a) \(\dfrac{6}{13}:\left(\dfrac{1}{2}-x\right)=\dfrac{15}{39}\)

\(\dfrac{1}{2}-x=\dfrac{6}{13}:\dfrac{15}{39}\)

\(\dfrac{1}{2}-x=\dfrac{6}{5}\)

\(x=\dfrac{1}{2}-\dfrac{6}{5}\)

\(x=-\dfrac{7}{10}\)

b) \(3\times\left(\dfrac{x}{4}+\dfrac{x}{28}+\dfrac{x}{70}+\dfrac{x}{130}\right)=\dfrac{60}{13}\)

\(3\times x\times\left(\dfrac{1}{4}+\dfrac{1}{28}+\dfrac{1}{70}+\dfrac{1}{130}\right)=\dfrac{60}{13}\)

\(x\times\left(\dfrac{3}{1\times4}+\dfrac{3}{4\times7}+\dfrac{3}{7\times10}+\dfrac{3}{7\times13}\right)=\dfrac{60}{13}\)

\(x\times\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}\right)=\dfrac{60}{13}\)

\(x\times\left(1-\dfrac{1}{13}\right)=\dfrac{60}{13}\)

\(x\times\dfrac{12}{13}=\dfrac{60}{13}\)

\(x=\dfrac{60}{13}:\dfrac{12}{13}\)

\(x=5\)

`3 xx (x/4 + x/28 + x/70 + x/130) =60/13`

`x/4 + x/28 + x/70 + x/130 = 20/13`

`x xx (1/4+1/28+1/70+1/130)=20/13`

`x xx 4/13= 20/13`

`x=5`

`3 xx (x/4 + x/28 + +x/70 +x/130) =60/13`

`x xx (1/4 + 1/28 + +1/70 +1/130)=20/13

`x xx 4/13 = 20/13`

`x=5`

\(3\times\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{13}\)

=> \(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}=\frac{20}{13}\)

=> \(\frac{x}{1\cdot4}+\frac{x}{4\cdot7}+\frac{x}{7\cdot10}+\frac{x}{10\cdot13}=\frac{20}{13}\)

=> \(\frac{x}{3}\left(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}\right)=\frac{20}{13}\)

=> \(\frac{x}{3}\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{10}-\frac{1}{13}\right)=\frac{20}{13}\)

=> \(\frac{x}{3}\left(1-\frac{1}{13}\right)=\frac{20}{13}\)

=> \(\frac{x}{3}\cdot\frac{12}{13}=\frac{20}{13}\)

=> \(\frac{x}{3}=\frac{20}{13}:\frac{12}{13}=\frac{20}{13}\cdot\frac{13}{12}=\frac{5}{3}\)

=> x = 5

\(3\cdot\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{13}\)

\(3\cdot\left(\frac{x}{1\cdot4}+\frac{x}{4\cdot7}+\frac{x}{7\cdot10}+\frac{x}{10\cdot13}\right)=\frac{60}{13}\)

\(3\left(x-3\right)\left(\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}\right)=\frac{60}{13}\)

\(\left(3x-9\right)\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=\frac{60}{13}\)

\(\left(3x-9\right)\left(1-\frac{1}{13}\right)=\frac{60}{13}\)

\(\left(3x-9\right)\cdot\frac{12}{13}=\frac{60}{13}\)

\(3x-9=\frac{\frac{60}{13}}{\frac{12}{13}}\)

\(3x-9=5\)

\(3x=5+9\)

\(3x=14\)

\(x=\frac{14}{3}\approx4,667\)

\(3.\left(\frac{x}{4}+\frac{x}{28}+\frac{x}{70}+\frac{x}{130}\right)=\frac{60}{13}\)

\(3.\left(\frac{x}{1.4}+\frac{x}{4.7}+\frac{x}{7.10}+\frac{x}{10.13}\right)=\frac{60}{13}\)

\(3.\frac{x}{3}.\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+\frac{3}{10.13}\right)=\frac{60}{13}\)

\(x.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)=\frac{60}{13}\)

\(x.\left(1-\frac{1}{13}\right)=\frac{60}{13}\)

\(x.\frac{12}{13}=\frac{60}{13}\)

\(x=\frac{60}{13}\div\frac{12}{13}\)

\(x=5\)

5ˣ⁻².5ˣ.5ˣ⁺².5ˣ⁺⁴ = 625

5ˣ⁻²⁺ˣ⁺ˣ⁺²⁺ˣ⁺⁴ = 5⁴

5⁴ˣ⁺⁴ = 5⁴

4x + 4 = 4

4x = 0

x = 0

\(\Leftrightarrow5^{\left(x-2+x+x+2+x+4\right)}=5^4\)

\(\Leftrightarrow5^{4x+4}=5^4\Rightarrow4x+4=4\Rightarrow x=0\)

\(...\Rightarrow5^{x-2+x+x+2+x+4}=5^4\)

\(\Rightarrow5^{4x+4}=5^4\)

\(\Rightarrow4x+4=4\)

\(\Rightarrow4x=0\)

\(\Rightarrow x=0\)

a) x = 160

b) x = 5

c) x = 107

d) x = 3

\(52:x=\frac{1}{4}+\frac{1}{28}+\frac{1}{70}+\frac{1}{130}\)

\(52:x=\frac{1}{1\times4}+\frac{1}{4\times7}+\frac{1}{7\times10}+\frac{1}{10\times13}\)

\(52:x=\frac{1}{3}\times\left(\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+\frac{3}{10\times13}\right)\)

\(52:x=\frac{1}{3}\times\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+\frac{1}{10}-\frac{1}{13}\right)\)

\(52:x=\frac{1}{3}\times\left(1-\frac{1}{13}\right)\)

\(52:x=\frac{1}{3}\times\frac{12}{13}\)

\(52:x=\frac{4}{13}\)

\(x=52:\frac{4}{13}\)

\(x=169\)

52 :x =1/4 + 1/28 +1/70 + 1/130

52 : x = 4/13

x = 52 : 4/13

x = 169

tinh trong ngoac truoc =12/3 nhan cho x

suy ra lay 36 : 12/3=9

con bai b ban ket hop cac gia tri la voi nhau vi phep cong co tinh chat ket hop

lay x*57+x*50-x*7=x*57+50-7=x*100

x nhan 100 = 10000
suy ra x bang 100

thu lai ket qua di minh chac la dung

nho k cho minh nha thank

pt đã cho có dạng \(\frac{1}{\left(x+1\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+7\right)}+\frac{1}{\left(x+7\right)\left(x+10\right)}=\frac{4}{13}\)
\(\Leftrightarrow\frac{1}{x+1}-\frac{1}{x+4}+\frac{1}{x+4}-\frac{1}{x+7}+\frac{1}{x+7}-\frac{1}{x+10}=\frac{4}{13}\)
\(\Leftrightarrow\frac{1}{x+1}-\frac{1}{x+10}=\frac{4}{13}\Leftrightarrow....\)

bạn tuấn mình thấy vậy nè

Gỉa sử cho x=1 ta thấy \(\frac{1}{1\times4}\ne\frac{1}{1}-\frac{1}{4}\)

Bạn bấm máy tính thử xem dấu bằng chỉ áp dụng với 2 số tự nhiên liên tiếp thôi còn cái này cách 3 lận

giải thích giúp mình với

à 

ý là nhân hai về pt cho 3 đúg kk 

mình hiểu rồi nha

cảm ơn nha

Lời giải:

\((50\times 60\times 70\times 80):(15\times 25\times 28\times 20)\\ =(50:25)\times (60:15)\times (70:28)\times (80:20)\\ =2\times 4\times \frac{5}{2}\times 4=80\)