\(a.\left(3x-1\right)^4=81\)

\(->3x-1=+-3\)

giải 2 trường hợp 1 là 3 và 2 là -3 nha bn 

b) tự làm nha 

c) cx zậy nha 

~ hok tốt ~

a) \(\left(3x-1\right)^4=81\)

\(\Rightarrow\left(3x-1\right)^4=3^4\)

\(\Rightarrow3x-1=3\)

\(\Rightarrow3x=4\Rightarrow x=\frac{4}{3}\)

b) \(\left(x+1\right)^5=-32\)

\(\Rightarrow\left(x+1\right)^5=\left(-2\right)^5\)

\(\Rightarrow x+1=-2\Rightarrow x=-3\)

c) \(\left(2x+1\right)^5=\left(2x+1\right)^{2010}\)

\(\Rightarrow\left(2x+1\right)^5-\left(2x+1\right)^{2010}=0\)

\(\Rightarrow\left(2x+1\right)^5\cdot\left[1-\left(2x+1\right)^{2005}\right]=0\)

\(\Rightarrow\orbr{\begin{cases}\left(2x+1\right)^5=0\\1-\left(2x+1\right)^{2005}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}2x+1=0\\2x+1=1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=0\end{cases}}\)

_(3x - 1 )^4 = 3^4

suy ra 3x - 1 = 3

suy ra 3x = 4

suy ra x = 4/3

_(x +1)^5 = -32

suy ra  (x +1)^5 = -2^5

suy ra x +1 = -2

suy ra x = -3 

(2x + 1) ^5 = (2x+1)^2010\

Suy ra (2x + 1) ^5 = ((2x+1)^5)^ 402

suy ra  2x + 1 = (2x+1)^402 

suy ra 2x + 1 - (2x+1)^402 =0

suy ra ( 2x + 1) [ (2x+1)^401 - 1)

Suy ra 2x+1 =0

suy ra x = -1/2

tui bấm lộn vào ta6

\(3x-32>-5x+1\)

\(\Leftrightarrow3x+5x>1+32\)

\(\Leftrightarrow8x>33\)

\(\Leftrightarrow x>\frac{33}{8}\)

đây là bất đẳng thức mà,bn chỉ cần chuyển vế thui,y như đẳng thức ý!

k mk nha!

#meo#

\(\Leftrightarrow\dfrac{3x-1}{4}-\dfrac{3x-6}{8}-\dfrac{5-3x}{2}>1\)

\(\Leftrightarrow\dfrac{\left(3x-1\right).2-\left(3x-6\right)-\left(5-3x\right).4}{8}>1\)

\(\Leftrightarrow\dfrac{6x-2-3x+6-20+12x}{8}>1\)

<=> 15x - 16 > 8

<=> 15x > 24

<=> x > 8/5

Ta có: \(\dfrac{3x-1}{4}-\dfrac{3\left(x-2\right)}{8}-1>\dfrac{5-3x}{2}\)

\(\Leftrightarrow2\left(3x-1\right)-3\left(x-2\right)-8>4\left(5-3x\right)\)

\(\Leftrightarrow6x-2-3x+6-8>20-12x\)

\(\Leftrightarrow3x-4-20+12x>0\)

\(\Leftrightarrow15x>24\)

hay \(x>\dfrac{8}{5}\)

= (6x-2-3x+6-8)/8=(20-12x)/8

= 12x-3x+6x=20+8-6

<=>21x=22

<=>x=22/21

(Ủa đúng không ha)

\(\dfrac{3x-1}{4}-\dfrac{3\left(x-2\right)}{8}-1>\dfrac{5-3x}{2}\)

MTC : 8

\(\Rightarrow\dfrac{2\left(3x-1\right)}{8}-\dfrac{3\left(x-2\right)}{8}-\dfrac{8}{8}>\dfrac{4\left(5-3x\right)}{8}\)

Suy ra : 2(3x - 1) - 3(x - 2) - 8 > 4(5 - 3x)

          \(\Leftrightarrow\) 6x - 2 - 3x + 6 - 8 > 20 - 12x

          \(\Leftrightarrow\) 6x - 3x + 12x > 20 + 2 - 6 + 8

          \(\Leftrightarrow\) 15x > 24

          \(\Leftrightarrow\) x > \(\dfrac{24}{15}=\dfrac{8}{5}\)

 Vay x >\(\dfrac{8}{5}\)

Chuc ban hoc tot

2x-|3x-5|=x+1

|3x-5|=2x-(x+1)

|3x-5|=2x-x-1

|3x-5|=x-1

TH1:

3x-5=x-1

x-3x-5=1

(-2)x-5=1

(-2)x=1+5

(-2)x=6

x=6:(-2)

x=-3

TH2

3x-5=-(x-1)

3x-5=(-x)-(-1)

(-x)-3x-5=(-1)

(-4)x-5=(-1)

(-4)x=(-1)+5

(-4)x=4

x=4:(-4)

x=-1

KL: TH1: x= -3

       TH2: x= -1