25 + 14 = ??
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Biểu thức thu gọn của biểu thức 14−(25−x)+(−14+50)14−(25−x)+(−14+50) là
Ta có : \(14-\left(25-x\right)+\left(-14+50\right).14-\left(25-x\right)+\left(-14+50\right)\)
\(=14-25+x+36.14-25+x-14+50\)
\(=2x+36.14=2x+504\)
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14−(25−x)+(−14+50).14−(25−x)+(−14+50)14−(25−x)+(−14+50).14−(25−x)+(−14+50)
=14−25+x+36.14−25+x−14+50=14−25+x+36.14−25+x−14+50
=2x+36.14=2x+504
Hok tốt!
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Giải:
\(14-\left(25-x\right)+\left(-14+50\right).14-\left(25-x\right)+\left(-14+50\right)\)
\(=14-25+x+\left(-14.14+50.14\right)-25+x-14+50\)
\(=\left(14-14\right)+\left(-25-25+50\right)+\left(x+x\right)+\left(-196+700\right)\)
\(=0+0+2x+504\)
\(=2x+504\)
Chúc bạn học tốt!
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a) 2019/2020 x 4/11 + 2019/2020 x 5/11 + 2019/2020 x 2/11
b) 17/14 x 25/27 - 1/14 x 25/27 - 2/14 x 25/27
\(a.=\dfrac{2019}{2020}\times\left(\dfrac{4}{11}+\dfrac{5}{11}+\dfrac{2}{11}\right)\\ =\dfrac{2019}{2020}\times1=\dfrac{2019}{2020}\\ b.=\dfrac{25}{27}\times\left(\dfrac{17}{14}-\dfrac{1}{14}-\dfrac{2}{14}\right)\\ =\dfrac{25}{27}\times1=\dfrac{25}{27}\)
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-(3)/(14)+-(12)/(25)*-(3)/(14)+(-(3)/(14))^(1)
Lời giải:
\(\frac{-3}{14}+\frac{-12}{25}.\frac{-3}{14}+(\frac{-3}{14})^1\\
=\frac{-3}{14}+\frac{-12}{25}.\frac{-3}{14}+\frac{-3}{14}\\
=\frac{-3}{14}(1+\frac{-12}{25}+1)=\frac{-3}{14}.\frac{38}{25}=\frac{-57}{175}\)
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Tính nhanh a) 25/4*9 + 25/9*14 + 25/14*19 +...+ 25/2004*2009
b) 20,07:0,2+20,07*91+20,07:0,25
c) 50,08*34 - 536,46 + 50,08 * 66 - 436,54
\(\text{Ta có : }\)\(\frac{25}{4.9}+\frac{25}{9.14}+\frac{25}{14.19}+......+\frac{25}{2004.2009}\)
\(=5.\left(\frac{5}{4.9}+\frac{5}{9.14}+\frac{5}{14.19}+......+\frac{5}{2004.2009}\right)\)
\(=5\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+......+\frac{1}{2004}-\frac{1}{2009}\right)\)
\(=5\left(\frac{1}{4}-\frac{1}{2009}\right)\)
\(=5.\frac{2005}{8036}=\frac{10025}{8036}\)
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Tính hợp lí nhất
1, 2155– (174 + 2155) + (-68 + 174)
2, -25 . 72 + 25 . 21 – 49 . 25
3, 35(14 –23) – 23(14–35)
4, 8154– (674 + 8154) + (–98 + 674) 5, – 25 . 21 + 25 . 72 + 49 . 25
6, 27(13 – 16) – 16(13 – 27)
7, –1911 – (1234 – 1911)
8, 156.72 + 28.156
9, 32.( -39) + 16.( –22)
10, –1945 – ( 567– 1945) ...
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Tính hợp lí nhất
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1, 2155– (174 + 2155) + (-68 + 174) 2, -25 . 72 + 25 . 21 – 49 . 25 3, 35(14 –23) – 23(14–35) 4, 8154– (674 + 8154) + (–98 + 674) 5, – 25 . 21 + 25 . 72 + 49 . 25 6, 27(13 – 16) – 16(13 – 27)
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7, –1911 – (1234 – 1911) 8, 156.72 + 28.156 9, 32.( -39) + 16.( –22) 10, –1945 – ( 567– 1945) 11, 184.33 + 67.184 12, 44.( –36) + 22.( –28)
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1) \( 2155 – (174 + 2155) + (-68 + 174) = -68\) 2) \(-25 . 72 + 25 . 21 – 49 . 25=-2500\) 3) \(35.(14 –23) – 23.(14–35)=168\) 4) \(8154 – (674 + 8154) + (–98 + 674)=-98\) 5) \(25.21+25.72+49.25=2399\) 6) \(27.(13-16)-16.(13-27)=143\) 7) \(–1911 – (1234 – 1911) =-1234\) |
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x2- 14/260 - 14/416 - ... - 14/19400 = 1/25
x2- 14/260 - 14/416 - ... - 14/19400 = 1/25
x^2 - 14/260-14/416-...-14/19400=1/25
x + (x+1) + (x+2) + (x+3) + .... + 13 + 14 = 14
25 + 24 + 23 +...+ x + (x - 2) + (x – 3) = 25
Tính một cách hợp lí.
a) \(A=\dfrac{-3}{14}+\dfrac{2}{13}+\dfrac{-25}{14}+\dfrac{-15}{13};\)
b) \(B=\dfrac{5}{3}\cdot\dfrac{7}{25}+\dfrac{5}{3}\cdot\dfrac{21}{25}-\dfrac{5}{3}\cdot\dfrac{7}{25}\).
a, \(\begin{array}{l}A = \dfrac{{ - 3}}{{14}} + \dfrac{2}{{13}} + \dfrac{{ - 25}}{{14}} + \dfrac{{ - 15}}{{13}}\\A = \left( {\dfrac{{ - 3}}{{14}} + \dfrac{{ - 25}}{{14}}} \right) + \left( {\dfrac{2}{{13}} + \dfrac{{ - 15}}{{13}}} \right)\\A = \dfrac{{ - 3 + \left( { - 25} \right)}}{{14}} + \dfrac{{2 + \left( { - 15} \right)}}{{13}}\\A = \dfrac{{ - 28}}{{14}} + \dfrac{{ - 13}}{{13}}\\A = - 2 + (-1)\\A = - 3\end{array}\)
b,
Cách 1:
\(\begin{array}{l}B = \dfrac{5}{3}.\dfrac{7}{{25}} + \dfrac{5}{3}.\dfrac{{21}}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}\\B = \left( {\dfrac{5}{3}.\dfrac{7}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}} \right) + \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = 0 + \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = \dfrac{{5.21}}{{3.25}}\\B = \dfrac{7}{5}\end{array}\)
Cách 2:
\(B = \dfrac{5}{3}.\dfrac{7}{{25}} + \dfrac{5}{3}.\dfrac{{21}}{{25}} - \dfrac{5}{3}.\dfrac{7}{{25}}\\B = \dfrac{5}{3}.({\dfrac{7}{{25}} -\dfrac{7}{{25}} + \dfrac{{21}}{{25}}})\\B = \dfrac{5}{3}.\dfrac{{21}}{{25}}\\B = \dfrac{{5.21}}{{3.25}}\\B = \dfrac{7}{5}\)
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