\(\dfrac{4}{3}:0,8=\dfrac{2}{3}:\left(0,1.x\right)\)
\(|x|=-1,2\)
(-2,5) . (-4) . (-7,9)
(-0,375) . \(\dfrac{13}{3}\). (-2)3
Những câu hỏi liên quan
Tính bằng máy tính CASIO:
\(A=\dfrac{\left(1986^2-1992\right).\left(1986^2+3972-3\right).1987}{1983.1985.1987.1989}\)
\(B=26\left[\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6,84:\left(28,57-25,15\right)}\right]+\dfrac{2}{3}:\dfrac{4}{21}\)
TÍNH NHANH
a) dfrac{11}{125}-dfrac{17}{18}-dfrac{5}{7}+dfrac{4}{9}+dfrac{17}{4}
b) 1-dfrac{1}{2}+2-dfrac{2}{3}+3-dfrac{3}{4}+4-dfrac{1}{4}-3-dfrac{1}{3}-2-dfrac{1}{2}-1
c) 26:left{{}begin{matrix}end{matrix}right.dfrac{3:left(0,2-0,1right)}{2,5.left(0,8+1,2right)}+dfrac{left(34,06-33,81right).4}{6,84:left(28,57-25,15right)}+dfrac{2}{3}:dfrac{4}{21}
Các bạn ơi câu c là tới phân số ... 4/...15 là đóng ngoặc nhé. Hai ps đó trong ngoặc đấy
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TÍNH NHANH
a) \(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{4}\)
b) \(1-\dfrac{1}{2}+2-\dfrac{2}{3}+3-\dfrac{3}{4}+4-\dfrac{1}{4}-3-\dfrac{1}{3}-2-\dfrac{1}{2}-1\)
c) \(26:\left\{{}\begin{matrix}\\\end{matrix}\right.\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6,84:\left(28,57-25,15\right)}+\dfrac{2}{3}:\dfrac{4}{21}\)
Các bạn ơi câu c là tới phân số ... 4/...15 là đóng ngoặc nhé. Hai ps đó trong ngoặc đấy
\(\left(\dfrac{-2}{3}\right)^2.x=\left(\dfrac{-2}{3}\right)^5\)
\(\left(x-\dfrac{1}{2}\right)^3=\dfrac{1}{27}\)
\(\left(\dfrac{2}{3}x-1\right)\left(\dfrac{3}{4}x+\dfrac{1}{2}\right)=0\)
\(\dfrac{4}{9}:x=3\dfrac{1}{3}:2,25\)
\(1\dfrac{1}{3}:0,8=\dfrac{2}{3}:0,1x\)
a: \(x=\left(-\dfrac{2}{3}\right)^5:\left(-\dfrac{2}{3}\right)^2=\left(-\dfrac{2}{3}\right)^3=-\dfrac{8}{27}\)
b: =>x-1/2=1/3
=>x=5/6
c: =>2/3x-1=0 hoặc 3/4x+1/2=0
=>x=3/2 hoặc x=-1/2:3/4=-1/2*4/3=-4/6=-2/3
d =>4/9:x=10/3:9/4=10/3*4/9=40/27
=>x=4/9:40/27=4/9*27/40=108/360=3/10
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Tìm x :
1) \(\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}\)
2) \(\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0\)
3) \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
4)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
3: \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
\(\Leftrightarrow\left|x-\dfrac{3}{4}\right|=\dfrac{1}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{2}\\x-\dfrac{3}{4}=-\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{4}\\x=\dfrac{1}{4}\end{matrix}\right.\)
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1) 23dfrac{1}{4}.dfrac{7}{5}-13dfrac{1}{4}:dfrac{5}{7}2) left(1+dfrac{2}{3}-dfrac{1}{4}right)left(0,8-dfrac{3}{4}right)^23) 16dfrac{2}{7}:left(dfrac{-3}{5}right)+28dfrac{2}{7}:dfrac{3}{5}4) left(2^2:dfrac{4}{3}-dfrac{1}{2}right).dfrac{6}{5}-175) left(dfrac{1}{3}right)^{50}.left(-9right)^{25}-dfrac{2}{3}:4
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1) \(23\dfrac{1}{4}.\dfrac{7}{5}-13\dfrac{1}{4}:\dfrac{5}{7}\)
2) \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)\left(0,8-\dfrac{3}{4}\right)^2\)
3) \(16\dfrac{2}{7}:\left(\dfrac{-3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
4) \(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right).\dfrac{6}{5}-17\)
5) \(\left(\dfrac{1}{3}\right)^{50}.\left(-9\right)^{25}-\dfrac{2}{3}:4\)
1: Ta có: \(23\dfrac{1}{4}\cdot\dfrac{7}{5}-13\dfrac{1}{4}:\dfrac{5}{7}\)
\(=\dfrac{93}{4}\cdot\dfrac{7}{5}-\dfrac{53}{4}\cdot\dfrac{7}{5}\)
\(=\dfrac{7}{5}\cdot10=14\)
2: Ta có: \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
\(=\dfrac{12+8-3}{12}\cdot\dfrac{1}{400}\)
\(=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{4800}\)
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Tính nhanh :
a) \(\left(-6,37.0,4\right).2,5\)
b) \(\left(-0,125\right).\left(-5,3\right).8\)
c) \(\left(-2,5\right).\left(-4\right).\left(-7,9\right)\)
d) \(\left(-0,375\right).4\dfrac{1}{3}.\left(-2\right)^3\)
Tính nhanh:
a) (-6,37 × 0,4) × 2,5;
b) (-0,125) × (-5,3) × 8;
c) (-2,5) × (-4) × (-7,9);
d) (-0,375) × 413(−2)3413(−2)3
Hướng dẫn làm bài:
a) (- 6,37 × 0,4) × 2,5
= - 6,37× (0,4 × 2,5)
= - 6,37 × 1 = - 6,37
b) (-0,125) × (-5,3) × 8
= (-0,125 × 8) × (-5,3)
=(-1). (-5,3) = 5,3
c) (-2,5) × (-4) × (-7,9)
= [(-2,5) × (-4)] × (-7,9)
= 10 . (-7,9)
= -79
d) (−0,375).413.(−2)3
=[(−0,375).(−8)].133=[(−0,375).(−8)].133
=3.133=13
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1. Tính ( hợp lý nếu có thể )
a, A dfrac{7,5-0,6+dfrac{3}{7}+dfrac{3}{13}}{2,75-2,2+dfrac{11}{7}+dfrac{11}{3}}
b, B 26 : left[dfrac{3:left(0,2-0,1right)}{2,5.left(0,8+1,2right)}+dfrac{left(34,06-33,81right).4}{6.84:left(28,57-25,15right)}right]+ dfrac{2}{3} : dfrac{4}{21}
c, C left[left(dfrac{2}{193}-dfrac{3}{386}right).dfrac{193}{17}+dfrac{33}{34}right] : left[left(dfrac{7}{2001}+dfrac{11}{4002}right).dfrac{2001}{25}+dfrac{9}{2}right]
d, D dfrac{0.8:left(dfrac{4}{5}.1,25right)}{0.64-df...
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1. Tính ( hợp lý nếu có thể )
a, A = \(\dfrac{7,5-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{3}}\)
b, B = 26 : \(\left[\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6.84:\left(28,57-25,15\right)}\right]\)+ \(\dfrac{2}{3}\) : \(\dfrac{4}{21}\)
c, C = \(\left[\left(\dfrac{2}{193}-\dfrac{3}{386}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]\) : \(\left[\left(\dfrac{7}{2001}+\dfrac{11}{4002}\right).\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
d, D = \(\dfrac{0.8:\left(\dfrac{4}{5}.1,25\right)}{0.64-\dfrac{1}{25}}\) + \(\dfrac{\left(1.08-\dfrac{5}{25}\right):\dfrac{4}{7}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{7}}\) + ( 11,2 . 0,5 ) : \(\dfrac{4}{5}\)
Giúp mk nha chỉ là tính toán thông thường tính ra là đc nhưng mà mk lại khó tính ra nên các bn giúp mk nha
Đây là tính hợp lí ... mà câu a là 27,5 chứ không phải 2,75...
\(A=\dfrac{7,5-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{27,5-2,2+\dfrac{11}{7}+\dfrac{11}{3}}=\dfrac{\dfrac{15}{2}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{13}}{\dfrac{55}{2}-\dfrac{11}{5}+\dfrac{11}{7}+\dfrac{11}{3}}\\ =\dfrac{3\left(\dfrac{5}{2}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}{11\left(\dfrac{5}{2}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}=\dfrac{3}{11}\)
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b: \(=26:\left[\dfrac{3:0.1}{2.5\cdot2}+\dfrac{0.25\cdot4}{2}\right]+\dfrac{2}{3}\cdot\dfrac{21}{4}\)
\(=26:\left[\dfrac{30}{5}+1\right]+\dfrac{42}{12}\)
\(=\dfrac{26}{7}+\dfrac{42}{12}=\dfrac{101}{14}\)
c: \(=\left[\dfrac{4-3}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
\(=\dfrac{\left(\dfrac{1}{34}+\dfrac{33}{34}\right)}{\dfrac{1}{2}+\dfrac{9}{2}}=1:5=\dfrac{1}{5}\)
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Bài 1.(2,5 điểm)Tìm x, biết:a) left(2dfrac{1}{3}+3dfrac{1}{2}right).x-4dfrac{1}{6}+3dfrac{1}{2}b) left(1dfrac{1}{3}+3dfrac{1}{2}right).x4dfrac{1}{6}-3dfrac{1}{2}c) dfrac{1}{3}-dfrac{7}{8}.xdfrac{1}{4}d) dfrac{3}{2}.x+dfrac{1}{7}dfrac{7}{8}.dfrac{64}{49}e) 5dfrac{1}{2}-left(dfrac{1}{4}.x+dfrac{2}{5}right)25%
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Bài 1.(2,5 điểm)Tìm x, biết:
a) \(\left(2\dfrac{1}{3}+3\dfrac{1}{2}\right).x=-4\dfrac{1}{6}+3\dfrac{1}{2}\)
b) \(\left(1\dfrac{1}{3}+3\dfrac{1}{2}\right).x=4\dfrac{1}{6}-3\dfrac{1}{2}\)
c) \(\dfrac{1}{3}-\dfrac{7}{8}.x=\dfrac{1}{4}\)
d) \(\dfrac{3}{2}.x+\dfrac{1}{7}=\dfrac{7}{8}.\dfrac{64}{49}\)
e) \(5\dfrac{1}{2}-\left(\dfrac{1}{4}.x+\dfrac{2}{5}\right)=25\%\)
c: Ta có: \(\dfrac{1}{3}-\dfrac{7}{8}x=\dfrac{1}{4}\)
\(\Leftrightarrow x\cdot\dfrac{7}{8}=\dfrac{1}{12}\)
\(\Leftrightarrow x=\dfrac{1}{12}\cdot\dfrac{8}{7}=\dfrac{2}{21}\)
d: Ta có: \(\dfrac{3}{2}x+\dfrac{1}{7}=\dfrac{7}{8}\cdot\dfrac{64}{49}\)
\(\Leftrightarrow x\cdot\dfrac{3}{2}=1\)
hay \(x=\dfrac{2}{3}\)
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Câu 1)1) dfrac{11}{24}−dfrac{5}{41}+dfrac{13}{24}+0,5−dfrac{36}{41}2)12÷left(dfrac{3}{4}-dfrac{5}{6}right)^23) (1+dfrac{2}{3}-dfrac{1}{4})left(0,8-dfrac{3}{4}right)^2 4)16dfrac{2}{7}÷(dfrac{-3}{5})+28dfrac{2}{7}÷dfrac{3}{5}5)left(2^2divdfrac{4}{3}-dfrac{1}{2}right)timesdfrac{6}{5}-176)left(dfrac{1}{3}right)^{50}timesleft(-9right)^{25}-dfrac{2}{3}div4
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Câu 1)
1) \(\dfrac{11}{24}\)−\(\dfrac{5}{41}\)+\(\dfrac{13}{24}\)+0,5−\(\dfrac{36}{41}\)=
2)12÷\(\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)=
3) (\(1+\dfrac{2}{3}-\dfrac{1}{4}\))\(\left(0,8-\dfrac{3}{4}\right)^2\) =
4)\(16\dfrac{2}{7}\)÷(\(\dfrac{-3}{5}\))+\(28\dfrac{2}{7}\)÷\(\dfrac{3}{5}\)
5)\(\left(2^2\div\dfrac{4}{3}-\dfrac{1}{2}\right)\times\dfrac{6}{5}-17\)
6)\(\left(\dfrac{1}{3}\right)^{50}\times\left(-9\right)^{25}-\dfrac{2}{3}\div4\)
1: \(\dfrac{11}{24}-\dfrac{5}{41}+\dfrac{13}{24}+0,5-\dfrac{36}{41}\)
\(=\left(\dfrac{11}{24}+\dfrac{13}{24}\right)-\left(\dfrac{5}{41}+\dfrac{36}{41}\right)+\dfrac{1}{2}\)
\(=1-1+\dfrac{1}{2}=\dfrac{1}{2}\)
2: \(12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)
\(=12:\left(\dfrac{9}{12}-\dfrac{10}{12}\right)^2\)
\(=12:\left(-\dfrac{1}{12}\right)^2=12:\dfrac{1}{144}=12\cdot144=1368\)
3: \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right)\cdot\left(0,8-\dfrac{3}{4}\right)^2\)
\(=\dfrac{12+8-3}{12}\cdot\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
\(=\dfrac{17}{12}\cdot\left(\dfrac{16-15}{20}\right)^2\)
\(=\dfrac{17}{12}\cdot\dfrac{1}{400}=\dfrac{17}{4800}\)
4: \(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\dfrac{3}{5}\)
\(=\dfrac{5}{3}\cdot\left(-16-\dfrac{2}{7}\right)+\dfrac{5}{3}\cdot\left(28+\dfrac{2}{7}\right)\)
\(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)\)
\(=12\cdot\dfrac{5}{3}=20\)
5: \(\left(2^2:\dfrac{4}{3}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17\)
\(=\dfrac{5}{2}\cdot\dfrac{6}{5}-17=3-17=-14\)
6: \(\left(\dfrac{1}{3}\right)^{50}\cdot\left(-9\right)^{25}-\dfrac{2}{3}:4\)
\(=\left(\dfrac{1}{3}\right)^{50}\cdot\left(-1\right)\cdot3^{50}-\dfrac{2}{3\cdot4}\)
\(=-1-\dfrac{2}{12}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
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