a, 36:{336:[200–(12+8.20)]}

= 36:{336:[200–(12+160)]}

= 36:{336:[200–172]}

= 36:{336:28}

= 36:12 = 3

b, {145–[130–(246–236)]:2}.5

= {145–[130–10:2]}.5

= {145–130}.5

= 20.5 = 100

c, 100:{250:[450–(4. 5 3 – 2 2 .25]}

= 100:{250:[450–400]}

= 100:{250:50}

= 100:5 = 20

d, 798+100:[16–2.( 5 2 –22)]

= 798+100:10

= 798+10 = 808

e, (6954+1525:5+47.19).(29–58.2)

= (6954+1525:5+47.19).0 = 0

f,  2 4 .157– 2 4 .58+16

= 16.(157–58+1) = 1600

c 

\(=160:\left\{17+\left[9\cdot5-\left(14+2^3\right)\right]\right\}\)   

\(=160:\left\{17+\left[45-\left(14+8\right)\right]\right\}\)   

\(=160:\left\{17+\left[45-22\right]\right\}\)   

\(=160:\left(17+23\right)\)   

\(=160:40\)   

\(=4\)   

d 

\(=798+100:\left[16-2\cdot\left(25-22\right)\right]\)   

\(=798+100:\left(16-2\cdot3\right)\)      

\(=798+100:\left(16-6\right)\)   

\(=798+100:10\)   

\(=798+10\)   

\(=808\)

a, 798 + 100 : [ 19 - 2 [ 5² - 22 ]²

= 798 + 100 : [ 19 - 18 ]

= 798 + 100 : 1

= 898

b, 921 . 172 . 13 - 921 . 885

= 921 . ( 172 + 13 - 85 )

= 921 . 100

= 92100

c, 5² . [[ 5² - 3 ] : 11 ] - 16 + 2 . 15

= 5² . 2 - 16 + 30

= 50 - 16 + 30

= 64

CÁC BẠN GIÚP MÌNH VỚI ! CẢM ƠN CÁC BẠN RẤT NHIỀU !!!

2006/2007<2007/2008

16/39>15/40

37/67<377/677

22/67<51/512

22/67<51/152

\(\frac{2006}{2007}< \frac{2007}{2008}\)

\(\frac{39}{16}>\frac{15}{40}\)

\(\frac{37}{67}< \frac{377}{677}\)

\(\frac{22}{67}< \frac{51}{512}\)

\(\frac{22}{67}< \frac{51}{512}\)

Ủng hộ mk nha

Bạn chỉ cần tìm phần bù của các p/s thui

   2³.19 - 2³.14 + 1²⁰²⁰

= 2³.(19 - 14) + 1

= 8.5 + 1

= 41

    10² - [60: (5⁶: 5⁴ - 3.5)]

= 100 - [60: (5² - 15)]

= 100 - [60: (25 - 15)]

= 100 - [60 : 10]

= 100 - 6

= 94 

   160: {17 + [3².5 - ( 14 + 2⁷:2⁴)]}

= 160: {17 + [9.5 - (14 + 2³)]}

= 160: {17 + [45 - (14 + 8)]}

= 160: {17 + [45 - 22]}

= 160: {17 + 23}

= 160 : 40

= 4

a: \(-472+\left(235-28\right)-\left(35-350\right)\)

\(=-472+235-28-35+350\)

\(=\left(-472-28\right)+\left(235-35\right)+350\)

=-500+350+200

=50

b: \(91\cdot172+91\cdot13-91\cdot85\)

\(=91\cdot\left(172+13-85\right)\)

\(=91\cdot100=9100\)

c: \(798-298:\left[19-2\left(5^2-22\right)^2\right]\cdot1^{2023}\)

\(=798-298:\left[19-2\left(25-22\right)^2\right]\)

\(=798-298:\left[19-2\cdot3^2\right]\)

\(=798-298:\left(19-18\right)\)

=798-298

=500

a,25/100 +19/22+19/35+3/4+3/22+16/35

=(19/22+3/22)+(19/35+16/35)+(25/100+3/4)

=   22/22 + 35/35 + ( 1/4 + 3/4)

= 22/22 + 35/35 + 4/4

= 1 + 1 + 1

= 3

b, 2/5 : 4/7 - 2/5 : 2/3

=(2/5 - 2/5) : (4/7 : 2/3)

= 0 : 6/7

=0

tất cả các số kia là đều phần hết

1) \(\frac{25}{100}+\frac{19}{22}+\frac{19}{35}+\frac{3}{4}+\frac{3}{22}+\frac{16}{35}\)

\(=\frac{1}{4}+\frac{19}{22}+\frac{19}{35}+\frac{3}{4}+\frac{3}{22}+\frac{16}{35}\)

\(=\left(\frac{1}{4}+\frac{3}{4}\right)+\left(\frac{19}{22}+\frac{3}{22}\right)+\left(\frac{19}{35}+\frac{16}{35}\right)\)

\(=1+1+1\)

\(=3\)

2) \(\frac{2}{5}:\frac{4}{7}-\frac{2}{5}:\frac{2}{3}\)

\(=\frac{2}{5}:\left(\frac{4}{7}-\frac{2}{3}\right)\)

\(=\frac{2}{5}:\frac{-2}{21}\)

\(=-\frac{21}{5}\)

=))