x=18\)

\(\Rightarrow x=6\)

c, -(2x+4)+11=-27

=>-2x-4+11=-27

=>-2x+7=-27

=>-2x = -34

=>x=17

d, 33-(33-x)=0

=>33-33+x=0

=>x=0

a) 33^x:11^x-1=80

3^x=81

3^x=3⁴

x⁴

b) 81^2x.27^x=9¹¹

(3⁴)^2x.(3³)^x=(3²)¹¹

3^8x.3^3x=3²²

3^8x+3x=3²²

3^11.x=3²²

11.x=22

x=2