Tìm x:
8.(3+x)=24
Tìm x :
● x × 2 = 8..........................
● x × 3 = 15..........................
● 3 × x = 24..........................
Phương pháp giải:
Muốn tìm một thừa số ta lấy tích chia cho thừa số kia.
Lời giải chi tiết:
● x × 2 = 8
x = 8 : 2
x = 4
● x × 3 = 15
x = 15 : 3
x = 5
● 3 × x = 24
x = 24 : 3
x = 8
Tìm x
a. (x + 1) + (x + 2) + (x + 3) = 24
b. x + x + 8 = 24
a ) (x+1)+(x+2)+(x+3)=24
=>x+1+x+2+x+3=24
=>(x+x+x)+(1+2+3)=24
=>3x+6=24
=>3x = 24-6
=> 3x = 18
=> x = 18 : 3
=> x = 3
b )x+x+8 =24
=>2x = 24-8
=> 2x = 16
=> x = 16 : 2
=> x =8
k cho mh nha
.
a. ( x+1 )+(x+2)+(x+3)=24
x+1+x+2+x+3=24
x+x+x+1+2+3=24
3*x+(1+2+3)=24
3*x+6=24
3*x=24-6
3*x=18
x=18:3
x=6
b.x+x+8=24
2*x+8=24
2*x=24-8
2*x=16
x=16:2
x=8
Lần sau mấy bài dễ thế này em nên tư duy một tí nha!
Tìm x
a. X - 24/8 = 8
b. 76/18 - X x 17/3 = 4/9
`a) x - 24/8 = 8`
`x = 8 + 24/8`
`x = 11`
`b) 76/18 - x × 17/3 = 4/9`
`x × 17/3 = 76/18 - 4/9`
`x × 17/3 = 34/9`
`x = 34/9 : 17/3`
`x = 2/3`
a, X = 8 + 24/8
X = 11
b, X x 17/3 = 76/18 - 4/9
X x 17/3 = 34/9
X = 34/9 : 17/3
X = 2/3
Bài 2: Tìm x
a. (x + 1) + (x + 2) + (x + 3) = 24
b. x + x + 8 = 24
Bài 2: Tìm x:
a. (x + 1) + (x + 2) + (x + 3) = 24 (x + x + x) + (1 +2 + 3) = 24 x × 3 + 6 = 24 x × 3 = 24 - 6 x × 3 = 18 x = 18 : 3 x = 6 | b. x + x + 8 = 24 2 × x + 8 = 24 2 × x = 24 - 8 2 × x = 16 x = 16 : 2 x = 8 |
Bài 1: Tìm x
x-7/12.x=5/24-3/8.x
(x-1/2).(-3-x/2)=0
x-3/-2=-8/x-3
=) (x-3).(x-3)=(-2).(-8)
(x-3) mũ 2 =16
\(a,x-\dfrac{7}{12}x=\dfrac{5}{24}-\dfrac{3}{8}x\)
\(\Leftrightarrow\dfrac{5}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
\(\Leftrightarrow\dfrac{19}{24}x=\dfrac{5}{24}\Leftrightarrow x=\dfrac{5}{19}\)
Vậy x = 5/19
\(b,\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{1}{2}=0\\-3-\dfrac{x}{2}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-6\end{matrix}\right.\)
Vậy x = 1/2 hoặc x = -6
\(c,\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
\(\Leftrightarrow\left(x-3\right)^2=16\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)
Vậy x = 7 hoặc x = -1
Tìm x biết: a) \(\dfrac{6}{-x}=\dfrac{x}{-24}\) b) \(x-\dfrac{7}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
c)\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\) d) \(\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
e) \(\dfrac{9}{x}=\dfrac{-35}{105}\) f) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
a: =>6/x=x/24
=>x^2=144
=>x=12 hoặc x=-12
b: =>x(1-7/12+3/8)=5/24
=>x*19/24=5/24
=>x=5/24:19/24=5/19
c: =>(x-1/3)^2=1+3/4+1/2=9/4
=>x-1/3=3/2 hoặc x-1/3=-3/2
=>x=11/6 hoặc x=-7/6
d: =>(x-3)^2=16
=>x-3=4 hoặc x-3=-4
=>x=-1 hoặc x=7
e: =>9/x=-1/3
=>x=-27
f: =>x-1/2=0 hoặc -x/2-3=0
=>x=1/2 hoặc x=-6
tìm X:
3/8 + ( X - 5/24 ) :2/3 = 1
tìm X.
3/8 + ( x - 5/24 ) :2/3 = 1
3/8+(x-5/24)=2/3
x-5/24=7/24
x=1/2
vậy x=1/2
1) Tìm x biết:
a)-(2x-16)-(x-8)=24
b)-3.(-x-4)-x=42-24
c)|2x-4|-16=-8
Tìm x
8. 3^x + 3. 2^x - 6^x = 24
8.3x+3.2x-6x=24
=>6x-8.3x-(3.2x-24)=0
=>3x(2x-8)-3(2x-8)=0
=>(2x-8)(3x-3)=0
=>\(\orbr{\begin{cases}2^x-8=0\\3^x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}2^x=8\\3^x=3\end{cases}\Rightarrow}\orbr{\begin{cases}2^x=2^3\\3^x=3^1\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=1\end{cases}}}\)
Vậy x=3 hoặc x=1
tìm x biet x-(3/8+x-7và5/24):16và2/3=0