A)(x+5)(x-4)=0

=)x+5=0 hoặc x-4=0

=)x=-5 hoặc x=4

Nếu đề là tìm x thì làm như sau :

a) (x+5).(x-4)=0

\(\Rightarrow\orbr{\begin{cases}x+5=0\\x-4=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-5\\x=4\end{cases}}\)

Vậy x\(\in\){-5;4}

Câu b, c và d tương tự

e) 4-(27-3)=x-(13-4)

x-(13-4)=-20

x-9=-20

x=-20+9

x=-11

Vậy x=-11

f) 8-(x-10)=23-(-4+12)

8-(x-10)=15

x-10=8-15

x-10=-7

x=-7+10

x=3

Vậy x=3.

Lần sau bạn nhớ ghi yêu cầu đề bài nhé!

4-(27-3) = x- (13-4)

4-24= x - 9

-20 = x-9

x-9 = -20

x = -20+9

x = -11

Vậy : x =  -11

8-(x-10) = 23-(-4+12)

8-(x-10) = 23-8

8-(x-10) = 15

x-10 = 8-15

x-10 = -7

x = -7+10

x = 3

Vậy : x = 3

3) \(-12+2x-9+x=0\\ -21+3x=0\\ 3x=21\\ x=7\)

4)
\(11+\left(15-x\right)=1\)
\(15-x=1-11\)
\(15-x=-10\)
\(x=15-\left(-10\right)\)
\(x=25\)

5) 
\(4-\left(27-3\right)=x-\left(13-4\right)\)
\(4-24=x-9\)
\(x-9=-20\)
\(x=-20+9\)
\(x=-11\)
 

\(3.-12+\left(2x-9\right)+x=0.\)

\(\Leftrightarrow-12+2x-9+x=0.\Leftrightarrow3x=21.\Leftrightarrow x=7.\)

Vậy \(x=7.\)

\(4.11+\left(15-x\right)=1.\Leftrightarrow11+15-x=1.\Leftrightarrow26-x=1.\Leftrightarrow x=25.\)

Vậy \(x=25.\)

\(5.4-\left(27-3\right)=x-\left(13-4\right).\Leftrightarrow4-24=x-9.\Leftrightarrow-20=x-9.\Leftrightarrow x=-11.\)

Vậy \(x=-11.\)

\(6.8-\left(x-10\right)=23-\left(-4+12\right).\Leftrightarrow8-x+10=23-8.\Leftrightarrow18-x=15.\Leftrightarrow x=3.\)

Vậy \(x=3.\)

\(7.105-5\left(10-5x\right)=-20.\Leftrightarrow105-50+25x=-20.\Leftrightarrow25x=-75.\Leftrightarrow x=-3.\)

Vậy \(x=-3.\)

\(8.\left(x-1\right)\left(8-2x\right)\left(3x+123\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0.\\8-2x=0.\\3x+123=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1.\\x=4.\\x=-41.\end{matrix}\right.\)

Vậy \(x\in\left\{1;4;-41\right\}.\)

\(9.\left(x^2-25\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left(x-5\right)\left(x+5\right)\left(x+10\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0.\\x+5=0.\\x+10=0.\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5.\\x=-5.\\x=-10.\end{matrix}\right.\)

Vậy \(x\in\left\{5;-5;-10\right\}.\)

\(10.x\left(x^2+5\right)=0.\Leftrightarrow x=0.\)

tách ra

\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)

\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)

1)10-x=5-7

x=10-(-2)

x=12

2)x+5=0+32

x=32-5

x=27

3) -12+2x-9+x=0

-12+(2x+x-9)=0

3x-9=0+12

3x=12+9

x=21:3

x=7

4) 15-x=1-11

x=15-(-10)

x=25

5) 4-(27+3)=x-9

4-30=x-9

-26+9=x

x=-17

#)Giải :

a) x + 2x + 3x + ... + 100x = - 213

=> 100x + ( 2 + 3 + 4 + ... + 100 ) = - 213 

=> 100x + 5049 = - 213 

<=> 100x = - 5262

<=> x = - 52,62

#)Giải :

b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)

\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{3}+\frac{1}{6}\)

\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{2}\)

\(\Rightarrow\left(\frac{1}{2}+\frac{1}{4}\right)x=\frac{1}{2}\)

\(\Rightarrow\frac{3}{4}x=\frac{1}{2}\)

\(\Leftrightarrow x=\frac{2}{3}\)

a) x + 2x + 3x + ... +100x = -213

=>  x . (1 + 2 + 3 +... + 100) = - 213

=> x . 5050 = -213

=> x           = - 213 : 5050

=> x           = -213/5050

b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)

=> \(\frac{1}{2}x-\frac{1}{4}x=\frac{1}{3}-\frac{1}{6}\)

=> \(x.\left(\frac{1}{2}-\frac{1}{4}\right)=\frac{1}{6}\)

=> \(x.\frac{1}{4}=\frac{1}{6}\)

=> \(x=\frac{1}{6}:\frac{1}{4}\)

=> \(x=\frac{2}{3}\)

c) 3(x-2) + 2(x-1) = 10

=> 3x - 6 + 2x - 2 = 10

=> 3x + 2x - 6 - 2 = 10

=> 5x - 8 = 10

=> 5x = 10 + 8

=> 5x = 18

=> x = 18:5

=> x = 3,6

d) \(\frac{x+1}{3}=\frac{x-2}{4}\)

=> \(4\left(x+1\right)=3\left(x-2\right)\)

=>\(4x+4=3x-6\)

=> \(4x-3x=-4-6\)

=> \(x=-10\)

d) \(x-\left(-25+x\right)=13-x.\)

\(\Rightarrow x+25+x=13-x\)

\(\Rightarrow x+x+x=13-25\)

\(\Rightarrow3x=-12\)

\(\Rightarrow x=-4\)

e) \(15-\left(30+x\right)=x-\left(27-\text{| }-8\text{| }\right)\)

\(\Rightarrow15-30-x=x-19\)

\(\Rightarrow-15-x=x-19\)

\(\Rightarrow-15+19=x+x\)

\(\Rightarrow4=2x\)

\(x=2\)

f) \(\left(12x-4^3\right).8^3=4.8^4\)

\(\left(12x-2^6\right).2^9=2^2.2^{12}\)

\(12x-2^6=2^2.2^{12}\div2^9\)

\(12x-64=2^5=32\)

\(12x=96\)

\(x=8\)

g) \(\left[119-\left(3^3-10\right)\right].x=2448\)

\(\left[119-\left(27-10\right)\right].x=2448\)

\(\left[119-17\right].x=2448\)

\(102.x=2448\)

\(x=24\)

h) 

 [( 10 - x ) .2-51] : 3 - 2 = 3

    [( 10 - x ) .2-51] : 3      = 3 + 2

    [( 10 - x ) .2-51] : 3      = 5

     ( 10 - x ) .2 - 51          = 5 . 3

      ( 10 - x ) . 2 - 51        = 15 

    ( 10 - x ) . 2                 = 15 + 51 

       ( 10 - x ) . 2              = 66

         10 - x                     = 66 : 2 

       10 - x                       = 33

          x                           = 10 - 33

          x                           = -23 

i) 

(x-12)-15 = (20-7)-(18+x)                              

     x-12-15  = 20-7-18-x                                                     

     x-27      =   -5-x                                                             

=> x-27+5+x = 0                                                       

          2x-25  =0

          2x = 0+25 = 25

k) 

thank cậu

bạn ơi từ câu k mình ko thấy bạn viết gì

a) Ta có:  x 2 = 2 2  nên x = 2.

b) Ta có: x 2 = 5 2 nên x = 5.

c) Ta có:  3 x 5 = 3  nên  x 5 = 1 . Do đó x = 1.

d) Ta có:  6 x 3 = 48  nên  x 3 = 8 . Do đó x = 2.

e) Ta có:  x - 1 2 = 2 2  nên  x - 1 = 2 . Do đó x = 3.

f) Ta có:  x + 1 2 = 5 2  nên x +1 = 5. Do đó x = 4.

g) Ta có:  x - 1 3 = 3 3  nên  x - 1 = 3 . Do đó x = 4.

h) Ta có:  x + 1 3 = 4 3 nên x +1 = 4. Do đó x = 3