Ta có : 2^x + 2^{x + 4} = 544

=> 2^x(1 + 2⁴) = 544

=> 2^x.17 = 544

=> 2^x = 32

=> 2^x = 2⁵

=> x = 5

Vậy x = 5

\(\Leftrightarrow2^x\left(1+2^4\right)=544\\ \Leftrightarrow2^x\cdot17=544\\ \Leftrightarrow2^x=32=2^5\Leftrightarrow x=5\)

\(2^x+2^{x+4}=544\\\Rightarrow2^x\cdot1+2^x\cdot2^4=544\\\Rightarrow2^x\cdot(1+2^4)=544\\\Rightarrow2^x\cdot(1+16)=544\\\Rightarrow2^x\cdot17=544\\\Rightarrow2^x=544:17\\\Rightarrow2^x=32\\\Rightarrow2^x=2^5\\\Rightarrow x=5\)

\(2^x+2^{x+4}=544\)

=>\(2^x+2^x\cdot2^4=544\)

=>\(2^x\left(1+2^4\right)=544\)

=>\(2^x\cdot17=544\)

=>\(2^x=\dfrac{544}{17}=32\)

=>\(2^x=2^5\)

=>x=5

​\(2^x+2^{x+4}=544\)

\(\Rightarrow2^x+2^x\cdot2^4=544\)

\(\Rightarrow2^x\left(1+2^4\right)=544\)

​\(\Rightarrow2^x\cdot17=544\)

\(\Rightarrow2^x=32\)

mà \(2^5=32\)

Suy ra: \(x=5\)

Vậy \(x=5\) là giá trị cần tìm.

4 vẫn trên mũ

2^x + 2^{x + 4} = 544

=> 2^x . 1 + 2^x . 2⁴ = 544

=> 2^x . (1 + 16) = 544

=> 2^x . 17 = 544

=> 2^x = 32

=> 2^x = 2⁵

=> x = 5

Vậy x = 5.

~Study well~

#Shizu

\(2^x+2^{x+4}=544\)

\(2^x.1+2^x.2^4=544\Rightarrow2^x.\left(1+2^4\right)=544\)

\(2^x.17=544\Rightarrow2^x=544:17=32\)   

\(\Rightarrow2^x=2^5\Rightarrow x=5\)

Vậy \(x=5\)

x = 5 nhé bạn 

ra đi ra lại không chán hả

     2^x + 2^{x + 4}  = 544

\(\Rightarrow\)  2^x + 2^x . 2⁴ = 544

\(\Rightarrow\)2^x . ( 1 + 2⁴ ) = 544

\(\Rightarrow\)2^x = 544 ÷ 17

\(\Rightarrow\)2^x = 32 = 2⁵

\(\Rightarrow\)x = 5

Vậy : x = 5

2^x+2^x+4=544

2^x+2^x.2⁴=544

2^x.(1+16)=544

2^x.17        =544

2^x              =544:17

2^x               =32=2⁵

^=>x=5

Vậy x=5

hok tốt

2^x + 2^x+4 = 544

<=> 2^x + 2^x.2⁴ = 544

<=> 2^x( 1 + 2⁴ ) = 544

<=> 2^x.( 1 + 16 ) = 544

<=> 2^x.17 = 544

<=> 2^x = 32

<=> 2^x = 2⁵

<=> x = 5

\(2^x+2^{x+4}=544\Leftrightarrow2^x\left(1+2^4\right)=544\)

\(\Leftrightarrow2^x=\frac{544}{17}=32=2^5\Rightarrow x=5\)

~ Học tốt ~