Viết các tích sau dưới dạng một lũy thừa :
a, \(2^5\times8^4\)
b, \(12^3\times3^3\)
c, \(25^6\times125^3\)
d, \(3\times3^2\times3^3\times...\times3^{98}\times3^{99}\times3^{100}\)
Tính (theo mẫu).
Mẫu: \(\dfrac{2}{5}\times3=\dfrac{2}{5}\times\dfrac{3}{1}=\dfrac{2\times3}{5\times1}=\dfrac{6}{5}\) Ta có thể viết gọn như sau: \(\dfrac{2}{5}\times3=\dfrac{2\times3}{5}=\dfrac{6}{5}\) |
a) \(\dfrac{9}{11}\times8\) b) \(\dfrac{4}{5}\times1\) c) \(\dfrac{15}{8}\times0\)
a) \(\dfrac{9}{11}\times8=\dfrac{9\times8}{11}=\dfrac{72}{11}\)
b) \(\dfrac{4}{5}\times1=\dfrac{4\times1}{5}=\dfrac{4}{5}\)
c) \(\dfrac{15}{8}\times0=\dfrac{15\times0}{8}=\dfrac{0}{8}=0\)
a: 9/11*8=(9*8)/11=72/11
b: 4/5*1=(4*1)/5=4/5
c: 15/8*0=(15*0)/8=0/8=0
Tính S = \(\frac{5\times2^{30}\times6^2\times3^{15}-2^3\times8^9\times3^{17}\times21}{21\times2^{29}\times3^{16}\times4-2^{29}\times\left(3^4\right)^5}\)
Ta có : S = \(\frac{5.2^{30}.6^3.3^{15}-2^3.8^9.3^{17}.21}{21.2^{29}.3^{16}.4-2^{29}.\left(3^4\right)^5}=\frac{5.2^{30}.\left(2.3\right)^3.3^{15}-2^3.\left(2^3\right)^9.3^{17}.3.7}{3.7.2^{29}.3^{16}.2^2-2^{29}.3^{20}}=\frac{5.2^{33}.3^{18}-2^{30}.3^{18}.7}{3^{17}.7.2^{31}-2^{29}.3^{20}}\)
\(=\frac{2^{30}.3^{18}.\left(5.2^3-7\right)}{3^{17}.2^{29}.\left(7.2^2-3^3\right)}=2.3.33=198\)
\(\dfrac{4^{10}\times9^6+3^{12}\times8^5}{6^{13}\times4-2^{16}\times3^{12}}\)
\(\dfrac{2^4\times2^6}{\left(2^5\right)^2}-\dfrac{2^5\times15^3}{6^3\times10^2}\)
\(\dfrac{\left(-2\right)^{10}\times3^{31}+2^{40}\times\left(-3\right)^6}{\left(-2\right)^{11}\times\left(-3\right)^{31}+2^{41}\times3^6}\)
giải chi tiết giúp mình nhé
M=\(\frac{9^4\times27^5\times3^6\times3^4}{3^8\times81^4\times243\times8^2}\)
N=4\(\frac{4^6\times9^5\times6^9\times120}{8^4\times3^{12}-6^{11}}\)
Tính:
\(\frac{exp\left(24\right)}{\frac{25}{2}\%}\times12\frac{5}{4}+\left|-54^2\right|\times\pi+6\)\(\times7\sqrt{65}+\frac{7\times7^2\times7^3\times7^4}{3\times3^2\times3^3\times3^4}\)
Bài 5 : Tính nhanh :
a, A =\(1993^{1^{2\times3\times4\times.....\times1994}}\)
b, B = \(1994^{\left(225-1^2\right)\times\left(225-2^2\right)\times....\times\left(225-50^2\right)}\)
c, C =\(\frac{2^{10}\times3^{31}+2^{40}\times3^6}{2^{11}\times3^{31}+2^{41}\times3^6}\)
d, D = \(\left(1+2+2^2+2^3+.....+2^{2003}+2^{2004}\right)-2^{2005}\)
Ta có : D = (1 + 2 + 22 + 23 + ....... + 22004) - 22005
Đặt A = 1 + 2 + 22 + 23 + ....... + 22004
=> 2A = 2 + 22 + 23 + ....... + 22005
=> 2A - A = 22005 - 1
=> A = 22005 - 1
Thay vào ta có : D = (1 + 2 + 22 + 23 + ....... + 22004) - 22005
=> D = 22005 - 1 - 22005
=> D = -1
cậu làm còn thiếu bước kìa Nguyễn Việt Hoàng
1.Tính giá trị tuyệt đối:(hẹp me)
a)\(\frac{72^3\times54^2}{108^4}\)
b)\(\frac{3^{10}\times11+3^{10}\times5}{3^9\times2^4}\)
c)\(\left(1:\frac{1}{7}\right)^2[\left(2^2\right)^3:2^5]\times\frac{1}{49}\)
d)\(\frac{4^6\times3^5-2^{12}\times3^6}{2^{12}\times9^3+8^4\times3^5}\)
M=\(\frac{9^4\times27^5\times3^6\times3^4}{3^8\times81^4\times243\times8^2}\)
Tính nhanh:\(\frac{1\times2\times3+2\times4\times6+3\times6\times9+4\times8\times12+5\times10\times15}{1\times3\times5+2\times6\times10+3\times9\times15+4\times12\times20+5\times15\times25}-\frac{1+2+3+2+4+6+3+6+9+4+8+12+5+10+15}{1+3+5+2+6+10+3+9+15+4+12+20+5+15+25}\)