325.(37+45)-63.(-325)+45.(-225)

=325.37+325.45+63.325+45.(-225)

=325.(37+63)+45.(325-225)

=325.100+45.100

=100.(325+45)

=100.370

=37000

mình chắc là nó đúng

cho mik hỏi sao 45*(-225)=45*(325-225)vậy

\(325\left(37+45\right)-63\left(-325\right)+45\left(-225\right)\)

\(=325\cdot37+325\cdot45+63\cdot325-45\cdot225\)

\(=325\left(37+63\right)+45\left(325-225\right)\\ =325\cdot100+45\cdot100\\ =100\left(325+45\right)\\ =100\cdot370\\ =37000\)

b)\(\dfrac{45^2.40^2.18^2}{180^2}=\dfrac{45^2.4.10.4.10.18.18}{180^2}=\dfrac{45^2.4.4.180.180}{180^{20}}=\dfrac{45^2.16}{ }\)

a) \(\left(45x105-225\right)-\left(210+42x95\right)\)

\(=45x\left(100+5\right)-225-210+42x\left(100-5\right)\)

\(=4500+45x5-225-210+4200-42x5\)

\(=4500+4200+45x5-42x5-225-210\)

\(=8700+5x\left(45-42\right)-435\)

\(=8700+15-435=8280\)

a: =45*105-225-210-42*95

=45*(105-5)-42(95+5)

=100*3

=300

b: =47(105-5)-42(96+4)

=47*100-42*100

=5*100

=500

b) \(\left(47x105-235\right)-\left(168+42x96\right)\)

\(=47x\left(100+5\right)-235-168-42x\left(100-4\right)\)

\(=4700+235-235-168-4200-168\)

\(=4700-4200+235-235-168-168\)

\(=500\)

    -5 + (-37 - 45 + 51) - (-37 + 51)

=  -5  - 37 - 45 + 51 + 37 - 51

=  - (5 + 45) - (37 - 37) + (51 - 51)

= - 50 - 0 + 0

= - 50

  - (15 - 47 + 58) + (15 - 47 ) + 3

= - 15 + 47 - 58 + 15 - 47 + 3

= (-15 + 15) + (47 - 47) - (58 - 3)

= 0 + 0 - 55

= - 55

  (53 - 45 - 49) - (53 + 45 - 49)

= 53 -  45 - 49 - 53 - 45 + 49

= (53 - 53) + (-49 + 49) - (45 + 45)

= 0 + 0 - 90

= - 90 

    13 - 15 + 49 - 13 + 15 - 48

=  (13 - 13) + (-15 + 15) + (49 - 48)

= 0 + 0 + 1

=  1 

15+13 -15-13 +49-48

a) = \(\left(\dfrac{2}{7}+\dfrac{4}{7}+\dfrac{1}{7}\right):\dfrac{27}{31}\)

= \(\dfrac{7}{7}\) x \(\dfrac{31}{27}\)

= 1 x \(\dfrac{31}{27}\) = \(\dfrac{31}{27}\)

b) = \(\left(\dfrac{23}{45}:\dfrac{23}{45}\right)\)x \(\dfrac{17}{51}\)

= 1 x \(\dfrac{17}{51}\)= \(\dfrac{17}{51}\)

\(37x2+325:5-172\)

\(=74+65-172\)

\(=74+26+39-100-39-33\)

\(=100-100+39-39-33\)

\(=-33\)

Ư(26)={1;2;13;26}

Ư(39)={1;3;13;39}

Ư(64)={1;2;4;8;16;32;64}

Ư(12)={1;2;3;4;12}

Ư(45)={3;5;9;15;45}

\(Ư\left(26\right)=\left\{1;-1;2;-2;13;-13;21;-26\right\}\)

\(Ư\left(39\right)=\left\{1;-1;3;-3;13;-13;39;-39\right\}\)

\(Ư\left(64\right)=\left\{1;-1;2;-2;4;-4;8;-8;16;-16;32;-32;64;-64\right\}\)

\(Ư\left(12\right)=\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)

\(Ư\left(45\right)=\left\{1;-1;3;-3;5;-5;9;-9;15;-15;45;-45\right\}\)