1/2-(-2/5)+1/3+5/7-(-1/6)+(-4/35)+1/41
Những câu hỏi liên quan
1/2+-2/5+1/3+5/7- -1/6+-4/35+1/41
11 tháng 2 2022 lúc 15:01
tính hợp lí : 1/2+2/5+1/3+5/7+1/6+(-4)/35+1/41
\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}+\dfrac{-4}{35}+\dfrac{5}{7}\right)+\dfrac{1}{41}=1+1+\dfrac{1}{41}=\dfrac{83}{41}\)
Đúng 1
Bình luận (0)
Tính bằng cách hợp lý nhất : a) -2/3+(-1)/5+3/4-5/6-7/10 b) 0,5+1/3+0,4+5/7+1/6-4/35 c) 1/3+(-1)/5-(-1)/4-7/9-(-5)/12+(-1)/45+1/41
a. \(\dfrac{-2}{3}+\dfrac{-1}{5}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)
= \(\dfrac{-4}{6}+\dfrac{-2}{10}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)
= \(\dfrac{-3}{2}+\dfrac{1}{2}+\dfrac{3}{4}\)
= (-1) + \(\dfrac{3}{4}\)
= \(\dfrac{-4}{4}+\dfrac{3}{4}\)
= \(\dfrac{-1}{4}\)
Đúng 3
Bình luận (0)
b; 0,5 + \(\dfrac{1}{3}\) + 0,4 + \(\dfrac{5}{7}\) + \(\dfrac{1}{6}\) - \(\dfrac{4}{35}\)
= (\(\dfrac{1}{3}\)+ \(\dfrac{1}{6}\) + \(\dfrac{1}{2}\)) + (\(\dfrac{5}{7}\)- \(\dfrac{4}{35}\)+ \(\dfrac{2}{5}\))
= ( \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\)) + (\(\dfrac{3}{5}\) + \(\dfrac{2}{5}\))
= 1 + 1
= 2
Đúng 0
Bình luận (0)
c; \(\dfrac{1}{3}\) + \(\dfrac{-1}{5}\) - \(\dfrac{-1}{4}\) - \(\dfrac{7}{9}\)- \(\dfrac{-5}{12}\) + \(\dfrac{-1}{45}\) + \(\dfrac{1}{41}\)
= (\(\dfrac{1}{3}\) + \(\dfrac{1}{4}\) + \(\dfrac{5}{12}\)) - (\(\dfrac{1}{5}\) + \(\dfrac{7}{9}\) + \(\dfrac{1}{45}\)) + \(\dfrac{1}{41}\)
= (\(\dfrac{4}{12}\) + \(\dfrac{3}{12}\) + \(\dfrac{5}{12}\)) - (\(\dfrac{9}{45}+\dfrac{35}{45}\) + \(\dfrac{1}{45}\)) + \(\dfrac{1}{41}\)
= (\(\dfrac{7}{12}\) + \(\dfrac{5}{12}\)) - (\(\dfrac{44}{45}\) + \(\dfrac{1}{45}\)) + \(\dfrac{1}{41}\)
= 1 - 1 + \(\dfrac{1}{41}\)
= 0 + \(\dfrac{1}{41}\)
= \(\dfrac{1}{41}\)
Đúng 0
Bình luận (0)
Tính
a, (-2/3) + 3/4 -(-1/6)+(-2/5)
b, (-2/3) +(-1/5)+ 3/4 - 5/6- (-7/10)
c, 1/2 - (-2/5)+1/3+5/7-(01/6)+(-4/35) +1/41
d, (1/100.99) - (1/99.98)-(1/98.97)-...-(1,3.2)- (1/2.1)
\(\dfrac{1}{2}-\dfrac{-2}{5}+\dfrac{1}{3}+\dfrac{5}{7}-\dfrac{-1}{6}+\dfrac{-4}{35}-\dfrac{1}{41}\)
\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}-\dfrac{4}{35}+\dfrac{5}{7}\right)-\dfrac{1}{41}=-\dfrac{1}{41}\)
Đúng 1
Bình luận (0)
\(\dfrac{1}{2}-\dfrac{-2}{5}+\dfrac{1}{3}+\dfrac{5}{7}-\dfrac{-1}{6}+\dfrac{-4}{35}-\dfrac{1}{41}\)
\(=\dfrac{1}{2}+\dfrac{2}{5}+\dfrac{1}{3}+\dfrac{5}{7}+\dfrac{1}{6}+\dfrac{-4}{35}+\dfrac{-1}{41}\)
\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}+\dfrac{5}{7}+\dfrac{-4}{35}\right)+\dfrac{-1}{41}\)
\(=1+1+\dfrac{-1}{41}\)
\(=2+\dfrac{-1}{41}=\dfrac{81}{41}\)
Đúng 2
Bình luận (0)
1. THỰC HIỆN PHÉP TÍNH :
a) -2/3+3/4--1/6+-2/5 ;
b) -2/3+-1/5+3/4-5/6- -7/10 ;
c)1/2- -2/5+1/3+5/7- -1/6+-4/35+1/41 ;
d) 1/100.99-1/99.98-1/98.97-...-1/3.2-1/2.1
tính a= -(-3/2) -2/5+(-1/6)-(-2011/2012)+-(1/3)-41/35-(-4/7)
a) 1/2 - (- 2/5) + 1/3 + 5/7 - (- 1/6) + (- 4/35) + 1/41
b) 1/ 100.99 - 1/ 99.98 - 1/ 98.97 - ..... - 1/ 3.2 - 1/ 2.1
b) \(\dfrac{1}{100.99}-\dfrac{1}{99.98}-\dfrac{1}{98.97}-...-\dfrac{1}{3.2}-\dfrac{1}{2.1}\)
\(=\dfrac{1}{100.99}-\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{97.98}+\dfrac{1}{98.99}\right)\)
\(=\dfrac{1}{100.99}-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{97}-\dfrac{1}{98}+\dfrac{1}{98}-\dfrac{1}{99}\right)\)
\(=\dfrac{1}{100.99}-\left(1-\dfrac{1}{99}\right)\)
\(=\dfrac{1}{100.99}-\dfrac{98}{99}=-\dfrac{9799}{9900}\)
Đúng 0
Bình luận (0)
1/2+2/5+1/3+5/7+1/6+(-4/35)+1/41
đổi ra rồi nha bạn thế là tự biết làm được rồi
Đúng 0
Bình luận (0)
Cần gấp mấy bn ơi:>>>
a,-2/3+3/4--1/6+-2/5
b,-2/3+-1/5=3/4-5/6- (-7/6)
c,1/2-(-2/5)+1/3+5/7-(-1/6)+(-4/35)+1/41
d,1/100.99-1/99.98-1/98.97-.....-1/3.2-1/2.1