Cho \(f\left(n\right)=\frac{2n+1+\sqrt{n\left(n+1\right)}}{\sqrt{n}+\sqrt{n+1}}\)
Tính \(f\left(1\right)+f\left(2\right)+...+f\left(2020\right)\)
Cho \(f\left(n\right)=\dfrac{4n+\sqrt{4n^2-1}}{\sqrt{2n+1}+\sqrt[]{2n-1}}\) với n nguyên dương. Tính \(f\left(1\right)+f\left(2\right)+...+f\left(40\right)\).
\(f\left(n\right)=\dfrac{2n-1+2n+1+\sqrt{\left(2n+1\right)\left(2n+1\right)}}{\sqrt{2n+1}+\sqrt{2n-1}}\\ f\left(n\right)=\dfrac{\left(\sqrt{2n+1}-\sqrt{2n-1}\right)\left(2n-1+2n+1+\sqrt{\left(2n+1\right)\left(2n+1\right)}\right)}{2n+1-2n+1}\\ f\left(n\right)=\dfrac{\left(\sqrt{2n+1}\right)^3-\left(\sqrt{2n+1}\right)^3}{2}=\dfrac{\left(2n+1\right)\sqrt{2n+1}-\left(2n-1\right)\sqrt{2n+1}}{2}\)
\(\Leftrightarrow f\left(1\right)+f\left(2\right)+...+f\left(40\right)=\dfrac{3\sqrt{3}-1\sqrt{1}+5\sqrt{5}-3\sqrt{3}+...+81\sqrt{81}-79\sqrt{79}}{2}\\ =\dfrac{81\sqrt{81}-1\sqrt{1}}{2}=\dfrac{9^3-1}{2}=364\)
tính các giới hạn sau:
a) lim (3n2+n2-1)
b)lim \(\dfrac{n^3+3n+1}{2n-n^3}\)
c) lim \(\dfrac{-2n^3+3n+1}{n-n^2}\)
d) lim \(\left(n+\sqrt{n^2-2n}\right)\)
e) lim \(\left(2n-3.2^n+1\right)\)
f) lim \(\left(\sqrt{4n^2-n}-2n\right)\)
g) lim \(\left(\sqrt{n^2+3n-1}-\sqrt[3]{n^3-n}\right)\)
a/ Bạn coi lại đề bài, 3n^2 +n^2 thì bằng 4n^2 luôn chứ ko ai cho đề bài như vậy cả
b/ \(\lim\limits\dfrac{\dfrac{n^3}{n^3}+\dfrac{3n}{n^3}+\dfrac{1}{n^3}}{-\dfrac{n^3}{n^3}+\dfrac{2n}{n^3}}=-1\)
c/ \(=\lim\limits\dfrac{-\dfrac{2n^3}{n^2}+\dfrac{3n}{n^2}+\dfrac{1}{n^2}}{-\dfrac{n^2}{n^2}+\dfrac{n}{n^2}}=\lim\limits\dfrac{-2n}{-1}=+\infty\)
d/ \(=\lim\limits\left[n\left(1+1\right)\right]=+\infty\)
e/ \(\lim\limits\left[2^n\left(\dfrac{2n}{2^n}-3+\dfrac{1}{2^n}\right)\right]=\lim\limits\left(-3.2^n\right)=-\infty\)
f/ \(=\lim\limits\dfrac{4n^2-n-4n^2}{\sqrt{4n^2-n}+2n}=\lim\limits\dfrac{-\dfrac{n}{n}}{\sqrt{\dfrac{4n^2}{n^2}-\dfrac{n}{n^2}}+\dfrac{2n}{n}}=-\dfrac{1}{2+2}=-\dfrac{1}{4}\)
g/ \(=\lim\limits\dfrac{n^2+3n-1-n^2}{\sqrt{n^2+3n-1}+n}+\lim\limits\dfrac{n^3-n^3+n}{\sqrt[3]{\left(n^3-n\right)^2}+n.\sqrt[3]{n^3-n}+n^2}\)
\(=\lim\limits\dfrac{\dfrac{3n}{n}-\dfrac{1}{n}}{\sqrt{\dfrac{n^2}{n^2}+\dfrac{3n}{n^2}-\dfrac{1}{n^2}}+\dfrac{n}{n}}+\lim\limits\dfrac{\dfrac{n}{n^2}}{\dfrac{\sqrt[3]{\left(n^3-n\right)^2}}{n^2}+\dfrac{n\sqrt[3]{n^3-n}}{n^2}+\dfrac{n^2}{n^2}}\)
\(=\dfrac{3}{2}+0=\dfrac{3}{2}\)
a) lim \(\left(-3n^3+n^2-1\right)\)
minh le oi ban dao mau so cua ban len cho tu uong roi thay vi tri cua mau thanh n3 +2n
cho f(x) dương liên tục trên [0;1] f(0)=1. Biết \(3\int_0^1\left[f'\left(x\right)\left[f\left(x\right)\right]^2+\frac{1}{9}\right]dx\le2\int_0^1\sqrt{f'\left(x\right)}f\left(x\right)dx\) . Tính \(\int_0^1\left[f\left(x\right)\right]^3dx\)
\(3\int\limits^1_0\left[f'\left(x\right).f^2\left(x\right)+\frac{1}{9}\right]dx\le2\int\limits^1_0\sqrt{f'\left(x\right)}f\left(x\right)dx\) (1)
Ta lại có:
\(3f'\left(x\right).f^2\left(x\right)+\frac{1}{3}\ge2\sqrt{f'\left(x\right)}.f\left(x\right)\)
\(\Rightarrow3\int\limits^1_0\left[f'\left(x\right).f^2\left(x\right)+\frac{1}{9}\right]\ge2\int\limits^1_0\sqrt{f'\left(x\right)}.f\left(x\right)dx\) (2)
Từ (1); (2) \(\Rightarrow3\int\limits^1_0\left[f'\left(x\right).f^2\left(x\right)+\frac{1}{9}\right]dx=2\int\limits^1_0\sqrt{f'\left(x\right)}.f\left(x\right)dx\)
Dấu "=" xảy ra khi và chỉ khi:
\(3f'\left(x\right).f^2\left(x\right)=\frac{1}{3}\Rightarrow3\int f'\left(x\right).f^2\left(x\right)dx=\int\frac{1}{3}dx\)
\(\Rightarrow f^3\left(x\right)=\frac{x}{3}+C\)
Thay \(x=0\Rightarrow f^3\left(0\right)=C\Rightarrow C=1\)
\(\Rightarrow f^3\left(x\right)=\frac{x}{3}+1\Rightarrow\int\limits^1_0f^3\left(x\right)dx=\int\limits^1_0\left(\frac{x}{3}+1\right)dx=\frac{7}{6}\)
Cho \(f\left(n\right)=\left(n^2+n+1\right)^2+1\) với n là số nguyên dương.
Đặt \(P_n=\frac{f\left(1\right).f\left(3\right).f\left(5\right).......f\left(2n-1\right)}{f\left(2\right).f\left(4\right).f\left(6\right).......f\left(2n\right)}\).Chứng minh rằng:\(P_1+P_2+P_3+...........+P_n< \frac{1}{2}\)
Bài 1:Tính S= \(\sqrt{1+\frac{1}{2^2}+\frac{1}{3^2}}+\sqrt{1+\frac{1}{3^2}+\frac{1}{4^2}}+...+\sqrt{1+\frac{1}{99^2}+\frac{1}{100^2}}\)
Bài 2: Tính S= 1+3+9+27+...+1438907
Bài 3: Cho \(f\left(1\right)=1;f\left(m+n\right)=f\left(m\right)+f\left(n\right)+mn.\)Tính f(10), f(2015) (Với m, n là các số nguyên dương)
Bài 1
Ta có \(\sqrt{1+\frac{1}{2^2}+\frac{1}{3^2}}=\sqrt{\left(1+\frac{1}{2}-\frac{1}{3}\right)^2}\)
Tương tự như trên ta được
S = 1+1/2-1/3+1+1/3-1/4+...+1+1/99-1/100
= 98 + 1/2 - 1/100
= 9849/100
\(f\left(n\right)=\left(n^2+n+1\right)^2+1\). Xét dãy \(\left(u_n\right)\) sao cho : \(\left(u_n\right)=\dfrac{f\left(1\right)\cdot f\left(3\right)\cdot f\left(5\right)...\cdot f\left(2n-1\right)}{f\left(2\right)\cdot f\left(4\right)\cdot...\cdot f\left(2n\right)}\). Tính \(\lim\limits_{n\sqrt{u_n}}\)
Cho \(f\left(x\right)=\left(x^2+x+1\right)^2+1\).Gọi n là số nguyên dương nhỏ nhất mà \(\frac{f\left(2\right).f\left(4\right)......f\left(2n\right)}{f\left(1\right).f\left(3\right).....f\left(2n-1\right)}>2^{2013}\)
Tìm chữ số tận cùng của n
cho f(x)=(x2+x+1)2+1 với mọi x thuộc N.
a)tìm x để f(x) là số tự nhiên
b)thu gọn:
Pn=\(\frac{f\left(1\right).f\left(3\right).....f\left(2n-1\right)}{f\left(2\right).f\left(4\right).....f\left(2n\right)}\) với n thuộc N*
Câu 1: Gọi \(F\left(x\right)\) là một nguyên hàm của \(f\left(x\right)\) . Cho \(f’\left(x\right)=2x\ln\left(x\right)+2x\) và \(f\left(1\right)=\frac{1}{2}\), \(F\left(1\right)=\frac{1}{18}\) . Hỏi phương trình \(\frac{f\left(x\right).F\left(x\right)}{F\left(f\left(x\right)\right)+f\left(F\left(x\right)\right)}=0\) có bao nhiêu nghiệm dương.
Câu 2: Cho \(\int\limits^4_1f\left(x\right)dx=\frac{14\sqrt{2}}{3}\) và \(\int\limits^4_1f’\left(x\right)dx=\sqrt{2}\), \(f\left(0\right)=0\). Tính \(f\left(1\right)+f\left(2\right)\) bằng
Câu 3: Cho \(\int\limits^2_1f\left(x\right)\log\left(x\right)dx=\log\left(4\right)-\frac{3}{4\ln\left(10\right)}\), \(\int\limits^2_1f’\left(x\right)\log\left(x\right)dx=\log\left(4\right)-\frac{1}{\ln10}\) . Khi này phương trình \(f\left(x\right)^2+f\left(x\right)-2=0\) có bao nhiêu nghiệm nguyên.