\(x\div4\frac{1}{3}=-2,5\)

\(\Leftrightarrow x\div\frac{13}{3}=\frac{-5}{2}\)

\(\Leftrightarrow x=\frac{-5}{2}.\frac{13}{3}\)

\(\Leftrightarrow x=\frac{-65}{6}\)

\(x\div\frac{-3}{5}=\frac{-10}{21}\)

\(\Leftrightarrow x=\frac{-10}{21}.\frac{-3}{5}\)

\(\Leftrightarrow x=\frac{30}{105}\)

\(\Leftrightarrow x=\frac{2}{7}\)

\(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)

\(\Leftrightarrow\frac{2}{3}x=\frac{1}{10}+\frac{1}{2}\)

\(\Leftrightarrow\frac{2}{3}x=\frac{6}{10}\)

\(\Leftrightarrow x=\frac{6}{10}\div\frac{2}{3}\)

\(\Leftrightarrow x=\frac{18}{20}\)

\(\Leftrightarrow x=\frac{9}{10}\)

\(\frac{1}{2}x+\frac{1}{2}=\frac{5}{2}\)

\(\Leftrightarrow\frac{1}{2}\left(x+1\right)=\frac{5}{2}\)

\(\Leftrightarrow\left(x+1\right)=\frac{5}{2}\div\frac{1}{2}\)

\(\Leftrightarrow\left(x+1\right)=5\)

\(\Leftrightarrow x=5-1\)

\(\Leftrightarrow x=4\)

\(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\)

\(\Leftrightarrow\frac{-2}{3}-\frac{2x}{3}+\frac{5}{3}=\frac{3}{2}\)

\(\Leftrightarrow1-\frac{2x}{3}=\frac{3}{2}\)

\(\Leftrightarrow\frac{2x}{3}=1-\frac{3}{2}\)

\(\Leftrightarrow\frac{2x}{3}=\frac{-1}{2}\)

\(\Leftrightarrow x=\frac{-1}{2}\div\frac{2}{3}\)

\(\Leftrightarrow x=\frac{-3}{4}\)

\(\frac{2}{5}x+\frac{1}{2}=\frac{-3}{4}\)

\(\Leftrightarrow\frac{2}{5}x=\frac{-3}{4}-\frac{1}{2}\)

\(\Leftrightarrow\frac{2}{5}x=\frac{-5}{4}\)

\(\Leftrightarrow x=\frac{-5}{4}\div\frac{2}{5}\)

\(\Leftrightarrow x=\frac{-25}{8}\)

(x-2)²-(x-3)(x-3)=6

x²-2.x.2+2²-x²-3²=6

(x²-x²)-4x+(2²⁺3²)=6

-4x+13=6

-4x=6-13=-7

x=-7:(-4)=1,75

1) |2x-1|=-19-x<=> \(\left[\begin{array}{nghiempt}2x-1=-19-x\\2x-1=19+x\end{array}\right.\)=> x=-6 hoặc x=20

2) |4-3x|=2x-10<=>\(\left[\begin{array}{nghiempt}4-3x=2x-10\\4-3x=10-2x\end{array}\right.\)=> x= 14/6 hoặc x=-6

3) |x|=3+2x<=> \(\left[\begin{array}{nghiempt}x=-3-2x\\x=3+2x\end{array}\right.\)=> x=-1 hoặc x=-3

1) - Nếu 2x - 1 < 0 thì -2x + 1 = -19 - x => -x = -20 => x = 20

    - Nếu 2x - 1 > 0 thì 2x - 1 = -19 - x => 3x = -18 => x = -6

2) - Nếu 4 - 3x < 0 thì -4 + 3x = 2x - 10 => 6 = -x => x = -6

    - Nếu 4 - 3x > 0 thì 4 - 3x = 2x - 10 => 14 = 5x => x = \(\frac{14}{5}\)

3) - Nếu x < 0 thì -x = 3 + 2x => -3x = 3 => x = -1

    - Nếu x > 0 thì x = 3 + 2x => -x = 3 => x = -3

1.

\(\left|2x-1\right|=-19-x\)

\(2x-1=\pm\left(-19-x\right)\)

TH1:

\(2x-1=-19-x\)

\(2x+x=-19-1\)

\(3x=-20\)

\(x=-\frac{20}{3}\)

TH2:

\(2x-1=19+x\)

\(2x-x=19-1\)

\(x=18\)

Vậy x = -20/3 hoặc x = 18

2.

\(\left|4-3x\right|=2x-10\)

\(4-3x=\pm\left(2x-10\right)\)

TH1:

\(4-3x=2x-10\)

\(-3x-2x=-10-4\)

\(-5x=-14\)

\(x=\frac{14}{5}\)

TH2:

\(4-3x=-2x+10\)

\(-3x+2x=10-4\)

\(x=-6\)

Vậy x = 14/5 hoặc x = -6

3.

\(\left|x\right|=3+2x\)

\(x=\pm\left(3+2x\right)\)

TH1:

\(x=3+2x\)

\(x-2x=3\)

\(x=-3\)

TH2:

\(x=-3-2x\)

\(x+2x=-3\)

\(3x=-3\)

\(x=-1\)

1) | 2x-1| = -19 -x

Th1:

2x -1 = -19 -x

3x = -18

x= -6

Th2:

2x -1 = -(-19 -x)

2x -1 = 19 +x

x= 20

Vậy...

2) | 4- 3x| = 2x- 10

Th1:

4 - 3x = 2x -10

5x = 14

x= 14/5

Th2:

4- 3x = -(2x-10)

4 - 3x = -2x +10

x= -6

Vậy...

3) | x| = 3+ 2x

Th1:

3 + 2x = x

x= -3

Th2:

3 + 2x = -x

3x = -3 

x= -1

Vậy...

1) không có x

2) x=14 , x=-6

3)x=-3 hoặc x= -1

1)2x-1=-(-19-x)

2x-1=19+x

2x-x=19+1

x=20

1) \(\left|2x-1\right|=-19-x\)

\(=>\orbr{\begin{cases}-19-x=2x-1\\-19-x=-\left(2x-1\right)\end{cases}=>\orbr{\begin{cases}-19+1=2x+x\\-19-x=-2x+1\end{cases}}}\)

                                                                 \(=>\orbr{\begin{cases}-18=3x\\-x+2x=1+19\end{cases}=>\orbr{\begin{cases}x=-6\\x=20\end{cases}}}\)     

2) \(\left|4-3x\right|=2x-10\)   

\(=>\orbr{\begin{cases}2x-10=4-3x\\2x-10=-\left(4-3x\right)\end{cases}=>\orbr{\begin{cases}2x+3x=4+10\\2x-10=-4+3x\end{cases}}}\)    

                                                               \(=>\orbr{\begin{cases}5x=14\\-10+4=3x-2x\end{cases}=>\orbr{\begin{cases}x=\frac{14}{5}\\x=-6\end{cases}}}\)     

3) \(\left|x\right|=3+2x\)     

\(=>\orbr{\begin{cases}3+2x=x\\3+2x=-x\end{cases}=>\orbr{\begin{cases}2x-x=-3\\2x+x=-3\end{cases}}}\)   

                                            \(=>\orbr{\begin{cases}x=-3\\3x=-3\end{cases}=>\orbr{\begin{cases}x=-3\\x=-1\end{cases}}}\)           

Ủng hộ mk nha ^_-