a,3^x.3=243

   3^x+1=3⁵

     x+1=5 

         x=5-1

         x=4

Vậy x=4

b,x²⁰=x

Vô lí vì 1 ko bằng 20

Vậy x E 0

c,2^x.16²=1024

   2^x.2⁸=2¹⁰

   2^x+8=2¹⁰

     x+8=10

         x=10-8

         x=2

Vậy x=2

d,64.4^x=16⁸

     4³.4^x=4¹⁶

     4^3+x=4¹⁶

       3+x=16

           x=16-3

           x=13

Vậy x=13

cảm ơn

tui hổng có biết làm mà

64 . 4^x = 168

<=> 43. 4^x = 416

=> 3 + x = 16

<=> x = 13

Vậy x = 13

2^x.16² = 1024

<=> 2^x. 2⁸ = 210

=> x + 8 = 10

<=> x = 2

Vậy x = 2

b: Ta có: \(2^x\cdot16^2=1024\)

\(\Leftrightarrow2^x\cdot2^8=2^{10}\)

\(\Leftrightarrow x+8=10\)

hay x=2

  64.4^x=16³

  2⁶. (2²)^x = (2⁴)³

=> 2⁶. 2^2x = 2¹²

        2^2x   = 2 ¹² : 2⁶

       2^2x   = 2⁶

  =>  2x = 6

         x = 6 :2

         x=3

- Vậy x =3

64.4^x = 16⁸

=> 4³.4^x = (4²)⁸

=> 4^{x + 3} = 4^2.8

=> 4^{x + 3} = 4¹⁶

=> x + 3 = 16

=> x = 13

Vậy x = 13

64.4^x=16⁸

4³.4^x=(4²)⁸

4³.4^x=4¹⁶

4^3+x=4¹⁶

=> 3+x=16

          x=16-3

          x=13

vậy x=13

hfdhbzd,jzb kjhbj

1. \(2^x-26=6\)

\(\Rightarrow2^x=6+26\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

2. \(64\cdot4^x=16^8\)

\(\Rightarrow4^3\cdot4^x=4^{16}\)

\(\Rightarrow4^x=4^{16}:4^3\)

\(\Rightarrow4^x=4^{13}\)

\(\Rightarrow x=13\)

3. \(\left(2x-1\right)^4=16\)

\(\Rightarrow\left(2x-1\right)^4=2^4\)

\(\Rightarrow2x-1=2\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\dfrac{3}{2}\)

4. \(\left(2x+1\right)^3=125\)

\(\Rightarrow\left(2x+1\right)^3=5^3\)

\(\Rightarrow2x+1=5\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=2\)

x=13

h nha lấy 16^8 : cho 64 ra kq rồi cho mũ 4 lên là dc k mik nha

ban giai gium di

\(64\cdot4^x=16^8\)

\(2^6\cdot2^{2x}=2^{32}\)

\(2^{6+2x}=2^{32}\)

=> 6 + 2x = 32

=> 2x = 26

=> x = 13

a) 2^x . 16^2 = 1024                          b) 64 . 4^x =  16^8                    c) 2^x = 16

=> 2^x . 256 = 1024                             => 64 . 4^x  = (4^2) ^ 8               => 2^x  = 2^4

=> 2^x          = 1024 : 256                    =>   4^3 . 4^x  =  4^16                  => x     = 4

=> 2^x           =  4                                 =>             4^x  = 4^16 : 4^3

=>  2^x           = 2^2                             =>              4^x  =  4^13

                                                              =>                 x   =  13 

=>      x           = 2

a) \(2^x.16^2=1024\Rightarrow2^x=1024:16^2=2^{10}:\left(2^4\right)^2=2^{10}:2^8=2^2\)\(\Rightarrow x=2\)

b) \(64.4^x=16^8\Rightarrow4^x=16^8:64=\left(4^2\right)^8:4^3=4^{16}:4^3=4^{13}\Rightarrow x=13\)

c)\(2^x=16\Rightarrow2^x=2^4\Rightarrow x=4\)

64 . 4^x = 16⁸ 

<=> 2⁶ . 2^2x = 2³²

<=> 2^2x = 2²⁶

<=> 2x = 26

<=> x = 13

\(64.4^x=16^8\)

\(8^2.4^x=16^8\)

\(4^x=16^8:8^2\)

\(4^x=4^{13}\)

\(\Rightarrow x=13\)

Vậy \(x=13\)

2^x.16² = 1024

=> 2^x.(2⁴)² = 2¹⁰

=> 2^{x + 4.2} = 10

=> x + 8 = 10

=> x = 2

vậy_

64.4^x = 16⁸

=> 4³.4^x = (4²)⁸

=> 4^{3 + x} = 4¹⁶

=> 3 + x = 16

=> x = 13

vậy_

2^x = 16

=> 2^x = 2⁴

=> x = 4

vậy_