\(\dfrac{2010}{2011}+\dfrac{2011}{2012}+\dfrac{2012}{2013}+\dfrac{2013}{2011}\)

=1-\(\dfrac{1}{2011}\)+1\(-\dfrac{1}{2012}\)+1-\(\dfrac{1}{2013}\)+1-\(\dfrac{1}{2011}\)

=4-(\(\dfrac{2}{2011}+\dfrac{1}{2012}+\dfrac{1}{2013}\)) < 4 

m=\(\dfrac{2010}{2011}+\dfrac{2011}{2012}+\dfrac{2012}{2013}+\dfrac{2013}{2011}\)

=\(1-\dfrac{1}{2011}+1-\dfrac{1}{2012}+1-\dfrac{1}{2013}+1+\dfrac{2}{2011}\)

=4+\(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}\)

vì:

do \(\dfrac{1}{2011}< 1\)

\(\dfrac{1}{2012}< 1\)

\(\dfrac{1}{2013}< 1\)

nên \(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 1-1-1=-1\)

hay \(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 0\)

nên 4+\(\dfrac{1}{2011}-\dfrac{1}{2012}-\dfrac{1}{2013}< 4\)

vậy tổng m <4

bài này mình tưởng phải lên cấp 2 mới có thế mà mấy em lớp 4 đã phải làm á

Ta có : \(\frac{2011}{2012}=1-\frac{1}{2012}\)

           \(\frac{2012}{2013}=1-\frac{1}{2013}\)

            \(\frac{2013}{2011}=1+\frac{2}{2011}\)

Ta có : \(\frac{2011}{2012}+\frac{2012}{2013}+\frac{2013}{2011}=\left(1-\frac{1}{2012}\right)+\left(1-\frac{1}{2013}\right)+\left(1+\frac{2}{2011}\right)\)

       =   \(\left(1+1+1\right)+\left(\frac{2}{2011}-\frac{1}{2012}-\frac{1}{2013}\right)\)

       =  \(3+\frac{2}{2011}-\left(\frac{1}{2012}+\frac{1}{2013}\right)\)

Ta có :  

\(\frac{1}{2012}+\frac{1}{2013}< \frac{1}{2012}+\frac{1}{2012}=\frac{2}{2012}\)

mà : \(\frac{2}{2012}< \frac{2}{2011}=>\frac{1}{2012}+\frac{1}{2013}< \frac{2}{2011}\)

=> \(\frac{2}{2011}-\left(\frac{1}{2012}+\frac{1}{2013}\right)>0\)

Vậy : \(3+\frac{2}{2011}-\left(\frac{1}{2012}+\frac{1}{2013}\right)>3\)

Vậy : \(\frac{2011}{2012}+\frac{2012}{2013}+\frac{2013}{2011}>3\)

ủng hộ mik nhá các bạn ơiii ^_^"

\(\frac{2010+2011+2012}{2011+2012+2013}=\frac{2010}{2011+2012+2013}+\frac{2011}{2011+2012+2013}+\frac{2012}{2011+2012+2013}\)

Vì \(\frac{2010}{2011+2012+2013}<\frac{2010}{2011};\frac{2011}{2011+2012+2013}<\frac{2011}{2012};\frac{2012}{2011+2012+2013}<\frac{2012}{2013}\)

nên phép dưới nhỏ hơn phép trên

Ta có :

B = \(\dfrac{2011}{2012}\) + \(\dfrac{2012}{2013}\) .

       \(\dfrac{2011}{2012}\) > \(\dfrac{2011}{2012+2013}\) .

        \(\dfrac{2012}{2013}\) > \(\dfrac{2012}{2012+2013}\) .

\(\Rightarrow\) A < B .

Ta có :

B = 2012201320122013 .

       20112012+201320112012+2013 .

        20122012+201320122012+2013 .

 A < B .

Giải:

Ta có:

\(A=\dfrac{2011+2012}{2012+2013}\) 

\(A=\dfrac{2011}{2012+2013}+\dfrac{2012}{2012+2013}\) 

Vì \(\dfrac{2011}{2012}>\dfrac{2011}{2012+2013}\)  

\(\dfrac{2012}{2013}>\dfrac{2012}{2012+2013}\)

\(\Rightarrow A< B\)

Câu trả lời:A<B

M<4 :)

với cả đây là bài lớp 5

m bé hơn 4

mà giờ lớp 4 học khó nhở

M=2010/2011+2011/2012+2012/2013+2013/2014
4 = 1+1+1+1
Mà 2010/2011 <1
2011/2012<1
2012/2013<1
2013/2014 <1
=>2010/2011+2011/2012+2012/2013+2013/2014​ < 1+1+1+1 
=> M<4

tích cho chị zới nha

bạn tham khảo:

2010/2011+2012+2013 > 2010+2011+2012/2011+2012+2013

2011/2011+2012+2013 > 2010+2011+2012/2011+2012+2013

2012/2011+2012+2013 > 2010+2011+2012/2011+2012+2013

=> 2010/2011+2011/2012+2012/2013 > 2010+2011+2012/2011+2012+2013

2010/2011+2012+2013 > 2010+2011+2012/2011+2012+2013

2011/2011+2012+2013 > 2010+2011+2012/2011+2012+2013

2012/2011+2012+2013 > 2010+2011+2012/2011+2012+2013

=> 2010/2011+2011/2012+2012/2013 > 2010+2011+2012/2011+2012+2013

\(\overline{ }\)

Ta thấy 

\(\dfrac{2010}{2011}< 1\)

\(\dfrac{2011}{2012}< 1\)

\(\dfrac{2012}{2013}< 1\)

\(\dfrac{2013}{2014}< 1\) 

=> Tổng M của những phân số trên sẽ nhỏ hơn 1 

=> M < 1