suy ra  x + 1+ x+5=32     or            x+1+x+5=-32

 "      " 2x+6=32                             2x+6=-32

           2x= 32-6=26                       2x = -32-6=-38

"      "  x =26/2=13                           x = -38/2=-19

vay x =-19 or x =13

3/2+5/4+9/8/+17/16+33/32-6+x-1/x+1=31/32-2/2015

=(1+1/2)+(1+1/4)+(1+1/8)+(1+1/16)+(1+1/32-6+x-1/x+1=31/32-2/2015

=(1/2+1/4+1/8+1/16+1/32)+(1+1+1+1+1)-6+x-1/x+1=31/32-2/2015

=31/32+5-6+x-1/x+1=31/32-2/2015

=5-6+x-1/x+1=31/32-2/2015-31/32

=-1+x-1/x+1=-2/2015

=x-1/x+1=-2/2015- -1

=x-1/x+1=2013/2015

=>x=2014

\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\Leftrightarrow\frac{2^x}{2}+5.\frac{2^x}{2^2}=\frac{7}{32}\Leftrightarrow2^x\left(\frac{1}{2}+\frac{5}{4}\right)=\frac{7}{32}\Leftrightarrow2^x=\frac{1}{8}=2^{-3}\)

<=> x=-3

                                                 giải

32/9-x-5/12= 1/3 + 1/3 +1/3

32/9-x-5/12 =1 

32/9-x=1+ 5/12

32/9-x=17/12

x=32/9-17/12

x=77/36

thế đó bạn

Đúng không bạn ơi

 tìm x : -2/3x -3/2x =5/12

17/12 hay hon so 1/5/12

𝑥=77/36

#HT#

a/|x|-2,5=27,5

=>|x|=27,5+2,5=30

=>x=30 hoặc x=-30

b/\(\dfrac{3}{4}+\dfrac{2}{5}.x=\dfrac{29}{60}\)

=>\(\dfrac{2}{5}.x\)=\(\dfrac{29}{60}-\dfrac{3}{4}\)=\(\dfrac{-4}{15}\)

=>x=\(\dfrac{-4}{15}:\dfrac{2}{5}\)=\(\dfrac{-2}{3}\)

c/(x-1)\(^5\)=-32

=>x-1=-2 vì (-2)\(^5\)=-32

=>x=-2+1=-1

d/\(\dfrac{4}{5}.x+0,5=4.5\)

=>\(\dfrac{4}{5}.x+0,5=20\)

=>\(\dfrac{4}{5}.x=20-0,5=19,5\)

=>\(x=19,5:\dfrac{4}{5}\)=\(\dfrac{195}{8}\)

5(x - 1)  = 2x - 32

5x - 5 = 2x - 32

5x - 2x = -32 + 5

3x = -27

x = (-27) : 3

x = -9

123 nha

5( x - 1 ) = 2x - 32

5x - 5 = 2x - 32

5x - 2x = - 32 + 5

5x - 2x = - 27

3x = - 27

 x = ( - 27 ) : 3

 x = - 9

(x-1)^5 = -32

(-2)^5=-32

=>x-1=-2

=>x=-1

**** cho mik nhé

(x-1)^5=-2^5

(x-1)=-2

x=-2+1

x=-1

X = 3
mới học mãu giáo hả