x/-30+1,75=-5/9:4/3

=>x/-30+7/4=-5/12

=>x/-30=-13/6

=>x.6=-30.-13

=>x.6=390

=>x=65

vậy x=65.

bạn viết rõ ra phân số ra nha!

41436 nha

      3 x 4 x 45 + 12 x 25 + 12 x 3

= 12 x 45 + 12 x 25 + 12 x 3

= 12 x (45 + 25 + 3)

= 12 x 73

= 876

Bạn chắc chứ

\(\left(x-5\right)-\left(2x+7\right)=-8\\ x-5-2x-7+8=0\\ -x=4\\ x=-4\)

Tách nhỏ câu hỏi ra bạn

1, x - 45 = 48 - 68

    x - 45 = - 20

    x        = (- 20) + 45

    x        = 25

Vậy x = 25

2, 35 + 5. (6 - x) = ( - 12) - ( - 112)

    35 + 5. (6 - x) = 100

          40. (6 - x) = 100

                 6 - x  = 100 : 40

                 6 - x  = 25

                      x  = 6 - 25

                      x  = - 19

Vậy x = - 19

3, 157 - (x - 124) =  - 483

              x - 124   = 157 - (- 483)

              x - 124  = 640

              x           = 640 + 124

              x           = 764

Vậy x = 764

Câu 5: B

Câu 6: C

Câu 7: A

Câu 8: A

Vì \(\pi< \alpha< \dfrac{3\pi}{2}\) \(\Rightarrow\dfrac{\pi}{2}< \dfrac{\alpha}{2}< \dfrac{3\pi}{4}\)

\(\Rightarrow sin\dfrac{\alpha}{2}>0;cos\dfrac{\alpha}{2}< 0\)

\(\pi< \alpha< \dfrac{3\pi}{2}\Rightarrow cos\alpha< 0\)

\(\Rightarrow cos\alpha=-\sqrt{1-sin^2\alpha}=-\dfrac{3}{5}\)

Có \(sin^2\dfrac{\alpha}{2}=\dfrac{1-cosa}{2}=\dfrac{4}{5}\Rightarrow sin\dfrac{\alpha}{2}=\sqrt{\dfrac{4}{5}}=\dfrac{2\sqrt{5}}{5}\)

\(cos^2\dfrac{\alpha}{2}=\dfrac{1+cosa}{2}=\dfrac{1}{5}\Rightarrow cos\dfrac{\alpha}{2}=-\sqrt{\dfrac{1}{5}}=-\dfrac{\sqrt{5}}{5}\)

\(tan\dfrac{\alpha}{2}=\dfrac{sin\dfrac{\alpha}{2}}{cos\dfrac{\alpha}{2}}=-2\)

\(cot\dfrac{\alpha}{2}=-\dfrac{1}{2}\)

Bài 3: 

a) Ta có: \(A=\left(\dfrac{\sqrt{x}}{\sqrt{x}+3}+\dfrac{3}{\sqrt{x}-3}\right)\cdot\dfrac{\sqrt{x}+3}{x+9}\)

\(=\dfrac{x-3\sqrt{x}+3\sqrt{x}+9}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\cdot\dfrac{\sqrt{x}+3}{x+9}\)

\(=\dfrac{1}{\sqrt{x}-3}\)

b) Ta có: \(B=21\left(\sqrt{2+\sqrt{3}}+\sqrt{3-\sqrt{5}}\right)^2-6\left(\sqrt{2-\sqrt{3}}+\sqrt{3+\sqrt{5}}\right)^2-15\sqrt{15}\)

\(=21\left(5+\sqrt{3}-\sqrt{5}+2\sqrt{\left(2+\sqrt{3}\right)\left(3-\sqrt{5}\right)}\right)-6\left(5-\sqrt{3}+\sqrt{5}+2\sqrt{\left(2-\sqrt{3}\right)\left(3+\sqrt{5}\right)}\right)-15\sqrt{15}\)

\(=21\left(4+\sqrt{15}\right)-6\left(4+\sqrt{15}\right)-15\sqrt{15}\)

\(=84+21\sqrt{15}-24-6\sqrt{15}-15\sqrt{15}\)

=60

$\sin18=\cos72=2 \cos^{2}36-1=2(1- \sin^{2}18)^{2}-1
\Leftrightarrow 8 \sin^{4}18 -8 \sin^{2}18- \sin18+1=0
\Leftrightarrow ( \sin18-1)[8 \sin^{3}18+8 \sin^{2}18-1]=0 $

ht