204//200///205
205×2005-5/200+204×205
Tính nhanh: 199-200+201-202+203-204+205-206+207
199 - 200 + 201 - 202 + 203 - 204 + 205 - 206 + 207
= ( 199 - 200 ) + ( 201 - 202 ) + ( 203 - 204 ) + ( 205 - 206 ) + 207
= ( -1 ) + ( -1 ) + ( -1 ) + ( -1 ) + 207
= -4 + 207
= 203
199 - 200 + 201 - 202 + 203 - 204 + 205 - 206 + 207 = 203
199-200+201-202+203-204+205-206+207
=203
Tính nhanh: 204 x 207 + 200 / 207 x 205 - 7
204 x 207 +200 / 207 x 205 -7
= 204 x 207 +207 - 7 / 207 x 205 -7
= 207 x ( 204 +1 ) -7 / 207 x 205 -7
= 207 x 205 -7 / 207 x 205 -7
= 1
tick nha !
tính nhanh
a:132+76+868+524+500
b:200-201+202-203+204-205+206-207+208-209+210
a) 132 + 76 + 868 + 524 + 500
= (132 + 868) + (76 + 524) + 500
= 1000 + 600 + 500
= 2100
b) 200 - 201 + 202 - 203 + 204 - 205 + 206 - 207 + 208 - 209 + 210
= (200 + 210) + (-201 - 209) + (202 + 208) + (-203 - 207) + (204 + 206) - 205
= 410 - 410 + 410 - 410 + 410 - 205
= 0 + 0 + 205
= 205
B=1/101+1/102+1/203+1/204+1/205+...........1/199+1/200
Chứng tỏ b >5/8
ai giải ra nhanh nhất đúng mình like
CMR:
206205-205205 ⋮ 204
tìm x \(\in\)Z biết x+(x+1)+(x+2)+...+204+205=205
Sửa đề :
x + x + 1 + x + 2 + ... + x + 205 = 205
( x + x + ... + x ) + ( 1 + 2 + ... + 205 ) = 205
Số số hạng là :
( 205 - 1 ) : 1 + 1 = 205 ( số )
Tổng là :
( 205 + 1 ) . 205 : 2 = 21115
206x + 21115 = 205
206x = -20910
x = -101,5048544
x+(x+1)+(x+2)+....+204+205=205
=>x+(x+1)+(x+2)+....+204=0
mik nghĩ là sai đề bạn ơi
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+205\right)=205\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+....+205\right)\)
\(206x+\left[\left(205-1\right):1+1\right].\left(205+1\right):2\)
\(206x+2115=205\)
\(=>...\)
203 + 204 + 205 + ....................+300=
Tính tổng
TL:
203+204+......+300
\(=\frac{\left(203+300\right).\left[\left(300-203\right)+1\right]}{2}\)
\(=\frac{503.98}{2}\)
\(=24647\)
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.......+\frac{1}{205}}{\frac{204}{1}+\frac{203}{2}+\frac{202}{3}+....+\frac{1}{204}}\)
\(\)Đặt \(A=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}...+\frac{1}{205}}{\frac{204}{1}+\frac{203}{2}+\frac{202}{3}+...+\frac{1}{204}}=\frac{B}{C}\)
Biến đổi C:
\(C=\left(\frac{204}{1}+1\right)+\left(\frac{203}{2}+1\right)+\left(\frac{202}{3}+1\right)+...+\left(\frac{1}{204}+1\right)-204\)
\(=205+\frac{205}{2}+\frac{205}{3}+..+\frac{205}{204}+\frac{205}{205}-205\)
\(=205.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{205}\right)\)
\(\Rightarrow A=\frac{\frac{1}{2}+\frac{1}{3}+...+\frac{1}{205}}{205.\left(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{205}\right)}=\frac{1}{205}\)