A=1.2+2.3+3.4+.......+99.100
Nhân cả 2 vế với 3, ta được:
3A=1.2.3+ 2.3.3+ 3.4.3+ 4.5.3+...... 99.100.3
= 1.2.3 + 2.3(4-1) + 3.4.(5-2) +...+ 99.100.(101-98)
= 1.2.3 + 2.3.4 -1.2.3 + 3.4.5-2.3.4 +...+ 99.100.101-98.99.100= 99.100.101
=> A = (99.100.101)/3
A = 333300

S = 1.2.3.4 + 2.3.4.5 + 3.4.5.6+...97.98.99.100

5S = (1.2.3.4+2.3.4.5+3.4.5.6+ ... + 97.98.99.100).5

5S = 1.2.3.4.(5-0) + 2.3.4.5.(6-1)+ 3.4.5.6(7-2)+......+ 97.98.99.100.(101-96)

 5S = (1.2.3.4.5 + 2.3.4.5.6 + 3.4.5.6.7 + ....+ 97.98.99.100.101) - (0.1.2.3.4 + 1.2.3.4.5 + 2.3.4.5.6+.....+96.97.98.99.100)

 5S = 97.98.99.100.101

 S= 97.98.99.100.101/5

 S=1901009880

S=1*2*3*4+2*3*4*5+....+97*98*99*100

5S=1.2.3.4.5+2.3.4.5.5+...+97.98.99.100.5

5S=1.2.3.4.(5-0)+2.3.4.5.(6-1)+...+97.98.99.100.(101-96)

5S=1.2.3.4.5-0.1.2.3.4+2.3.4.5.6-1.2.3.4.5+...+97.98.99.100.101-96.97.98.99.100

5S=(1.2.3.4.5+2.3.4.5.6+...+97.98.99.100.101)-(0.1.2.3.4+1.2.3.4.5+...+96.97.98.99.100)

5S=97.98.99.100.101

S=9505049400:5=1901009880.

S = 1.2.3.4 + 2.3.4.5 + 3.4.5.6+...97.98.99.100

5S = (1.2.3.4+2.3.4.5+3.4.5.6+ ... + 97.98.99.100).5

5S = 1.2.3.4.(5-0) + 2.3.4.5.(6-1)+ 3.4.5.6(7-2)+......+ 97.98.99.100.(101-96)

5S = (1.2.3.4.5 + 2.3.4.5.6 + 3.4.5.6.7 + ....+ 97.98.99.100.101) - (0.1.2.3.4 + 1.2.3.4.5 + 2.3.4.5.6+.....+96.97.98.99.100)

5S = 97.98.99.100.101

S= 97.98.99.100.101/5

S=1901009880 

S= 5050

P= 2550 tick nha

1,  số số hạng là :

          (100 - 1)  + 1=100 (số)

 Tổng là :

          ( 100 + 1 )x 100 : 2 = 5050 

2,  Số số hạng 

            (100 - 2 ) : 2 +1 = 45(số)

     Tổng là :

           (  100 +2) x 45 :2 =2295

S= 5050

P= 2550 tick nha

\(S=100^2-99^2+98^2-97^2+...+2^2-1^2\)

\(S=\left(100^2-99^2\right)+\left(98^2-97^2\right)+...+\left(2^2-1^2\right)\)

\(S=\left(100-99\right)\left(99+100\right)+\left(98-97\right)\left(98+97\right)+...+\left(2-1\right)\left(2+1\right)\)

\(S=1\cdot199+1\cdot195+1\cdot193+...+1\cdot3\)

\(S=199+195+193+...+3\)

\(S=\left(3+199\right)\cdot\left[\left(199-3\right):2+1\right]:2\)

\(S=202\cdot99:2\)

\(S=101\cdot99\)

\(S=9999\)

(101+100+99+98+...+3+2+1)/(101-100+99-98+...+3-2+1)

=101+100+99+98+...+3+2+1

=101 . (101 + 2) : 2

=5151

101-100+99-98+...+3-2+1

=(101-100)+(99-98)+...+(3-2)+1

=1 + 1 + 1 + ... + 1

=101- 2 + 1
=100 : 2

=50 + 1

=51

(101 + 100 + 99 + 98 + ... + 3+2+1) / (101-100+99-98+...+3-2+1) = 5151/51 = 101

bang 101

bằng 101