\(A=20\times21+21\times22+...+99\times100\)

\(3\times A=20\times21\times\left(22-19\right)+21\times22\times\left(23-20\right)+...+99\times100\times\left(101-98\right)\)

\(=20\times21\times22-19\times20\times21+...+99\times100\times101-98\times99\times100\)

\(=99\times100\times101-19\times20\times21\)

Suy ra \(A=\frac{99\times100\times101-19\times20\times21}{3}=360640\)

\(B=3\times4\times5+4\times5\times6+...+98\times99\times100\)

\(4\times B=3\times4\times5\times\left(6-2\right)+4\times5\times6\times\left(7-3\right)+...+98\times99\times100\times\left(101-97\right)\)

\(=3\times4\times5\times6-2\times3\times4\times5+...+98\times99\times100\times101-97\times98\times99\times100\)

\(=98\times99\times100\times101-2\times3\times4\times5\)

Suy ra \(B=\frac{98\times99\times100\times101-2\times3\times4\times5}{4}=24497520\)

Bài 1: 

a: Tổng là:

(-19+19)+(-18+18)+...+20=20

b: Tổng là:

-18+(-17+17)+...+0=-18

Ai biết chỉ mình nha 

1. 11(x-9)=77

x-9=7

x=16

2. 4(x-3)=48

x-3=12

x=15

3.3(x-8)=81

(x-8)=27

x=35

\(40-21:\left(2.x+3\right)=33\)

\(21:\left(2.x+3\right)=40-33\)

\(21:\left(2.x+3\right)=7\)

\(\left(2.x+3\right)=21:7\)

\(\left(2.x+3\right)=3\)

\(2.x=3-3\)

\(2.x=0\)

\(x=0:2\)

\(x=0\)

\(\text{1: 1+(-2)+3+(-4)+........+19+(-20)}\)

\(\text{=1-2+3-4+.....+19-20}\)

\(\text{=-1+(-1)+..........+(-1)}\)

\(\text{=-1.(20-1)+1:2}\)

\(\text{=-1.10}\)

\(=-10\)

\(\text{2: 1- 2 +3 -4+......+99 - 100}\)

\(\text{=( 1- 2) +(3 -4)+......+(99 - 100)}\)

\(\text{=-1+(-1)+.....+(-1)}\)

\(\text{=-1.(100-1)+1:2}\\ \text{=-1.50}\)

\(=-50\)

\(\text{3: 2 - 4+6 - 8+.....+48 - 50}\\ \text{=(2 - 4)+(6 - 8)+.....+(48 - 50)}\\ \text{=-2+(-2)+......+(-2)}\\ \text{=-2.(50-2):2+1}\\ \text{=-2.25}\\ =-50\)

\(\text{4: -1 + 3 - 5 +7 -.....+97 - 99}\\ \text{=-1 +(3-5)+(7-9)+.......+(97-99)}\\ \text{=-1+(-2)+(-2)+........+(-2)}\\ \text{=-1+[(-2).(99-3):2+1]}\\ \text{=-1+[(-2).49]}\\ \text{=-1+(-98)}\\ =-99\)

\(\text{5: 1 + 2 – 3 – 4 + . . . . + 97 + 98 – 99 – 100}\)

\(\text{=1−2+3−4+5−6+...+99−100}\)

\(\text{=(1−2)+(3−4)+(5−6)+...+(99−100) }\)

\(\text{=(−1)+(−1)+(−1)+...+(−1)}\)

\(\text{=(−1).50}\)

\(\text{=−50}\)

1/ 1 + (-2) + 3 + (-4) + . . . + 19 + (-20)

=(1-2)+(3-4)+..........+(19-20)

=-1+(-1)+.......+(-1)

=-1.[(20-1)+1:2]

=-1.10

=-10

2/ 1 – 2 + 3 – 4 + . . . + 99 – 100

=-1+(-1)+....+(-1)

=-1.[(100-1)+1:2]

=-1.50

=-50

3/ 2 – 4 + 6 – 8 + . . . + 48 – 50

=-2+(-2)+.......+(-2)

=-2.[(50-2):2]:2

=-2.12

=-24

=-2.

C1 : lần trước mình giải 

C2 : mình không chắc thử xem 

thay x= 9 vao F ta có

F = 9^14 - 10 .9^13 + 10.9^12 - 10 .9^11 + ... +10.9^2 -10.9 + 10

  = 9^14 - ( 9 + 1 ) . 9^13 + (9+1). 9^12+..+(9+1) .9^2 - (9+1)9 +10

 = 9^14 - 9^14 - 9^13 + 9^13 + 9^12 -.....+9^3 + 9^2 - 9^2 -   9 + 10 = 1

Tương tự vói G , H 

kho

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