\(D=\frac{-1}{5}.\left(\frac{9}{8}+\frac{16}{32}-\frac{12}{46}\right)-\frac{9}{17}\)

\(D=\frac{-1}{5}.\frac{251}{184}+\frac{-9}{17}\)

\(D=\frac{-251}{920}+\frac{-9}{17}\)

\(D=\frac{-12547}{15640}\)

\(D=\frac{-1}{5}\cdot\left[\frac{9}{8}+\frac{16}{32}+\frac{12}{46}\right]-\frac{9}{17}\)

\(D=\frac{-1}{5}\cdot\left[\frac{9}{8}+\frac{1}{2}-\frac{6}{23}\right]-\frac{9}{17}\)

\(D=\frac{-1}{5}\cdot\left[\frac{9}{8}+\frac{4}{8}-\frac{6}{23}\right]-\frac{9}{17}\)

\(D=\frac{-1}{5}\cdot\left[\frac{15}{8}-\frac{6}{23}\right]-\frac{9}{17}\)

\(D=\frac{-1}{5}\cdot\left[\frac{345}{184}-\frac{48}{184}\right]-\frac{9}{17}\)

\(D=\frac{-1}{5}\cdot\frac{297}{184}-\frac{9}{17}\)

Tự tính

a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)

yutyugubhujyikiu

a)\(\frac{243}{22}\)

b)\(\frac{4}{5}=0,8\)

giúp với ạ

giải dc nhưng mà hoi lâu

a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)

\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)

a) \(\frac{17}{9}-\frac{17}{9}:\left(\frac{7}{3}+\frac{1}{2}\right)\)

= \(\frac{17}{9}-\frac{17}{9}:\frac{17}{6}\)

= \(\frac{17}{9}-\frac{2}{3}\)

= \(\frac{11}{9}\)

b) \(\frac{4}{3}.\frac{2}{5}-\frac{3}{4}.\frac{2}{5}\)

= \(\frac{2}{5}.\left(\frac{4}{3}-\frac{3}{4}\right)\)

= \(\frac{2}{5}.\frac{7}{12}\)

= \(\frac{7}{30}\)

Mình lười làm quá, hay mình nói kết quả cho bn thôi nha

c) -6

d) 3

e) 3

g) 12

h) \(\frac{23}{18}\)

i) \(\frac{-69}{20}\)

k) \(\frac{-1}{2}\)

l) \(\frac{49}{5}\)

8/5:(8/5.5/4) / 16/25-1/25 + 1:4/7 / (50/9-9/4).36/17) + 0,6.0,5:2/5

= 8/5:8/5:5/4 / 3/5 + 7/4 / 50/9.36/17-9/4.36/17 + 0,3.5/2

= 4/5:3/5 + 7/4 / 200/17-81/17 + 3/10.5/2

= 4/5.5/3 + 7/4 / 119/17 + 3/4

= 4/3 + 7/4 : 7 + 3/4

= 4/3 + 4 + 3/4

= 16/12 + 48/12 + 9/12

= 73/12

☆★☆★☆

73/12

a)   \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)=\frac{31}{23}-\frac{7}{32}-\frac{8}{23}=1-\frac{7}{32}=\frac{25}{32}\)

b)   \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)

\(=\frac{1}{3}+\frac{12}{67}+\frac{13}{41}-\frac{79}{67}+\frac{28}{41}\)

\(=\frac{1}{3}-\left(\frac{79}{67}-\frac{12}{67}\right)+\left(\frac{13}{41}+\frac{28}{41}\right)\)

\(=\frac{1}{3}-1+1=\frac{1}{3}\)

d)   \(\frac{1}{7}.\frac{1}{3}+\frac{1}{7}.\frac{-1}{3}+\frac{17}{19}=\frac{1}{7}.\left(\frac{1}{3}-\frac{1}{3}\right)+\frac{17}{19}=\frac{17}{19}\)

e)  \(\frac{3}{5}.\frac{7}{9}+\frac{7}{5}.\frac{2}{9}=\frac{7}{5}.\left(\frac{3}{9}+\frac{2}{9}\right)=\frac{7}{5}.\frac{5}{9}=\frac{7}{9}\)

a) x+ \(\frac{4}{5}\)= \(\frac{4}{5}\)+ ( \(\frac{3}{7}\)+ \(\frac{3}{5}\))

    x + \(\frac{4}{5}\)=  \(\frac{4}{5}\)+ \(\frac{36}{35}\)

    => x = \(\frac{36}{35}\)

Vậy : x = \(\frac{36}{35}\)

b) \(\frac{4}{9}\)+\(\frac{8}{9}\)+ \(\frac{12}{9}\)+ ... + \(\frac{56}{9}\)

    = \(\frac{4+8+12+...+56}{9}\)

    Ta có : 4+8+12 + ... +56

     Số các số hạng của dẫy số trên là : ( 56 -4) + 4 +1 = 14 ( số hạng )

      => Tổng trên = ( 4+56) x 14 : 2 = 420

      => \(\frac{4}{9}\)+ \(\frac{8}{9}\)+ ... + \(\frac{56}{9}\)= \(\frac{420}{9}\)= \(\frac{140}{3}\)

a)x=3/7+3/5=3x(1/7+1/5)=36/35

b)=(4+8+...+56)/9=(56+4)x14/9=280/3