\(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot...\cdot\dfrac{7}{8}=\dfrac{1}{8}\)

`= 1/2 xx 2/3 xx...xx 7/8`

`= 1/8`

\(=\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{6}{7}\times\dfrac{7}{8}\\ =\dfrac{1}{8}\)

\(B=\left(1-\dfrac{1}{3}\right)\cdot\left(1-\dfrac{1}{6}\right)\cdot\left(1-\dfrac{1}{10}\right)\cdot\left(1-\dfrac{1}{15}\right)\cdot...\cdot\left(1-\dfrac{1}{780}\right)\)

\(B=\left(1-\dfrac{1}{3+6+10+15+...+780}\right)\)

\(B=\left(1-\dfrac{1}{\left(780-3\right)\div3+1}\right)\)

\(B=\left(1-\dfrac{1}{260}\right)\)

\(B=\dfrac{259}{260}\)

Ta có: \(\dfrac{-5}{13}\cdot\dfrac{3}{7}-\dfrac{2}{17}\cdot\dfrac{8}{13}+\dfrac{5}{13}\cdot\dfrac{1}{7}\)

\(=\dfrac{5}{13}\left(-\dfrac{3}{7}+\dfrac{1}{7}\right)-\dfrac{2}{17}\cdot\dfrac{8}{13}\)

\(=\dfrac{5}{13}\cdot\dfrac{-2}{7}-\dfrac{2}{17}\cdot\dfrac{8}{13}\)

\(=\dfrac{-10}{91}-\dfrac{16}{221}\)

\(=\dfrac{-282}{1547}\)

\(\dfrac{-5}{13}.\dfrac{3}{7}-\dfrac{2}{17}.\dfrac{8}{13}+\dfrac{5}{13}.\dfrac{1}{7}\) 

\(=\dfrac{5}{13}.\dfrac{-3}{7}-\dfrac{2}{17}.\dfrac{8}{13}+\dfrac{5}{13}.\dfrac{1}{7}\)

\(=\dfrac{5}{13}.\left(\dfrac{-3}{7}+\dfrac{1}{7}\right)+\dfrac{-2}{17}.\dfrac{8}{13}\) 

\(=\dfrac{5}{13}.\dfrac{-2}{7}+\dfrac{-2}{13}.\dfrac{8}{17}\)

\(=\dfrac{-2}{13}.\dfrac{5}{7}+\dfrac{-2}{13}.\dfrac{8}{17}\) 

\(=\dfrac{-2}{13}.\left(\dfrac{5}{7}+\dfrac{8}{17}\right)\) 

\(=\dfrac{-2}{13}.\dfrac{141}{119}\) 

\(=\dfrac{-282}{1547}\)

⇔\(x\) x 1=\(\dfrac{8}{3}\)

⇔\(x\) =\(\dfrac{8}{3}\)

Vậy \(x\)=\(\dfrac{8}{3}\)

\(x\times3\times\dfrac{1}{3}=2\dfrac{2}{3}\\x\times3\times\dfrac{1}{3}=\dfrac{8}{3}\\ x\times3=\dfrac{8}{3}:\dfrac{1}{3}\\ x\times3=8\\ x=8:3\\ x=\dfrac{8}{3}\)

\(\Rightarrow x=\dfrac{8}{3}\)

\(\Rightarrow y\times\left(2+\dfrac{1}{5}\right)=\dfrac{8}{5}\\ \Rightarrow y\times\dfrac{11}{5}=\dfrac{8}{5}\\ \Rightarrow y=\dfrac{8}{5}:\dfrac{11}{5}=\dfrac{8}{5}\times\dfrac{5}{11}=\dfrac{8}{11}\)

C1 : ( 2,45 + 7,55 ) x 2,75

= 10 x 2,75

= 27,5

C2 : ( 2,45 + 7,55 ) x 2,75
= 2,45 x 2,75 + 7,55 x 2,75
= 6,7375 + 20,7625
= 27,5

C1 : ( 25,5 - 17,15 ) x 100

= 8,35 x 100

= 835

C2 : ( 25,5 - 17,15 ) x 100
= 25,5 x 100 - 17,15 x 100
= 2550 - 1715
= 835

C1 : 5 x 67,35 x 20

= 336,75 x 20

= 6735

C2 : 5 x 67,35 x 20

= 5 x 20 x 67,35

= 100 x 67,35

= 6735

Nhân cả hai vế với 12 (đỡ mất công quy đồng kiểu kia), ta tìm x sao cho:

\(10x-8=3x+8\Leftrightarrow7x=16\Leftrightarrow x=\frac{16}{7}\)

Vậy...