cho M=((x+2/3x)+(2/x+1)-3):(2-4x/x+1)-(3x-3x^2+1/3x)
a. rut gon M
b. tim x sao cho M<1/3
c. tim xϵZ de MϵZ
giup mk vs, mk dang can gap a
cho M=|3x-2|+4x+1
a; rut gon M
b;voi gia tri nao cua x thi M =18
a)Với 3x-2 > hoặc = 0 =>x> hoặc = 2/3
=>M=|3x-2|+4x+1=3x-2+4x+1=7x-1
Với 3x-2 <0 =>x<2/3
=>M=|3x-2|+4x+1=2-3x+4x+1=x+3
b)M=18
=>|3x-2|+4x+1=18
TH1:x> hoặc = 2/3
=>7x-1=18
=>7x=19
=>x=19/7 (nhận)
TH2: x<2/3
=>x+3=18
=>x=15 (loại)
B1: rut gon bieu thuc
a, (x+y)^2-4(x-y)^2
b, 2(x-y)(x+y)+(x+y)^2+(x-y)^2
B2: tim X
a, (2X-1)^2-4(X+2)^2=9
b, 3(X-1)^2-3X(X-5)=21
B3: Cho bieu thuc
M=(x+3)^3-(x-1)^3+12x(x-1)
a, Rut gon bieu thuc tren
b, Tinh gia tri M tai x=-2/3
c, Tim x de M=16
1)a)=>x2+y2+2xy-4(x2-y2-2xy)
=>x2+y2+2xy-4.x2+4y2+8xy
=>-3.x2+5y2+10xy
CHO E=\(\left(\frac{x^3}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{2+x}\right):\left(x+2+\frac{10-x^2}{x-2}\right)\)
a) Rut gon E
b) Tim x thuoc Z sao cho E thuoc Z
1) CMR: 543-54 khong la so chinh phuong
2) Tim x:
2(x-2).(x+3)-x2+4=0
3) Rut gon
a)2(x+1)2-3(x-1)2+(x+2).(5-x)
b)(3x-1)3+(3x-1)3-6x2+9
4) A= (x-5).(x+2)+3.(x-2).(x+2)-(3x-1)2+5x2
a) rut gon A
b) tinh a khi x =1/2
\(2\left(x-2\right)\left(x+3\right)-x^2+4=0\)
\(2\left(x^2+3x-2x-6\right)-x^2+4=0\)
\(2x^2+6x-4x-12-x^2+4=0\)
\(x^2+2x-8=0\)
\(x^2+4x-2x-8=0\)
\(x\left(x+4\right)-2\left(x+4\right)=0\)
\(\left(x+4\right)\left(x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+4=0\rightarrow x=\left(-4\right)\\x-2=0\rightarrow x=2\end{cases}}\)
3/
a/ \(2\left(x+1\right)^2-3\left(x-1\right)^2+\left(x+2\right)\left(5-x\right)\)
\(=2\left(x^2+2x+1\right)-3\left(x^2-2x+1\right)+\left(5x-x^2+10-2x\right)\)
\(=2x^2+4x+2-3x^2+6x-3+5x-x^2+10-2x\)
\(=-2x^2+13x+9\)
b/ \(\left(3x-1\right)^3+\left(3x-1\right)^3-6x^2+9\)
\(=2\left(3x-1\right)^3-6x^2+9\)
\(=2\left(\left(3x\right)^3-3\left(3x\right)^2\cdot1+3\cdot3x\cdot1-1\right)-6x^2+9\)
\(=2\left(27x^3-27x^2+9x-1\right)-6x^2+9\)
\(=54x^3-54x^2+18x-2-6x^2+9\)
\(=54x^3-60x^2+18x+7\)
Số hơi dài, nên dễ tính sai -,- tính mik hay cẩu thả có j sai ibbb ạ
2) 2.(x - 2).(x + 3) - x2 + 4 = 0
<=> x2 + 2x - 8 = 0
<=> (x - 2).(x + 4) = 0
x - 2 = 0 hoặc x + 4 = 0
x = 0 + 2 x = 0 - 4
x = 2 x = -4
=> x = 2 hoặc x = -4
3) a) 2.(x + 1)2 - 3.(x - 1)2 + (x + 2).(5 - x)
= 2.(x2 + 2x + 1) - 3.(x2 - 2x + 1) + (x + 2).(5 - x)
= 2x2 + 4x + 2 - 3x2 + 6x - 3 + (x + 2).(5 - x)
= 2x2 + 4x + 2 - 3x2 + 6x - 3 + 3x - x2 + 10
= (2x2 - 3x2 - x2) + (4x + 6x + 3x) + (2 - 3 + 10)
= -2x2 + 13x + 9
b) (3x - 1)3 + (3x - 1)3 - 6x2 + 9
= 2.(3x - 1)3 - 6x2 + 9
= 2.(27x3 - 27x2 + 9x - 1) - 6x2 + 9
= 54x3 - 54x2 + 18x - 2 - 6x2 + 9
= 54x3 + (-54x2 - 6x2) + 18x + (-2 + 9)
= 54x3 - 60x + 18x + 7
4) a) A = (x - 5).(x + 2) + 3.(x - 2).(x + 2) - (3x - 1)2 + 5x2
A = (x - 5).(x + 2) + 3.(x - 2).(x + 3) - (9x2 - 6x + 1) + 5x2
A = x2 - 3x - 10 + 3x2 - 12 - (9x2 - 6x + 1) + 5x2
A = x2 - 3x - 10 + 3x2 - 12 - 9x2 + 6x - 1 + 5x2
A = (x2 + 3x2 - 9x2 + 5x2) + (-3x + 6x) + (-10 - 12 - 1)
A = 3x - 23 (1)
b) Thay x = 1/2 vào (1), ta có:
A = 3x - 23 = 3.(1/2) - 23
= 3/2 - 23
= -43/2
A khi x = 1/2 là -43/2
a, rut gon A
b, tim x de a<-1
c, tim cac gia tri nguyen cua x de A co gia tri nguyen
cho bthuc B = \(\left(\frac{x^2}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{x-2}\right)chia\left(x-2+\frac{16-x^2}{x+2}\right)\)rut gon B tính b khi /x/ = 1/2tim x de b=2tim x \(\in\) z de b \(\in\) zBài 2:
a: \(B=\left(\dfrac{x}{\left(x-2\right)\left(x+2\right)}-\dfrac{6}{3\left(x-2\right)}+\dfrac{1}{x-2}\right):\left(\dfrac{x^2-4+16-x^2}{x+2}\right)\)
\(=\left(\dfrac{x}{\left(x-2\right)\left(x+2\right)}-\dfrac{2}{x-2}+\dfrac{1}{x-2}\right):\dfrac{12}{x+2}\)
\(=\left(\dfrac{x}{\left(x-2\right)\left(x+2\right)}-\dfrac{1}{x-2}\right):\dfrac{12}{x+2}\)
\(=\dfrac{x-x-2}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{x+2}{12}=\dfrac{-1}{6\left(x-2\right)}\)
b: Thay x=1/2 vào B, ta được:
\(B=\dfrac{-1}{6\cdot\left(\dfrac{1}{2}-2\right)}=\dfrac{-1}{6\cdot\dfrac{-3}{2}}=\dfrac{1}{9}\)
Thay x=-1/2 vào B, ta được:
\(B=\dfrac{-1}{6\cdot\left(-\dfrac{1}{2}-2\right)}=-\dfrac{1}{15}\)
c: Để B=2 thì \(\dfrac{-1}{6\left(x-2\right)}=2\)
=>6(x-2)=-1/2
=>x-2=-1/12
hay x=23/12
P(x) = -3x2+4x-x3+x2+3x-1 Q(x)=3x4-x2+x3-2x-1-2x3 a) thu gon va sx giam dan b) M(x) =P(x)-Q(x) tim nghiem cua da thuc
a,
*\(P\left(x\right)\) = \(-3x^2+4x-x^3+x^2+3x-1\)
\(P(x)=-3x^2+7x-x^3-1\)
\(P(x)=-x^3-3x^2+7x-1\)
* \(Q(x)=3x^4-x^2+x^3-2x-1-2x^3\)
\(Q(x)=3x^4-x^2-x^3-2x-1\)
\(Q(x)=3x^4-x^3-x^2-1\)
b, \(M(x)=P(x)-Q(x)\)
\(M(x)=-x^3-3x^2+7x-1-3x^4+x^3+x^2+1\)
\(M(x)=-2x^2+7x-3x^4\)
1) CMR: 543-54 khong la so chinh phuong
2) Tim x:
2(x-2).(x+3)-x2+4=0
3) Rut gon
a)2(x+1)2-3(x-1)2+(x+2).(5-x)
b)(3x-1)3+(3x-1)3-6x2+9
4) A= (x-5).(x+2)+3.(x-2).(x+2)-(3x-1)2+5x2
a) rut gon A
b) tinh a khi x =1/2
Bai1,RUT GON BANG CACH NHANH NHAT
a,(x2+3x+1)2-(3x.1)2-2(x2+3x+1)(3x-1)
b,(3x3+3x+1) (3x3-3x+1)-(3x3+1)2
c,(2x2+2x+1)(2x2-2x+1)-(2x2+1)2
BAI2 TIM GTNN
A, x2 - x + 1
B. 2x2 + 6x - 5
C, 4x2 - 4x
D, x2 - 2x + y2 - 4y + 6
E, 3x2 + y2 - 2xy - 7
a) \(=\left(x^2+3x+1\right)^2-2\left(x^2+3x+1\right)\left(3x-1\right)+\left(3x-1\right)^2\)
\(=\left(x^2+3x+1-3x+1\right)^2\)
\(=\left(x^2+2\right)^2\)
b) \(=\left[\left(3x^3+1\right)^2-\left(3x\right)^2\right]-\left(3x^2+1\right)^2\)
\(=-\left(3x\right)^2=9x^2\)
c)\(=\left[\left(2x^2+1\right)^2-\left(2x\right)^2\right]-\left(2x^2+1\right)^2\)
\(=-\left(2x\right)^2=4x^2\)
Bai1:
a- 3x^2 - 7x +2 b- a(x^2 +1 ) - x (a^2 +1)
Bai2 : Cho bieu thuc
A= (2+x/ 2-x - 4x^2 / x^2 -4 - 2-x/ 2+x ) : x^2 - 3x / 2x^2 - x ^3
a- Tim DKXD roi rut gon bieu thuc A ?
b- Tim gia tri cua x de A>0?
c- Tinh gia tri cua A TRong truong hop : \vbar x-7 \vbar=4
Giup mk nha moi nguoi !!!!!!!!!
Bài 2:
a: ĐKXĐ: \(x\notin\left\{0;2;-2;3\right\}\)\(A=\left(\dfrac{-\left(x+2\right)}{x-2}-\dfrac{4x^2}{\left(x-2\right)\left(x+2\right)}+\dfrac{x-2}{x+2}\right):\dfrac{x\left(x-3\right)}{x^2\left(2-x\right)}\)
\(=\dfrac{-x^2-4x-4-4x^2+x^2-4x+4}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{-x\left(x-2\right)}{x-3}\)
\(=\dfrac{-4x^2-8x}{\left(x+2\right)}\cdot\dfrac{-x}{x-3}\)
\(=\dfrac{-4x\left(x+2\right)}{x+2}\cdot\dfrac{-x}{x-3}=\dfrac{4x^2}{x-3}\)
b: Để A>0 thì x-3>0
hay x>3