a)   \(18.17-3.6.7\)

\(=18.17-18.7\)

\(=18\left(17-7\right)\)

\(=18.10=180\)

c)   \(33\left(17-5\right)-17.\left(33-5\right)\)

\(=33.17-33.5-17.33+5.17\)

\(=5\left(17-33\right)\)

\(=5.\left(-16\right)=-80\)

a, 18.17-3.6.7            b,54-6.(17+5)      c,33.(17.5)-17.(33-5)

=18.17-18.7               =6.9-6.22            =33.17.5-17.(33-5)

=18.(17-17)                =6.(9-22)            =17.(33.5)-17.(33-5)

=18.10                        =6.(-13)              =17.165-17.28        

=18.10                        =6.(-13)              =17.(165-28)

=180                           =-78                    =17.137

                                                              =2329

33.(17 – 5) – 17.(33 -5)

= 33. 17 – 33.5 – 17.33 + 17.5

= (33.17 – 33. 17) + ( 17.5 – 33.5)

= 0 + 5.(17- 33)

= 5.(- 16) = -80

\(a,18.17-3.6.7\)

\(=18.17-18.7\)

\(=18.\left(17-7\right)\)

\(=18.10\)

\(=180\)

\(b,54-6.\left(17+9\right)\)

\(=54-6.17+6.9\)

\(=54-102+54\)

\(=\left(54+54\right)-102\)

\(=108-102\)

\(=6\)

\(c,33.\left(17-5\right)-17.\left(33-5\right)\)

\(=33.17-33.5-17.33-17.5\)

\(=\left(33.17-17.33\right)-\left[5\left(33-17\right)\right]\)

\(=0-5.16\)

\(=-80\)

a) \(18.17-3.6.7\)

\(=18.17-18.7\)

\(=18.\left(17-7\right)\)

\(=18.10\)

\(=180\)

b) \(54-6.\left(17+9\right)\)

\(=54-102-54\)

\(=-102\)

c) \(33.\left(17-5\right)-17.\left(33-5\right)\)

\(=561-165-561+85\)

\(=-80\)

a , 18 . 17 - 3 . 6 . 7

= 18 .17 - 18 . 7

= 18 . ( 17 - 7 )

= 18 . 10

= 180

b , 54 - 6 . ( 17 + 9 )

= 54 - 6 . 17 + 6 . 9

= 54 - 102 + 54

= ( 54 - 54 ) - 102

= 0 - 102

= - 102

c , 33 . ( 17 - 5 ) - 17 . ( 33 - 5 )

= 33 . 17 - 33 . 5 - 17 . 33 - 17 .5

= 0 - 5 . 16

= 0 - 80

= - 80

a.18.17-3.6.7
 =18.17-18.7
 =18.(17-7)
 =18.10=180
b.54-6.(17+9)
 =54-6.26
 =54-156=-102
c.33.(17-5)-17.(33-5)
 =33.17-33.5-17.33+17.5
 =33.5+17.5
 =(33+17).5
 =50.5=250

a) \(=\left(\left(-\frac{1}{4}-\frac{5}{3}\right)+\frac{7}{33}\right)-\left(-\frac{15}{12}+\frac{6}{11}-\frac{48}{49}\right)\)

\(=\left(-\frac{23}{12}+\frac{7}{33}\right)+\frac{15}{12}-\frac{6}{11}+\frac{48}{49}\)

\(=\left(-\frac{23}{12}+\frac{15}{12}\right)+\left(\frac{9}{33}-\frac{6}{11}\right)+\frac{48}{49}\)

\(=-\frac{2}{3}-\frac{3}{11}+\frac{48}{49}\)

\(=\frac{65}{1617}\)

b) \(=\frac{11}{125}+\left(-\frac{17}{18}+\frac{4}{9}\right)+\left(-\frac{5}{7}+\frac{17}{14}\right)\)

\(=\frac{11}{125}-\frac{1}{2}+\frac{1}{2}\)

\(=\frac{11}{125}\)

tính từng cái là đc

cau a em

a) 18.17 - 3.6.7

= 18.17-18.7

=18.( 17 - 7 )

= 18 . 10

= 180

b) 54 - 6.( 17 + 9) 

= 6.9 - 6 . 26

= 6.( 9 - 26 ) 

= 6 . ( - 17 ) 

= -102

c) 33.(17 - 5 ) - 17.(33-5)

= 33.17 - 33 .3  - 17.33 -  17 . 5 

= 33.17 + ( -33 ) .3 + ( - 17) .33 + ( -17) .5

= 33.17 + ( - 17) . 33 + 33 . ( - 3) + ( -17 ) .5

= 33. [ 17 + ( -17 ) + ( - 3 )] + (-17) . 5

= 33 . ( - 3 ) + ( -17 ) .5

= -99 + ( - 85)

= -184

a) 18 . 17 - 3 . 6 . 7                   b) 54 - 6 . ( 17 + 9 )                             

= 306      - 126                           = 48  . 26                                            

= 180                                        = 1248

,mk giúp đc từng đó nha

a) \(25.\left(-7\right).4=\left(25.4\right).\left(-7\right)=100.\left(-7\right)=-700\)

b) \(33.\left(17-5\right)-17.\left(33-5\right)=33.17-33.5-17.33+17.5=5.\left(17-33\right)\)\(=5.\left(-16\right)=-80\)

25.(-7).4

=(25.4).(-7)

=100.(-7)

=-700

\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)

\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)

\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)

\(=\frac{17}{33}\times\left(1-1\right)\)

\(=\frac{17}{33}\times0=\frac{17}{33}\)

 Làm he LÀM đi bạ nó lại  cồn bỏ bỏ