Part 1 : 

1. so 

2. forward

3. which

4.didn't

5. if

6. although

Part 2 : 

1.C

2.E

3.A

4.F

5.B

6.D

Part 3 : 

1. eruption

2.compelling

3.badly

4.natural 

5. not to stay 

6. didn't work / has had

8. would tell

Part 4 : 

1. didn't => haven't

2. happily => happy

3. complains => should complain

4. on => off

Part 1:

1. with

2. does

3. after

4. if

5. where

6. I won't

Part 2:

1B 2F 3A 4E 5C 6D

Part 3:

1. invited

2. will play

3. have just won

4. be cleaned

5. to take

6. beautifully

7. impression

Part 4:

1. read -> reading

2. disappointing -> disappointed

3. environment -> environmental

4. who -> that

Part 5:

1. the bad weather

2. are made to study

3. were good at learning

4. going to the English

toàn hỏi mấy cái này:)

tuổi dậy thì đó ba

Vì   

    Cơ thể tiết ra hormon sinh dục cũng khiến cơ quan sinh dục của bé phát triển to lên. Cơ thể bắt đầu mọc nhiều lông ở vùng kín. Đối với các bé gái, dậy thì là giai đoạn có những biến đổi lớn trong sinh lý, chuẩn bị hoàn thiện khả năng thụ thai và sinh con.

     Tham khảo

1 This meal didn't cost as much as I though

2 I've never seen such a bad film

3 Is that the best you can do?

4 There is less dry in the North than there is in the south of England

5 She was not expected to be so beautiful

6 The meeting went more smoothly than it did last time

7 You lead 

8 Helen earns twice as much as I do

9 The other teams have gone less games than they 

Part 6 : 

1. especially

2. with

3. goods 

4. perform

Part 7: 

1. T

2. F

3. F

4.T

\(\dfrac{-2m+1}{2}=1-2m\) \(\Leftrightarrow\) m=\(\dfrac{1}{2}\).

\(\dfrac{m-1}{2}=m-1\) \(\Leftrightarrow\) m=1.

Hai phương trình đã cho không là hai phương trình tương đương.

1a.\(nMg=\dfrac{2.4}{24}=0.1mol\Rightarrow nO2=\dfrac{0.1}{2}=0.05mol\)

\(\Rightarrow V_{O2}=0.05\times22.4=11.2l\)

b.nMg = nMgO = 0.1 mol

\(\Rightarrow mMgO=0.1\times40=4g\)

2.4Al + 3O2 -> 2Al2O3

a.\(nAl=\dfrac{1.35}{27}=0.05mol\Rightarrow nO2=\dfrac{0.05\times3}{4}=0.0375mol\)

\(V_{O2}=0.0375\times22.4=0.84l\)

b.\(nAl2O3=\dfrac{0.05}{2}=0.025mol\)

\(mAl2O3=0.025\times102=2.55g\)