cho tam giac ABC vuong tai A co AB bang 6 cm , AC bang 8 cm . tinh do dai ban kinh duong tron tam a tiep xuc voi BC
cho tam giac ABC co 3 goc nhon cac duong cao AD BE CF cua tam giac ABC cat nhau tai H
a) CM: tu giac CFHD noi tiep trong 1 duong tron xac dinh vi tri tam O cua duong tron ngoai tiep tu giac CEHD
b) CM: goc FEH bang goc DEH . CM: H la tam duong tron noi tiep tam giac DEF
c) CM; CH = 4cm tinh do dai duong tron tam (o) va duong kinh hinh tron (o)
Cho nua duong tron tam O , ban kinh R , duong kinh AB. D la diem thuoc nua duong tron sao cho DA > DB . Goi DH la duong cao cua tam giac DAB . Biet DH = 6cm , HB = 4,5 cm
a) Chung minh tam giac ADB vuong , tinh do dai DB , DA
b) Goi G la trung diem cua BD . tia OG cat tiep tuyen tai B cua duong tron tai F . CHung minh FD la tiep tuyen va goc DAF = Goc BAG
c) Doan AF cat DO , DH thu tu tai I , P . Cm dien tich tu giac BPIO va dien tich tam giac DIA bang nhau
Trần Nguyễn Bảo QuyênLoverstthAki TsukiAkai Haruma@buithianhtho
Cho nua duong tron tam O , ban kinh R , duong kinh AB. D la diem thuoc nua duong tron sao cho DA > DB . Goi DH la duong cao cua tam giac DAB . Biet DH = 6cm , HB = 4,5 cm
a) Chung minh tam giac ADB vuong , tinh do dai DB , DA
b) Goi G la trung diem cua BD . tia OG cat tiep tuyen tai B cua duong tron tai F . CHung minh FD la tiep tuyen va goc DAF = Goc BAG
c) Doan AF cat DO , DH thu tu tai I , P . Cm dien tich tu giac BPIO va dien tich tam giac DIA bang nhau
cho tam giac ABC vuong tai A, co chu vi la 72 cm. Do dai canh AB bang 3/5 do dai canh BC, do dai canh AC bang 4/5 do dai canh BC. Tinh s tam giac
cho tam giac ABC nhon co AB<AC noi tiep duong tron (O),lay M tuy y tren cung BC ke MP vuong voi ACva PR vuong voi BC tai Q,
a)chung minh MQ vuong voi PQ va PM*CM=BM*MR
c)ke duong cao AD va CE cua tam giac ABCcat nhau tai Hduong kinh BK cat DE tai I.cm tu giac DCKI noi tiep duong tron
d)ke SC vuong voi AM tai S.chung minh PQ vuong ES
Cho nua duong tron tam O , ban kinh R , duong kinh AB. D la diem thuoc nua duong tron sao cho DA > DB . Goi DH la duong cao cua tam giac DAB . Biet DH = 6cm , HB = 4,5 cm
a) Chung minh tam giac ADB vuong , tinh do dai DB , DA
b) Goi G la trung diem cua BD . tia OG cat tiep tuyen tai B cua duong tron tai F . CHung minh FD la tiep tuyen va goc DAF = Goc BAG
c) Doan AF cat DO , DH thu tu tai I , P . Cm dien tich tu giac BPIO va dien tich tam giac DIA bang nhau
HELP!10SP cho câu tl đúng>
cho tam giac abc vuong tai a, co ab=3 cm ac=4 cm, duong phan giac ad. duong vuong goc voi dc cat ac tai e
a) cmr tam giac abc va tam giac dec dong dang
b) tinh do dai cac doan thang bc,bd
c) tinh do dai ad
d) tinh dien tich tam giac abc va dien tich tu giac abde
cho tam giac ABC co AB bang AC bang 5 cm ; BC bang 6 cm . ke AH vuong BC , h thuoc bc
a , chung minh HB bang HC va BAH bang CAH
B, tinh do dai AH
c, ke HM vuong AB tai M , ke HN vuong AC tai N . Chung minh tam giac MHN la tam giac can
d, ke tia Bx vuong BA , ke Cy vuong AC ; hai tia Bx va Cy cat nhau tai I .Chung minh AI vuong goc voi BC
tu ve hinh :
a, AC = AB => tamgiac ABC can tai A (dn)
=> goc ABC = goc ACB (tc)
xet tam giac ABH va tamgiac ACH co : goc AHC = goc AHB do AH | BC (gt)
=> tam giac ABH = tamgiac ACH (ch - gn) (1)
b, tamgiac AHB vuong tai H do AH | BC (gt)
=> AB2 = AH2 + BH2
(1) => BH = HC ma BC = 6 (gt)=> BH = 3
BA = 5 (gt)
=> AH2 = 52 - 32
=> AH2 = 16
=> AH = 4 do AH > 0
c, xet tamgiac BMH va tamgiac NCH co : goc BMH = goc NCH = 90o do MH | AB va HN | AC (gt)
goc ABC = goc ACB (cmt) va BH = HC (cmt)
=> tamgiac BMH = tamgiac NCH (ch - gn)
=> MH = HN (dn)
=> tamgiac MNH can tai H (dn)
d, cm theo truong hop ch - gn di, moi tay qa
Giải
( Bạn tự vẽ hình nhé )
a, \(AB=AC\) \(\Rightarrow\)\(\Delta ABC\) cân tại A
\(\Rightarrow\widehat{ABC}=\widehat{ACB}\)
Xét \(\Delta ABH\) và \(\Delta ACH\) có : \(\widehat{AHC}=\widehat{AHB}\) do \(AH\perp BC\)
\(\Delta ABH=\Delta ACH\) (1) [ đpcm]
b, \(\Delta AHB\) vuông tại H do \(AH\perp BC\)
\(\Rightarrow AB^2=AH^2+BH^2\)
Từ (1) suy ra BH = HC mà BC = 6 nên BH = 3
\(\Rightarrow\)BA = 5
\(\Rightarrow AH^2=5^2-3^2\)
\(\Rightarrow AH^2=25-9\)
\(\Rightarrow AH^2=16\)
\(\Rightarrow AH=\sqrt{16}\)
\(\Rightarrow AH=4cm\)
\(\Rightarrow\) AH = 4cm do AH > 0
c, Xét \(\Delta BMH\) và \(\Delta NCH\) có :\(\widehat{BMH}=\widehat{NCH}=90^0\) do \(MH\perp AB\) va \(HN\perp AC\)
\(\Rightarrow\widehat{ABC}=\widehat{ACB}\)và \(BH=HC\)
\(\Rightarrow\Delta BHM=\Delta NCH\)
\(\Rightarrow MH=HN\)
\(\Rightarrow\Delta MNH\) cân tại H \(\left(đpcm\right)\)
d, ...
co giup em voi
tam giac ABC vuong tai A co BC>AC>AB. D thuoc BC, E thuoc BA sao cho BD=BE=AC. Duong trong ngoai tiep tam giac EBD cat AC tai P, BP cat duong tron ngoai tiep ABC tai Q.
cm: AQ+CQ=BP