\(\dfrac{x^2}{6}=\dfrac{24}{25}\)

\(\Leftrightarrow x^2=\dfrac{144}{25}\)

hay \(x\in\left\{\dfrac{12}{5};-\dfrac{12}{5}\right\}\)

⇔x2=14425⇔�2=14425

hay 

\(\dfrac{x^2}{6}=\dfrac{24}{25}\)

\(\Rightarrow x^2=\dfrac{24.6}{25}=\dfrac{144}{25}\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)

a) ĐKXĐ: \(x\ne-5\)

\(\Leftrightarrow7x-7=6x+30\\ \Leftrightarrow x=37\)

b) \(\Leftrightarrow25x^2=144\\ \Leftrightarrow x^2=\dfrac{144}{25}\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)

\(\left(x-1\right)7=\left(x+5\right)6\Leftrightarrow7x-7-6x-30=0\Leftrightarrow x=37\)

\(25x^2=24\cdot6\Leftrightarrow25x^2=144\Leftrightarrow\left(5x\right)^2=\left(12\right)^2\Leftrightarrow x=2,4\)

a) x=37
b) x=+- 12/5
bạn nhé

\(\frac{x^2}{6}=\frac{24}{25}\)

=> x².25 = 6 . 24

=> x² . 25 = 144

=> x² = 144 : 25

=> x² = 5,76 = 2,4² = (-2,4)²

=> x \(\in\){2,4 ; -2,4}

\(\frac{x^2}{6}=\frac{24}{25}\Rightarrow25x^2=24.6\Rightarrow25x^2=144\Rightarrow x^2=\frac{144}{25}=\left(\frac{12}{5}\right)^2=\left(-\frac{12}{5}\right)^2\)

=> x = 12/5 hoặc x = -12/5

\(\frac{x^2}{6}=\frac{24}{25}\)

\(\Rightarrow x^2.25=24.6\)

\(\Rightarrow x^2.25=144\)

\(\Rightarrow x^2=5,76\)

\(\Rightarrow x=2,4\)

Bài 1

a) \(5\times72\times10\times2=\left(5\times2\times10\right)\times72=100\times72=7200\) 

b) \(40\times125=5\times\left(8\times125\right)=5\times1000=5000\) 

c) \(16\times6\times25=4\times4\times6\times25=\left(4\times6\right)\times\left(4\times25\right)=24\times100=2400\) Bài 2:

a) \(24\times57+43\times24=24\times\left(57+43\right)=24\times100=2400\) 

b) \(12\times19+80\times12+12=12\times\left(19+80+1\right)=12\times100=1200\) 

c) \(\left(36\times15\times169\right)\div\left(5\times18\times13\right)\) 

 \(=\left(18\times2\times3\times5\times13\times13\right)\div\left(5\times18\times13\right)\) 

\(=\left(2\times3\times13\right)\times\left(18\times5\times13\right)\div\left(5\times18\times13\right)\) 

\(=2\times3\times13\)

\(=78\)

d) \(\left(44\times52\times60\right)\div\left(11\times13\times15\right)\) 

\(=\left(4\times11\times4\times13\times4\times15\right)\div\left(11\times13\times15\right)\)

\(=\left(4\times4\times4\right)\times\left(11\times13\times15\right)\div\left(11\times13\times15\right)\)

\(=4\times4\times4\)

\(=64\)

Bài 3:

a) \(x-280\div35=5\times54\) 

                \(x-8=270\) 

                      \(x=270+8\) 

                      \(x=278\) 

b) \(\left(x-280\right)\div35=54\div4\) 

    \(\left(x-280\right)\div35=\dfrac{27}{2}\) 

               \(x-280=\dfrac{27}{2}\times35\) 

                \(x-280=\dfrac{945}{2}\) 

                          \(x=\dfrac{945}{2}+280\) 

                          \(x=\dfrac{1505}{2}\) 

c) \(\left(x-128+20\right)\div192=0\) 

                 \(x-128+20=0\times192\) 

                \(x-128+20=0\) 

                        \(x-128=0-20\) 

                        \(x-128=-20\)

                                  \(x=-20+128\) 

                                 \(x=108\) 

d) \(4\times\left(x+200\right)=460+85\times4\) 

    \(4\times\left(x+200\right)=460+340\) 

    \(4\times\left(x+200\right)=800\) 

             \(x+200=800\div4\) 

             \(x+200=200\) 

                      \(x=200-200\) 

                      \(x=0\) 

Bài 4:

a) \(\dfrac{7}{12}-\dfrac{5}{12}=\dfrac{2}{12}=\dfrac{1}{6}\) 

b) \(\dfrac{8}{11}+\dfrac{19}{11}=\dfrac{27}{11}\) 

c) \(\dfrac{3}{8}+\dfrac{5}{12}=\dfrac{9}{24}+\dfrac{10}{24}=\dfrac{19}{24}\) 

d) \(\dfrac{3}{4}+\dfrac{7}{12}=\dfrac{9}{12}+\dfrac{7}{12}=\dfrac{16}{12}=\dfrac{4}{3}\) 

Bài 5:

a) \(x-\dfrac{6}{7}=\dfrac{5}{2}\) 

           \(x=\dfrac{5}{2}+\dfrac{6}{7}\) 

           \(x=\dfrac{47}{14}\) 

b) \(\dfrac{12}{7}\div x+\dfrac{2}{3}=\dfrac{7}{5}\) 

            \(\dfrac{12}{7}\div x=\dfrac{7}{5}-\dfrac{2}{3}\) 

             \(\dfrac{12}{7}\div x=\dfrac{11}{15}\) 

                       \(x=\dfrac{12}{7}\div\dfrac{11}{15}\) 

                        \(x=\dfrac{180}{77}\)

\(\left(\dfrac{135}{2371}+\dfrac{24}{25}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{6}\right)\)

\(=\left(\dfrac{135}{2371}+\dfrac{24}{25}\right)\times\left(\dfrac{3}{6}-\dfrac{2}{6}-\dfrac{1}{6}\right)\)

\(=\left(\dfrac{135}{2371}+\dfrac{24}{25}\right)\times0=0\)

lm tui cứ tưởng dấu nhân thành x:))